Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which of the following gas molecule has the maxi mum specific heat at constant pressure? (a) helium (b) argon (c) nitrogen (d) oxygen

Short Answer

Expert verified
Nitrogen and oxygen have the maximum specific heat at constant pressure, being equal.

Step by step solution

01

Understand Specific Heat at Constant Pressure

The specific heat at constant pressure, denoted as \( C_p \), is the amount of heat required to raise the temperature of a unit mass of a gas by one degree Celsius at constant pressure. For ideal gases, \( C_p \) depends on the degree of freedom of the gas molecules.
02

Determine Degrees of Freedom

Monoatomic gases like helium and argon have 3 translational degrees of freedom. Diatomic gases like nitrogen and oxygen have 5 degrees of freedom (3 translational and 2 rotational) under standard conditions.
03

Use the Formula for \( C_p \)

The specific heat at constant pressure can be approximated using the formula \( C_p = \frac{f}{2} R + R \), where \( f \) is the degrees of freedom and \( R \) is the universal gas constant. For monoatomic gases, \( C_p = \frac{3}{2}R + R = \frac{5}{2} R \). For diatomic gases, \( C_p = \frac{5}{2}R + R = \frac{7}{2} R \).
04

Compare \( C_p \) Values

Comparing the calculated \( C_p \) values, we have \( \frac{5}{2} R \) for helium and argon, and \( \frac{7}{2} R \) for nitrogen and oxygen. Diatomic gases have a higher \( C_p \) than monoatomic gases.
05

Determine Which Gas Has Maximum \( C_p \)

Since both nitrogen and oxygen are diatomic gases with the same formula for \( C_p \), they both possess the maximum specific heat at constant pressure in this list. There is no difference between the \( C_p \) of nitrogen and oxygen under these conditions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of freedom refer to the number of independent ways a molecule in a gas can move or store energy. In simple terms, it represents the different types of motion or vibration a molecule can have. For monatomic gases, such as helium and argon, there are 3 translational degrees of freedom. This is because their motion can be described by their movements in the three-dimensional space: x, y, and z directions.

Diatomic gases, like nitrogen and oxygen, have 5 degrees of freedom under normal conditions. They have 3 translational degrees, similar to monatomic gases, but due to having two atoms bonded, they have 2 additional rotational degrees of freedom. These rotations occur around two perpendicular axes passing through their center of mass, giving them more ways to absorb heat.
Monoatomic Gases
Monoatomic gases consist of single atoms. Examples include noble gases like helium and argon. These types of gases are simpler in structure compared to diatomic or polyatomic gases. Because they are monoatomic, they only translate or move in the three-dimensional space without any internal rotation or vibration.

This simplicity limits their degrees of freedom to just the three translational motions. Monoatomic gases typically have lower heat capacities compared to more complex gases, primarily because they have fewer modes or ways to store energy when heat is added. This is important when understanding why their specific heat at constant pressure, denoted as \( C_p \), is lower than that of diatomic gases.
Diatomic Gases
Diatomic gases contain molecules composed of two atoms. Common examples are nitrogen \((N_2)\) and oxygen \((O_2)\). Due to their two-atom structure, they can move and rotate in space in more ways than monoatomic gases can.

In addition to the three translational degrees of freedom, they have two rotational degrees of freedom. This means that they can rotate about two axes perpendicular to the line joining the two atoms. Under certain conditions, they might also vibrate along the line joining the atoms, although this contribution often comes into effect at higher temperatures.
Heat Capacity
Heat capacity is a measure of the amount of heat energy required to change the temperature of a substance by a certain amount. Specific heat at constant pressure \( (C_p) \) is a type of heat capacity that tells us how much energy is needed to raise the temperature of a given mass of gas by one degree Celsius at constant pressure.

The greater the number of degrees of freedom, the higher the heat capacity. This is because the gas can distribute the absorbed heat into more modes of motion. For example, diatomic gases with 5 degrees of freedom have a higher \( C_p \) than monoatomic gases, which only have 3. Hence, diatomic gases require more energy to increase the temperature by the same amount, as compared to monoatomic gases.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry and physics that describes the relationship between the pressure \((P)\), volume \((V)\), temperature \((T)\), and amount \((n)\) of an ideal gas. It is often expressed as \( PV = nRT \), where \( R \) is the universal gas constant.

This law is an approximation that helps understand the behavior of gases under various conditions by assuming no interaction between gas particles and that they occupy no volume. Although real gases may deviate from these assumptions at high pressures and low temperatures, the Ideal Gas Law provides a useful approximation for explaining the basic properties and behavior of gases, and it often underlies how we think about concepts such as degrees of freedom and specific heat.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The work done by a system is 10 joule, when 40 joule heat is supplied to it. What is the increase in internal energy of system? (a) \(30 \mathrm{~J}\) (b) \(50 \mathrm{~J}\) (c) \(40 \mathrm{~J}\) (d) \(20 \mathrm{~J}\)

Calculate \(\Delta \mathrm{H}_{\mathrm{f}}^{\circ}\) for chloride ion from the following data: \(1 / 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I} / 2 \mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow \mathrm{HCl}(\mathrm{g})\) \(\Delta \mathrm{H}_{\mathrm{f}}^{\circ}=-92.4 \mathrm{~kJ}\) \(\mathrm{HCl}(\mathrm{g})+\mathrm{nH}_{2} \mathrm{O}(\mathrm{l}) \longrightarrow \mathrm{H}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) \(\Delta \mathrm{H}_{\mathrm{Hyd}}=-74.8 \mathrm{~kJ}\) \(\Delta \mathrm{H}_{\mathrm{f}}^{\mathrm{f}}\left[\mathrm{H}^{+}\right]=0.0 \mathrm{~kJ}\) (a) \(-189 \mathrm{~kJ}\) (b) \(-167 \mathrm{~kJ}\) (c) \(+167 \mathrm{~kJ}\) (d) \(-191 \mathrm{~kJ}\)

In the reaction: \(\mathrm{CO}(\mathrm{g})+1 / 2 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}_{2}(\mathrm{~g})\) the change in \(\Delta \mathrm{S}^{\circ}\) is (given \(\mathrm{S}^{\circ}\) for \(\mathrm{CO}, \mathrm{O}_{2}\) and \(\mathrm{CO}_{2}\) are \(197.6,205.3\) and \(213.6 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) respectively) (a) \(-78.6 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) (b) \(-50 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) (c) \(-86.5 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) (d) \(-30 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)

What is the value of \(\Delta \mathrm{E}\), when \(64 \mathrm{~g}\) oxygen is heated from \(0^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C}\) at constant volume? \(\left(\mathrm{C}_{\mathrm{v}}\right.\) on an average is \(5 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) ) (a) \(1500 \mathrm{~J}\) (b) \(1800 \mathrm{~J}\) (c) \(2000 \mathrm{~J}\) (d) \(2200 \mathrm{~J}\)

If \(0.75\) mole of an ideal gas is expanded isothermally at \(27^{\circ} \mathrm{C}\) from 15 litres to 25 litres, then work done by the gas during this process is \(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\) (a) \(-1054.2 \mathrm{~J}\) (b) \(-896.4 \mathrm{~J}\) (c) \(-954.2 \mathrm{~J}\) (d) \(-1254.3 \mathrm{~J}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free