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Classify each of the following processes as spontaneous or non-spontaneous. I. \(\mathrm{H}_{2} \mathrm{O}(1) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g}), \mathrm{T}=25^{\circ} \mathrm{C}\) vessel open to atomsphere with \(50 \%\) relative humidity. II. \(\mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l}), \mathrm{T}=25^{\circ} \mathrm{C}, \mathrm{P}=\mathrm{l} \mathrm{atm}\) (a) I and II are both non-spontaneous (b) I and II are both spontaneous (c) I is non-spontaneous and II is spontaneous (d) I is spontaneous and II is non-spontaneous

Short Answer

Expert verified
Both processes are spontaneous, so the answer is (b).

Step by step solution

01

Analyze Process I

Process I considers the evaporation of water from liquid to gas at 25°C with 50% relative humidity in an open vessel. In general, water tends to evaporate at any temperature due to the kinetic energy of the molecules. Even if relative humidity is at 50%, which means the air is not saturated, evaporation will still occur. Therefore, this process is spontaneous.
02

Analyze Process II

Process II examines the melting of ice to liquid water at 25°C and 1 atm pressure. Since 25°C is above the melting point of ice (0°C), this process occurs without any external intervention under these conditions. Thus, this process is also spontaneous.
03

Compare the Processes with Options

Given that both Process I and Process II are spontaneous under the described conditions, examine the provided options: (a) Both non-spontaneous — Incorrect (b) Both spontaneous — Correct (c) I is non-spontaneous and II is spontaneous — Incorrect (d) I is spontaneous and II is non-spontaneous — Incorrect
04

Select the Correct Answer

Since both processes are spontaneous, the correct answer is option (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is the study of energy, heat transfer, and the work done by these interactions. In chemistry, it helps us understand why certain reactions or processes occur spontaneously.
A spontaneous process is one that occurs without the need for constant external energy. It tends towards thermodynamic equilibrium, often releasing free energy.
There are several factors affecting spontaneity:
  • Temperature
  • Pressure
  • Entropy changes
  • Enthalpy changes
For example, in Process I from the exercise, the conversion of liquid water to vapor occurs because of entropy. The system favors disordered states, like that of gases, over organized states, like liquids.
Phase Transitions
Phase transitions refer to changes in the state of matter—solid, liquid, and gas. They occur because of temperature and pressure changes. When ice melts at 25°C (Process II in our exercise), a solid turns into a liquid. This happens because the energy absorbed by the ice overcomes the lattice structure of the solid state.
During phase transitions:
  • Temperature remains constant
  • Energy is either absorbed or released
  • There is a change in entropy
Thus, these changes often occur spontaneously when environmental conditions pass through critical points like the melting point or boiling point.
Kinetic Molecular Theory
The Kinetic Molecular Theory explains the behavior of gases based on the idea that they are made of many small particles. These particles are in constant random motion.
This theory can be applied to understand evaporation, like in Process I, where:
  • Molecules at the surface gain enough kinetic energy to break free into the vapor phase
  • Evaporation increases with temperature
  • Random molecular motion causes some molecules to escape even when the system isn't saturated
This theory helps explain why evaporation can be spontaneous even when relative humidity is not at 100%.
Relative Humidity
Relative humidity is a measure of how much moisture air contains compared to the maximum it can hold at that temperature.
In Process I of the exercise, the air has 50% relative humidity, meaning it is only halfway saturated.
This allows for continued evaporation:
  • Relative humidity below 100% means there's room for more water vapor.
  • Evaporation continues until air becomes saturated or equilibrium is reached.
Understanding relative humidity helps predict whether processes like drying or precipitation will occur, which are crucial for assessing the spontaneity of phase transitions.

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Most popular questions from this chapter

Standard entropy of \(\mathrm{X}_{2}, \mathrm{Y}_{2}\) and \(\mathrm{XY}_{3}\) are 60,40 and 50 \(\mathrm{JK}^{-1} \mathrm{~mol}^{-1}\), respectively. For the reaction, \(1 / 2 \mathrm{X}_{2}+3 / 2 \mathrm{Y}_{2} \longrightarrow \mathrm{XY}_{3}, \Delta \mathrm{H}=-30 \mathrm{~kJ}\), to be at equilibrium, the temperature will be (a) \(1250 \mathrm{~K}\) (b) \(500 \mathrm{~K}\) (c) \(750 \mathrm{~K}\) (d) \(1000 \mathrm{~K}\)

Calculate \(\Delta \mathrm{H}_{\mathrm{f}}^{\circ}\) for chloride ion from the following data: \(1 / 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I} / 2 \mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow \mathrm{HCl}(\mathrm{g})\) \(\Delta \mathrm{H}_{\mathrm{f}}^{\circ}=-92.4 \mathrm{~kJ}\) \(\mathrm{HCl}(\mathrm{g})+\mathrm{nH}_{2} \mathrm{O}(\mathrm{l}) \longrightarrow \mathrm{H}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) \(\Delta \mathrm{H}_{\mathrm{Hyd}}=-74.8 \mathrm{~kJ}\) \(\Delta \mathrm{H}_{\mathrm{f}}^{\mathrm{f}}\left[\mathrm{H}^{+}\right]=0.0 \mathrm{~kJ}\) (a) \(-189 \mathrm{~kJ}\) (b) \(-167 \mathrm{~kJ}\) (c) \(+167 \mathrm{~kJ}\) (d) \(-191 \mathrm{~kJ}\)

The internal energy change when a system goes from state \(\mathrm{A}\) to \(\mathrm{B}\) is \(40 \mathrm{~kJ} / \mathrm{mol}\). If the system goes from \(\mathrm{A}\) to B by a reversible path and returns to state A by an irreversible path what would be the net change in internal energy? (a) \(40 \mathrm{~kJ}\) (b) \(>40 \mathrm{~kJ}\) (c) \(<40 \mathrm{~kJ}\) (d) zero

In the conversion of lime stone to lime, \(\mathrm{CaCO}_{3}(\mathrm{~s}) \longrightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\) The values of \(\Delta \mathrm{H}^{\circ}\) and \(\Delta \mathrm{S}^{\circ}\) are \(+179.1 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(160.2 \mathrm{~J} / \mathrm{K}\) respectively at \(298 \mathrm{~K}\) and 1 bar. Assuming that \(\Delta \mathrm{H}^{\circ}\) and \(\Delta \mathrm{S}^{\circ}\) do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is (a) \(1200 \mathrm{~K}\) (b) \(845 \mathrm{~K}\) (c) \(1118 \mathrm{~K}\) (d) \(1008 \mathrm{~K}\)

The change in entropy, in the conversion of one mole of water at \(373 \mathrm{~K}\) to vapour at the same temperature is (Latent heat of vaporization of water = \(\left.2.257 \mathrm{~kJ} \mathrm{~g}^{-1}\right)\) (a) \(99 \mathrm{JK}^{-1}\) (b) \(129 \mathrm{JK}^{-1}\) (c) \(89 \mathrm{JK}^{-1}\) (d) \(109 \mathrm{JK}^{-1}\)

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