Chapter 1: Problem 40
Fluorine reacts with uranium hexafluoride, \(\mathrm{UF}_{6}\), as represented by this equation: \(\mathrm{U}(\mathrm{s})+3 \mathrm{~F}_{2}(\mathrm{~g}) \rightarrow \mathrm{UF}_{6}(\mathrm{~g})\) How many fluorine molecules are required to produce \(2.0 \mathrm{mg}\) of uranium hexafluoride, \(\mathrm{UF}_{6}\), from an excess of uranium? The molar mass of \(\mathrm{UF}_{6}\) is \(352.0 \mathrm{~g} \mathrm{~mol}^{-1} .\) (a) \(5.13 \times 10^{18}\) (b) \(1.026 \times 10^{19}\) (c) \(2.052 \times 10^{19}\) (d) \(1.026 \times 10^{20}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.