Chapter 13: Problem 13
A ruby laser produces radiations of wavelength \(662.6 \mathrm{~nm}\) in pulses whose duration are \(1.0 \times 10^{-9} \mathrm{~s}\). If the laser produces \(0.36 \mathrm{~J}\) of energy per pulse, how many photons are produced in each pulse? (a) \(1.2 \times 10^{9}\) (b) \(1.2 \times 10^{27}\) (c) \(1.2 \times 10^{18}\) (d) \(1.2 \times 10^{15}\)
Short Answer
Step by step solution
Calculate the energy of a single photon
Convert the wavelength from nanometers to meters
Calculate the energy of one photon
Calculate the number of photons per pulse
Select the correct answer
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Planck's equation
When considering the energy of light emitted by a laser, as with the ruby laser in our example, Planck's equation becomes pivotal to calculate the energy of each individual photon. It establishes an essential relationship used in a multitude of applications, such as determining the power of laser pulses in modern technology and communications.
Wavelength to frequency conversion
To find a photon's frequency (\( u \)), just rearrange the equation to \( u = \frac{c}{\lambda} \). In our ruby laser problem, this conversion allows us to relate the known wavelength of the emitted light to the photon frequency needed for Planck's equation. This step is fundamental because Planck's equation takes frequency into account, not wavelength. Thus, understanding this conversion is not just theoretical – it is practically applied when calculating photon energies.
Speed of light
Energy per pulse
For example, with our ruby laser emitting 0.36 J energy per pulse, we can calculate how many packets of light – photons – this energy corresponds to. By doing so, we can understand the laser's strength and its effects at the photonic level. This kind of calculation is not only essential for theoretical physics but also for practical applications in industry and technology where precise energy measurements are paramount.