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If \(8 \mathrm{~g}\) of a radioactive isotope has a halflife of \(10 \mathrm{~h}\). The half-life of \(2 \mathrm{~g}\) of the same substance is (a) \(2.5 \mathrm{~h}\) (b) \(5 \mathrm{~h}\) (c) \(10 \mathrm{~h}\) (d) \(40 \mathrm{~h}\)

Short Answer

Expert verified
The half-life remains constant regardless of the amount of substance, so the answer is (c) 10 hours.

Step by step solution

01

Understand the concept of half-life

The half-life of a radioactive substance is the time it takes for half of the substance to decay. It is a constant value for a given substance, which means it is independent of the amount of the substance present.
02

Apply the concept to the given problem

Since the half-life is a constant value for a radioactive isotope, the amount of the substance present does not affect its half-life. Therefore, whether we have 8 grams or 2 grams of the substance, the half-life remains the same.
03

Choose the correct answer

Given that the half-life of the isotope (8 g) is 10 hours, the half-life for 2g of the same isotope is also 10 hours. So the correct answer is (c) 10 hours.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactivity
Imagine a world where some elements have an unstable nucleus that's always looking to find balance. That's the reality of radioactivity. At its core, radioactivity is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can happen in several ways, such as through the release of alpha particles, beta particles, or gamma rays.

Elements that exhibit this behavior are known as radioactive isotopes, and they are found both in nature and can be created artificially in laboratories. A radioactive isotope, also called a radioisotope, undergoes a spontaneous transformation into a more stable form, a process we refer to as radioactive decay.

Understanding radioactivity is important not just in nuclear chemistry but also in a multitude of fields like medicine for diagnostic imaging, archaeology for carbon dating, and even in space exploration for powering spacecraft. It's fascinating, yet it must be approached with caution due to the potential risks associated with radiation exposure.
Half-Life Calculation
When we talk about the half-life of a radioactive substance, we're referring to the time it takes for one half of any sample of the substance to decay. It's like a stopwatch for radioactivity that, once you start it, tells you how long you have to wait until only half of your original sample remains. Calculating the half-life of a substance is crucial in various applications, from nuclear medicine to environmental science.

Decay Formula

To put it into a mathematical form, the amount of substance left after a certain number of half-lives can be determined by the formula: \( N = N_0 \times (\frac{1}{2})^{\frac{t}{T}} \), where \(N\) is the remaining quantity of the substance, \(N_0\) is the original quantity, \(t\) is the time elapsed, and \(T\) is the half-life of the substance.

It's critical to unravel that half-life is independent of the initial amount of substance; it remains constant regardless of how much substance you start with. This means that whether you have a mountain or a molehill of a radioactive isotope, the time it will take for half of it to decay is the same.
Nuclear Chemistry
Nuclear chemistry is like the rulebook for the nucleus of an atom. It's a field where chemists look at the heart of the atom and see how it interacts, transforms, and sometimes even splits apart or combines with another to release staggering amounts of energy. This branch of chemistry focuses on reactions that involve changes in nuclear composition as well as the study of the nature and properties of the atomic nucleus.

Nuclear chemistry has given us power production through nuclear reactors, medical advancements through radiation therapy, and even the ability to understand the history of ancient objects through radiocarbon dating. However, it is also the science behind nuclear weapons, making it a field that carries significant weight and responsibility.

One major aspect of nuclear chemistry is understanding and controlling the rate of nuclear reactions, which is where the knowledge of radioactive half-life becomes incredibly useful. By studying half-lives, nuclear chemists can predict the behavior of radioactive materials over time, which is essential for safety and practicality in all applications involving radioactivity.

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Most popular questions from this chapter

In nature a decay chain starts with \(\mathrm{Th}^{232}\) and finally terminates at \(\mathrm{Pb}^{208}\). A thorium ore sample was found to contain \(6.72 \times 10^{-5} \mathrm{ml}\) of \(\mathrm{He}\) (at \(273 \mathrm{~K}\) and \(\left.1 \mathrm{~atm}\right)\) and \(4.64 \times 10^{-7} \mathrm{~g}\) of \(\mathrm{Th}^{232}\). Find the age of the sample assuming that source of He to be only due to decay of \(\mathrm{Th}^{232}\). Also assume complete retention of He within the ore. \(\left(t_{1 / 2}\right.\) of \(\mathrm{Th}^{232}=1.38 \times 10^{10}\) years, \(\log 2=0.3)\) (a) \(2.3 \times 10^{10}\) years (b) \(2.3 \times 10^{9}\) years (c) \(4.6 \times 10^{9}\) years (d) \(9.2 \times 10^{9}\) years

An ore of uranium is found to contain \({ }_{92}^{238} \mathrm{U}\) and \({ }_{82}^{206} \mathrm{~Pb}\) in the mass ratio of \(1: 0.1 .\) The half-life period of \({ }_{92}^{238} \mathrm{U}\) is \(4.5 \times 10^{9}\) years. Age of the ore is \((\log 2=0.3, \log\) \(\left.\frac{114.9}{103}=0.048\right)\) (a) \(7.2 \times 10^{8}\) years (b) \(7.2 \times 10^{7}\) years (c) \(7.2 \times 10^{9}\) years (d) \(2.16 \times 10^{9}\) years

The largest stable nucleus is (a) \(\mathrm{U}^{238}\) (b) \(\mathrm{B}_{1}^{209}\) (c) \(\mathrm{U}^{235}\) (d) \(\mathrm{Pb}^{206}\)

Consider the following process of decay, \({ }_{92} \mathrm{U}^{234} \rightarrow{ }_{90} \mathrm{Th}^{230}+{ }_{2} \mathrm{He}^{4} ; t_{1 / 2}=2,50,000\) years \({ }_{90} \mathrm{Th}^{230} \rightarrow{ }_{88} \mathrm{Ra}^{226}+{ }_{2} \mathrm{He}^{4} ; t_{1 / 2}=80,000\) years \({ }_{88} \mathrm{Ra}^{226} \rightarrow{ }_{86} \mathrm{Rn}^{222}+{ }_{2} \mathrm{He}^{4} ; t_{1 / 2}=1600\) years After the above process has occurred for a long time, a state is reached where for every two thorium atoms formed from \({ }_{92} \mathrm{U}^{234}\), one decomposes to form \({ }_{88} \mathrm{Ra}^{226}\) and for every two \({ }_{88} \mathrm{Ra}^{226}\) formed, one decomposes. The ratio of \({ }_{90} \mathrm{Th}^{230}\) to \({ }_{88} \mathrm{Ra}^{226}\) will be (a) \(250000 / 80000\) (b) \(80000 / 1600\) (c) \(250000 / 1600\) (d) \(251600 / 8\)

\(\alpha\) -particle is considered identical to He-nucleus because (a) He-nucleus is present in the nuclei of all \(\alpha\) -emitters. (b) He-nucleus has two protons and two neutrons. (c) any sealed vessel containing some \(\alpha\) -emitter is found to contain He gas after some time. (d) He-nucleus is the most stable nucleus.

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