Chapter 3: Problem 28
An amount of 1 mole of a gas is changed from its initial state \((20 \mathrm{~L}, 2 \mathrm{~atm})\) to final state (4L, \(10 \mathrm{~atm}\) ), respectively. If the change can be represented by a straight line in \(P-V\) curve, the maximum temperature achieved by the gas in the process is \((R=0.08 \mathrm{~L}-\mathrm{atm} / \mathrm{K}-\mathrm{mol})\) (a) \(900^{\circ} \mathrm{C}\) (b) \(900 \mathrm{~K}\) (c) \(627 \mathrm{~K}\) (d) \(1173^{\circ} \mathrm{C}\)
Short Answer
Step by step solution
State the Ideal Gas Law
Determine the slope of the P-V curve
Calculate the slope
Apply the Ideal Gas Law at the initial state
Calculate the initial temperature
Determine the expression for temperature at any state
Calculate the temperature for the final state
Determine the maximum temperature
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Ideal Gas Law (PV=nRT)
The problem discussed requires applying this law to find the maximum temperature achieved by a gas. Remember that for any calculation using this formula, consistency in units is crucial. For example, pressure should typically be in atmospheres (atm), volume in liters (L), temperature in Kelvin (K), and the ideal gas constant should correspond to those units, which is \(0.08 \text{L-atm/K-mol}\) in this case.
The Ideal Gas Constant (R)
The correct value of \(R\) must be used for calculations to be valid. This is why we used \(0.08 \text{L-atm/K-mol}\) according to the problem's given units.
Slope of the P-V Curve
The slope of the line is calculated by \(\text{slope} = (\Delta P/\Delta V)\), which denotes the change in pressure to the change in volume. The exercise provided shows a decrease in volume with an increase in pressure, resulting in a negative slope (\( -0.5 \text{atm/L}\)), indicative of a compression process.
Temperature Calculation in Gases
In the given problem, temperature calculations are performed at the initial and final states of the gas's transformation using the Ideal Gas Law. By rearranging the equation, we get \(T = \frac{PV}{nR}\). Be mindful that when dealing with temperatures in gas laws, it's essential to ensure they are in the proper units (Kelvin) to avoid discrepancies in calculations. The maximum temperature in the given problem was calculated to be 5000 K. Remember that temperature directly reflects the average kinetic energy of the gas molecules.