Iodide ion is oxidized to hypoiodite ion, \(\mathrm{IO}^{-}\), by hypochlorite
ion, \(\mathrm{ClO}^{-}\), in basic solution as:
$$
\begin{array}{ccccc}
& \mathbf{I}^{-} & \mathbf{C l O}^{-} & \mathbf{O H}^{-} & \left(\mathrm{mol}
\mathbf{L}^{-1} \mathbf{s}^{-1}\right) \\
\hline 1 & 0.010 & 0.020 & 0.010 & 12.2 \times 10^{-2} \\
2 & 0.020 & 0.010 & 0.010 & 12.2 \times 10^{-2} \\
3 & 0.010 & 0.010 & 0.010 & 6.1 \times 10^{-2} \\
4 & 0.010 & 0.010 & 0.020 & 3.0 \times 10^{-2} \\
\hline
\end{array}
$$
The correct rate law for the reaction is
(a)
\(r=K\left[\mathrm{I}^{-}\right]\left[\mathrm{ClO}^{-}\right]\left[\mathrm{OH}^{-}\right]^{0}\)
(b)
\(r=K\left[\mathrm{I}^{-}\right]^{2}\left[\mathrm{ClO}^{-}\right]^{2}\left[\mathrm{OH}^{-}\right]^{0}\)
(c)
\(r=K\left[\mathrm{I}^{-}\right]\left[\mathrm{ClO}^{-}\right]\left[\mathrm{OH}^{-}\right]\)
(d)
\(r=K\left[\mathrm{I}^{-}\right]\left[\mathrm{ClO}^{-}\right]\left[\mathrm{OH}^{-}\right]^{-1}\)