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The drain cleaner, Drainex contains small bits of aluminium which react with caustic soda to produce hydrogen. What volume of hydrogen at \(27^{\circ} \mathrm{C}\) and \(0.831\) bar will be released when \(0.15 \mathrm{~g}\) of aluminium reacts? \((\mathrm{Al}=27)\) (a) \(250 \mathrm{ml}\) (b) \(150 \mathrm{~m} 1\) (c) \(500 \mathrm{ml}\) (d) \(125 \mathrm{ml}\)

Short Answer

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250 ml

Step by step solution

01

Write the balanced chemical equation

To solve this problem, you first need to write the balanced chemical equation for the reaction between aluminium and caustic soda (sodium hydroxide) to produce hydrogen. The reaction is: \[2\text{Al} + 2\text{NaOH} + 6\text{H}_2\text{O} \rightarrow 2\text{NaAl(OH)}_4 + 3\text{H}_2.\]
02

Calculate moles of aluminium

Use the molar mass of aluminium to convert grams into moles: \[\text{Moles of Al} = \frac{\text{mass of Al}}{\text{molar mass of Al}} = \frac{0.15\text{ g}}{27\text{ g/mol}} \approx 0.00556\text{ mol}.\]
03

Deduce moles of hydrogen gas produced

From the balanced equation, 2 moles of Al produce 3 moles of H2. So, 0.00556 moles of Al will produce: \[\text{Moles of H}_2 = \frac{3}{2} \times 0.00556\text{ mol} \approx 0.00834\text{ mol}.\]
04

Use the ideal gas law to find the volume of hydrogen gas

Using the ideal gas equation, PV = nRT, we can solve for the volume, V. Convert the temperature to Kelvin: T = 27 + 273.15 = 300.15 K. The pressure is given in bar and needs to be converted to Pa: P = 0.831 bar = 83100 Pa. The ideal gas constant R for the units of moles, Kelvin, and Pascals is 8.314 J/(mol K). Now, calculate the volume: \[V = \frac{nRT}{P} = \frac{0.00834 \text{ mol} \times 8.314 \text{ J/(mol K)} \times 300.15 \text{ K}}{83100 \text{ Pa}} \approx 0.025\text{ m}^3.\]
05

Convert the volume to milliliters

Since \(1 \text{ m}^3 = 10^6 \text{ ml}\), convert the volume from cubic meters to milliliters: \[V_{\text{H}_2} = 0.025 \text{ m}^3 \times 10^6 \text{ ml/m}^3 = 25000 \text{ ml} = 250 \text{ ml}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry, the heart of chemical reactions, is the calculation involving the quantities of reactants and products in a chemical process. It leans heavily on the law of conservation of mass that states matter is neither created nor destroyed in a chemical reaction. Therefore, the amount of reactants consumed will dictate the volume or mass of the products formed.

Understanding stoichiometry requires a solid grasp of chemical equations, which represent how reactants transform into products. A balanced chemical equation follows the stoichiometric coefficients: the numbers leading each molecule that ensure the same number of each type of atom appears on both sides of the reaction.

One usually calculates the moles of a reactant, like aluminium in our drain cleaner example, which interacts with other chemicals - in this case, caustic soda, to form hydrogen. Using a balanced chemical equation, one can decipher the proportional relationships and thus predict the moles of hydrogen produced.
Ideal Gas Law
The ideal gas law is a crucial equation for understanding how gases behave under different conditions of pressure (P), volume (V), temperature (T), and number of moles (n). The equation is written as PV = nRT, where R is the gas constant. This law combines several simpler gas laws and provides a powerful tool for predicting the behavior of gases.

The application of the ideal gas law extends to numerous scientific exercises, including the prediction of a gas's volume after a chemical reaction, as we've seen with hydrogen gas production. To apply the ideal gas law, one must consider the proper units (P in Pascals, V in cubic meters, n in moles, R in J/(mol·K), and T in Kelvin) and make conversions when necessary, ensuring that the conditions specified in the exercise are met.

When you know the amount of gas in moles, the temperature, and pressure, you can easily compute the volume. Always remember to adjust the temperature to Kelvin and pressure to the suitable units if they are not initially provided in the standard units.
Molar Mass
Molar mass is the weight of one mole of a given substance and is typically expressed in grams per mole (g/mol). It is fundamental for converting between grams and moles, a common task in chemistry known as molar conversions. The molar mass of each element is found on the periodic table and is equal to the atomic weight of the element.

For compounds, the molar mass is the sum of the atomic weights of all atoms in the molecule. For example, as seen in the drain cleaner situation, aluminium (Al) has a molar mass of 27 g/mol. Having the molar mass allows chemists to count molecules by weighing them, enabling stoichiometric calculations that convey how many moles of each reactant are involved and what volume of gaseous product can be expected after the reaction proceeds.

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Most popular questions from this chapter

If for two gases of molecular weights \(M_{\mathrm{A}}\) and \(M_{\mathrm{B}}\) at temperature \(T_{\mathrm{A}}\) and \(T_{\mathrm{B}}\), \(T_{\mathrm{A}} M_{\mathrm{B}}=T_{\mathrm{B}} M_{\mathrm{A}}\), then which property has the same magnitude for both the gases? (a) density (b) pressure (c) KE per mole (d) RMS speed

According to Avogadro's hypothesis, equal volumes of all gases under the same conditions of temperature and pressure will contain (a) the same number of molecules (b) different number of molecules (c) the same number of molecules only if their molecular masses are equal (d) the same number of molecules if their densities are equal

Suppose the inhaled air has partial pressure of water vapour of \(5 \mathrm{~mm} \mathrm{Hg}\) and exhaled air is nearly saturated at body temperature \((310 \mathrm{~K})\) with water vapour. The mass of water lost per day by a person assuming that the normal man breaths 10,000 litre per day. Saturated vapour pressure of water at \(310 \mathrm{~K}\) is \(45 \mathrm{~mm} \mathrm{Hg}\) (a) \(20.68 \mathrm{~g}\) (b) \(372.23 \mathrm{~g}\) (c) \(418.76 \mathrm{~g}\) (d) \(46.53 \mathrm{~g}\)

In a glass tube of uniform cross section, a mixture of \(\mathrm{HCl}\) and \(\mathrm{He}\) gases are sent from one end and a mixture of \(\mathrm{NH}_{3}\) and Ar gases are sent from the another end, at the same time. The white fumes of \(\mathrm{NH}_{4} \mathrm{Cl}\) will appear first (a) at the middle of the tube (b) closer to \(\mathrm{NH}_{3}\) end (c) closer to \(\mathrm{HCl}\) end (d) at the \(\mathrm{NH}_{3}\) end

If air is pumped slowly but continuously into a metallic cylinder of strong wall, what would happen to the air inside the cylinder? (a) temperature of air would increase (b) pressure of air would increase (c) pressure of air would decrease (d) temperature and pressure of air would increase

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