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In general, ketones are more reactive towards nucleophiles than esters because (a) The \(\alpha\) -protons of a ketone are more acidic than those of an ester. (b) The alkyl group in a ketone is an electron donating group due to hyperconjugation. (c) Alkoxy (RO-) groups are sterically larger than the related alkyl group. (d) Alkoxy (RO-) groups are stronger electron donating than alkyl groups via resonance.

Short Answer

Expert verified
Ketones are more reactive than esters due to steric hindrance from bulkier alkoxy groups and stronger resonance in esters.

Step by step solution

01

Identify Option (a)

Analyze the statement regarding the acidity of \(\alpha\)-protons. In ketones, the \(\alpha\)-protons are indeed more acidic compared to those in esters due to the electron-withdrawing nature of the carbonyl group, which stabilizes the conjugate base. However, this factor primarily affects stability and not nucleophilic reactivity, so it doesn't directly explain the higher reactivity of ketones.
02

Examine Option (b)

Consider the role of alkyl groups in ketones. Alkyl groups in ketones do provide some electron-donating effect through hyperconjugation, but their impact is not significant enough to directly influence nucleophilic reactivity compared to esters, where more electron-withdrawing effects occur.
03

Analyze Option (c)

Evaluate the steric effects of groups attached to the carbonyl carbon. The alkoxy (RO-) group in esters is indeed bulkier than an alkyl group, leading to steric hindrance which can reduce the approachability of nucleophiles towards the carbonyl carbon, making ketones more reactive.
04

Consider Option (d)

Investigate the electron donation through resonance. Alkoxy groups can donate electrons to the carbonyl carbon more effectively than alkyl groups due to resonance. This increased electron donation makes the carbonyl carbon less electrophilic, thereby reducing the reactivity towards nucleophiles in esters, as compared to ketones.
05

Conclusion

Based on the analyses of each option, option (c) and (d) together provide a more thorough explanation for why ketones are more reactive towards nucleophiles than esters: steric hindrance due to the bulkier alkoxy group and stronger electron donation via resonance in esters reduce nucleophilic attack.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Steric Hindrance in Esters
When we talk about steric hindrance in esters, we’re referring to the spatial arrangement that makes it difficult for other molecules, like nucleophiles, to approach the carbonyl carbon. In esters, the presence of an alkoxy group (RO-) instead of the simpler alkyl group creates additional bulkiness.
  • The alkoxy group is larger compared to the alkyl group.
  • This extra size prevents nucleophiles from getting close to the carbonyl carbon as easily.
  • This hindrance reduces the reactivity of esters compared to ketones where such bulk is absent.
So, while esters might seem similar to ketones, their bulkier structure due to the alkoxy group plays a crucial role in making them less reactive towards nucleophiles.
Electron Donation Effect
The electron donation effect is another fascinating aspect that differentiates ketones and esters. While both contain carbonyl groups, the surrounding groups contribute differently to their reactivity.
  • Esters have alkoxy groups, which are stronger electron donors compared to the alkyl groups in ketones.
  • The resonance stability of alkoxy groups allows them to donate electrons more effectively, making the carbonyl carbon less positive.
  • This reduces the attraction of nucleophiles to the carbonyl in esters, decreasing their reactivity.
Ketones, on the other hand, lack such strong resonance from electron donating groups, making their carbonyl carbon more accessible and electrophilic, thus increasing their reactivity.
Acidity of Alpha Protons in Ketones
The acidity of b1-protons in molecules like ketones and esters ties back to the structural and electronic features of these compounds.
  • The b1-protons in ketones are more acidic because the carbonyl group is a strong electron-withdrawing group.
  • This electron-withdrawing ability increases the stability of the carbanion formed after deprotonation.
  • However, while this acidity affects stability, it doesn't directly influence nucleophilic reactivity.
In contrast, esters have a weaker acidity of b1-protons due to the electron donation from alkoxy groups, which adds electron density rather than withdrawing it. This difference in acidity mainly impacts reactivity in other contexts rather than nucleophilic attack, which is more heavily influenced by the steric and electronic effects we've discussed.

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Most popular questions from this chapter

What will be the \(\mathrm{pH}\) of an acetate-acetic acid solution when the ratio of \(\left[\mathrm{CH}_{3} \mathrm{CO}_{2}\right] /$$\left[\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\right]\) is \(10 ?\) (A table of \(\mathrm{pK}\) data is given below.) $$ \begin{array}{|lc|} \hline \text { Some useful } & \mathrm{pK}_{\mathrm{a}} \text { values } \\ \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} & 4.76 \\ \mathrm{H}_{3} \mathrm{PO}_{4} & 2.2 \\ \mathrm{H}_{2} \mathrm{PO}^{\rho} & 7.2 \\ \mathrm{HPO}_{4}^{2} & 12.4 \\ \hline \end{array} $$ (a) \(5.76\) (b) \(4.76\) (c) \(3.76\) (d) \(1.76\)

\(\mathrm{CH}_{3}-\mathrm{CH}-\mathrm{COOH}\) can be converted into \(\mathrm{CH}_{3}-\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OH}\) by the use of (a) \(\mathrm{H}_{2} / \mathrm{Pd}\) (b) LiAIH \(_{4}\) (c) \(\mathrm{NaBH}_{4}\) (d) \(\mathrm{CH}_{3} \mathrm{MgBr}\)

Identify correct method of preparation of acetaldehyde from reaction of cyanide (a) \(\mathrm{Me}-\mathrm{C} \equiv \mathrm{N} \frac{\text { (i) DIBAL }}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}}\) (b) \(\mathrm{Me}-\mathrm{C} \equiv \mathrm{N} \frac{\text { (i) } \mathrm{SnCl}_{2}+\mathrm{HCl}}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}}\) (c) \(\mathrm{Me}-\mathrm{C} \equiv \mathrm{N} \frac{\text { (i) Conc. } \mathrm{H}_{2} \mathrm{SO}_{4}}{\text { (ii) dill. } \mathrm{NaOH}}\) (d) \(\mathrm{Me}-\mathrm{C} \equiv \mathrm{N} \frac{\text { (i) } \mathrm{Pd} / \mathrm{BaSo}_{4} / \mathrm{H}_{2}}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{\oplus}}\)

When methyl benzoate is nitrated with \(\mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4^{\prime}}\) the meta product is the major product. This is because (a) The \(-\mathrm{CO}_{2} \mathrm{CH}_{3}\) group is a meta director. (b) The \(-\mathrm{OCH}_{3}\) is a meta director. (c) The \(-\mathrm{NO}_{2}\) group is deactivating and a meta director. (d) Nitration usually occurs at the meta position.

If only one equivalent of \(\mathrm{NH}_{3}\) (one mole of \(\mathrm{NH}_{3}\) reacts with one mole of cyclohexyl chloride) was used, the reaction may not go to completion. Why? (a) \(\mathrm{NH}_{3}\) is not a strong nucleophile. Therefore, more \(\mathrm{NH}_{3}\) is needed. (b) \(\mathrm{Cl}\) is not a good leaving. Therefore, more \(\mathrm{NH}_{3}\) is needed. (c) Cyclohexyl group presents large steric hindrance. Therefore, more \(\mathrm{NH}_{3}\) is needed. (d) \(\mathrm{NH}_{3}\) will be protonated by \(\mathrm{HCl}\) as reaction proceeds. Therefore, the reaction will be incomplete.

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