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At a certain temperature, the reaction between \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) to form \(\mathrm{NO}_{2}\) is fast, while that between \(\mathrm{CO}\) and \(\mathrm{O}_{2}\) is slow. It may be concluded that (a) \(\mathrm{NO}\) is more reactive than \(\mathrm{CO}\). (b) CO is smaller in size than NO. (c) activation energy for the reaction: \(2 \mathrm{NO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}\) is less. (d) activation energy for the reaction: \(2 \mathrm{NO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}\) is high.

Short Answer

Expert verified
The correct conclusions are: (a) \(\mathrm{NO}\) is more reactive than \(\mathrm{CO}\) and (c) activation energy for the reaction \(2 \mathrm{NO} + \mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}\) is less.

Step by step solution

01

Understanding Chemical Reactivity

The reactivity of a chemical species in a reaction is often reflected by the speed or rate of the reaction. A faster reaction typically indicates a more reactive species or lower activation energy.
02

Evaluating the Given Information

From the given information, we know that the reaction between \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) to form \(\mathrm{NO}_{2}\) is fast, which suggests higher reactivity or lower activation energy for this reaction compared to the reaction between \(\mathrm{CO}\) and \(\mathrm{O}_{2}\), which is slow.
03

Analyzing Choice (a)

Considering the rate of reaction is a valid indicator of reactivity, able to say that \(\mathrm{NO}\) is more reactive than \(\mathrm{CO}\) because the reaction involving \(\mathrm{NO}\) is faster.
04

Analyzing Choice (b)

The size of the molecules \(\mathrm{CO}\) and \(\mathrm{NO}\) is not provided, and molecule size is not directly related to speed of reaction. Therefore, this choice cannot be concluded based on the given information.
05

Analyzing Choice (c)

A faster reaction rate usually suggests that the activation energy required for the reaction to proceed is lower. Therefore, it could be considered that the activation energy for the reaction \(2 \mathrm{NO} + \mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}\) is less.
06

Analyzing Choice (d)

Given that the reaction between \(\mathrm{NO}\) and \(\mathrm{O}_{2}\) is fast, it would be incorrect to conclude that the activation energy for the reaction is high. A high activation energy would result in a slower reaction rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Chemical Reactions
When we talk about chemical reactions, one of the first things that might come to mind is how quickly they occur. This speed, or rate of chemical reactions, is a measure of the change in concentration of reactants or products over time. Factors like temperature, pressure, concentration, and the presence of catalysts can influence these rates.

Picture a busy kitchen during a morning rush; the quick preparation of dishes can be akin to a fast chemical reaction, while a slower pace when the kitchen is less bustling is like a slower reaction. In our exercise scenario, the rapid formation of 2 from and 2 gives us a hint that we're dealing with a 'busy kitchen' scenario, where the reactivity of is higher than in the presence of 2.
Activation Energy in Reactions
Imagine you're at the bottom of a hill and your favorite ice cream stand is on the other side. To enjoy the treat, you must first climb up and over the hill. In chemical terms, you just encountered what's known as activation energy, the minimum energy needed by reacting particles to form a product.

This energetic 'hill' must be overcome for reactants to transform into products. Catalysts are like a tunnel through our metaphorical hill, reducing the energy required to reach the other side, thus accelerating the reaction. Reflecting on the original exercise, we can see the rapid reaction of and 2 to produce 2 likely has a smaller 'hill' to climb, indicating a lower activation energy compared to the slow reaction involving and 2.
Comparative Reactivity of Chemical Species
Chemical species have varying reactivity, much like students in a class who learn at different paces. Reactivity is influenced by several factors, including atomic or molecular size, electron configurations, and the energy difference between reactants and products.

In the context of the exercise, we observe that nitrogen monoxide () reacts more readily with oxygen (2) than carbon monoxide () does. It's not a direct measure of molecular size (which isn't a focus in this scenario) but rather how willing and able a molecule is to engage in a chemical reaction. Just as some students are quicker to raise their hands to answer questions, is quicker to react than , showcasing its higher reactivity.

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Most popular questions from this chapter

The reaction: \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{NO}_{2}+\mathrm{OH}^{-}\) \(\rightarrow \mathrm{H}_{3} \mathrm{C}-\mathrm{CH}^{-}-\mathrm{NO}_{2}+\mathrm{H}_{2} \mathrm{O}\) obeys the rate law for pseudo first-order kinetics in the presence of a large excess of hydroxide ion. If \(1 \%\) of nitro ethane undergoes reaction in half a minute when the reactant concentration is \(0.002 \mathrm{M}\), what is the pseudo first-order rate constant? (a) \(2 \times 10^{-2} \mathrm{~min}^{-1}\) (b) \(6 \times 10^{-3} \mathrm{~min}^{-1}\) (c) \(4 \times 10^{-2} \mathrm{~min}^{-1}\) (d) \(1 \times 10^{-2} \mathrm{~min}^{-1}\)

For two parallel first-order reactions, what is the overall activation energy of reaction? The yields of \(\mathrm{B}\) and \(\mathrm{C}\) in products are \(40 \%\) and \(60 \%\), respectively. \(\mathrm{A} \stackrel{\mathrm{Ea}=20 \mathrm{kcal} / \mathrm{mol}}{\longrightarrow} \mathrm{B} \quad \mathrm{A} \stackrel{\mathrm{Ea}=40 \mathrm{kcal} / \mathrm{mol}}{\longrightarrow} \mathrm{C}\) (a) \(60 \mathrm{kcal} / \mathrm{mol}\) (b) \(32 \mathrm{kcal} / \mathrm{mol}\) (c) \(28 \mathrm{kcal} / \mathrm{mol}\) (d) \(20 \mathrm{kcal} / \mathrm{mol}\)

For a bimolecular gaseous reaction of type: \(2 \mathrm{~A} \rightarrow\) Products, the average speed of reactant molecules is \(2 \times 10^{4} \mathrm{~cm} / \mathrm{s}\), the molecular diameter is \(4 \AA\) and the number of reactant molecules per \(\mathrm{cm}^{3}\) is \(2 \times 10^{19}\). The maximum rate of reaction should be (a) \(\left.4.72 \times 10^{7} \mathrm{~mol}\right]^{-1} \mathrm{~s}^{-1}\) (b) \(1.18 \times 10^{7} \mathrm{~mol} 1^{-1} \mathrm{~s}^{-1}\) (c) \(9.44 \times 10^{7} \mathrm{~mol} 1^{-1} \mathrm{~s}^{-1}\) (d) \(2.36 \times 10^{7} \mathrm{~mol} 1^{-1} \mathrm{~s}^{-1}\)

For the reaction: \(\mathrm{A}_{2}(\mathrm{~g}) \rightarrow \mathrm{B}(\mathrm{g})+\frac{1}{2} \mathrm{C}(\mathrm{g})\) pressure of the system increases from 100 to \(120 \mathrm{~mm}\) in 5 min. The average rate of disappearance of \(\mathrm{A}_{2}\) (in \(\mathrm{mm} / \mathrm{min}\) ) in this time interval is (a) 4 (b) 8 (c) 2 (d) 16

If \(t_{1 / 2}\) of a second-order reaction is \(1.0 \mathrm{~h}\). After what time, the amount will be \(25 \%\) of the initial amount? (a) \(1.5 \mathrm{~h}\) (b) \(2 \mathrm{~h}\) (c) \(2.5 \mathrm{~h}\) (d) \(3 \mathrm{~h}\)

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