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Which of the following pairs of a chemical reaction is certain to result in a spontaneous reaction? (a) exothermic and increasing disorder (b) exothermic and decreasing disorder (c) endothermic and increasing disorder (d) endothermic and decreasing disorder

Short Answer

Expert verified
The pair (a) exothermic and increasing disorder is certain to result in a spontaneous reaction.

Step by step solution

01

Understand the Problem

The problem asks us to identify which pair of conditions will guarantee a spontaneous chemical reaction. A spontaneous reaction is one that occurs without external influence.
02

Know the Criteria for Spontaneity

The spontaneity of a reaction depends on the Gibbs free energy change (\(\Delta G\)). The reaction is spontaneous if \(\Delta G < 0\). The Gibbs free energy is given by the equation \(\Delta G = \Delta H - T\Delta S\), where \(\Delta H\) is the enthalpy change, \(T\) is the temperature, and \(\Delta S\) is the entropy change.
03

Analyze the Options

For option (a), both an exothermic reaction (\(\Delta H < 0\)) and increasing disorder (\(\Delta S > 0\)) contribute to \(\Delta G < 0\), aiding spontaneity. Option (b) has \(\Delta H < 0\) but \(\Delta S < 0\), which can be less certain for spontaneity. Option (c) has \(\Delta H > 0\) but \(\Delta S > 0\), which might not guarantee spontaneity unless \(T\Delta S\) is very high. Option (d) has \(\Delta H > 0\) and \(\Delta S < 0\), making \(\Delta G\) positive, which is never spontaneous.
04

Conclusion

Based on the analysis, the pair that ensures a spontaneous reaction is (a) exothermic and increasing disorder.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs Free Energy, denoted as \( \Delta G \), is a thermodynamic quantity that helps us predict whether a process is spontaneous. It combines the effects of enthalpy change (\( \Delta H \)), entropy change (\( \Delta S \)), and temperature (\( T \)). The formula for Gibbs Free Energy is:
  • \( \Delta G = \Delta H - T \Delta S \)
A reaction is spontaneous when \( \Delta G \) is negative. This means the system releases free energy during the process, making it favorable to occur on its own.
When you see a negative \( \Delta G \), think of it as a green light for a chemical reaction. The reaction doesn’t need help from outside forces to happen. This is crucial because understanding \( \Delta G \) provides insight into how energy changes drive chemical processes.
Enthalpy Change
Enthalpy Change, symbolized as \( \Delta H \), is the measure of heat absorbed or released during a chemical reaction at constant pressure. It is a fundamental concept in chemistry since it helps describe the thermodynamic nature of reactions.
  • If \( \Delta H \) is negative, the reaction is exothermic, meaning it releases heat to its surroundings. Exothermic reactions often lead to spontaneous reactions.
  • If \( \Delta H \) is positive, the reaction is endothermic, meaning it absorbs heat from its surroundings.
In simple terms, an exothermic reaction feels warm and a spontaneous reaction is more likely. The heat change provides insight into which direction a reaction will favor. This understanding aids in predicting the reaction’s spontaneity together with entropy.
Entropy Change
Entropy Change, denoted as \( \Delta S \), revolves around the concept of disorder within a system. It's a pivotal factor in determining a reaction's spontaneity as per the Gibbs Free Energy equation.
  • A positive \( \Delta S \) indicates increasing disorder, which often favors spontaneity. For example, solid to gas transformations usually have \( \Delta S > 0 \).
  • A negative \( \Delta S \) suggests decreasing disorder, which might oppose spontaneity unless compensated by a significant release of heat (negative \( \Delta H \)).
Entropy can be thought of as a measure of randomness or chaos. Every system tends to favor the direction of higher disorder or randomness. The overall change in entropy, together with enthalpy change, helps forecast whether or not a reaction will occur spontaneously.

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Most popular questions from this chapter

If a gas at constant temperature and pressure expands, then its (a) internal energy decreases (b) entropy increases and then decreases (c) internal energy increases (d) internal energy remains constant

For a reaction to occur spontaneously (a) \((\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S})\) must be negative (b) \((\Delta \mathrm{H}+\mathrm{T} \Delta \mathrm{S})\) must be negative (c) \(\Delta \mathrm{H}\) must be negative (d) \(\Delta \mathrm{S}\) must be negative

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of \(10 \mathrm{dm}^{3}\) to a volume of \(100 \mathrm{dm}^{3}\) at \(27^{\circ} \mathrm{C}\) is: (a) \(35.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) (b) \(38.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) (c) \(45.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) (d) \(23.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\)

The enthalpy of vaporization of a liquid is \(30 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and entropy of vaporization is \(5 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K} .\) The boiling point of the liquid at 1 atm is (a) \(250 \mathrm{~K}\) (b) \(400 \mathrm{~K}\) (c) \(450 \mathrm{~K}\) (d) \(600 \mathrm{~K}\)

Which of the following equations represent standard heat of formation of \(\mathrm{C}_{2} \mathrm{H}_{4} ?\) (a) \(2 \mathrm{C}\) (diamond) \(+2 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})\) (b) \(2 \mathrm{C}\) (graphite) \(+2 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})\) (c) \(2 \mathrm{C}\) (diamond) \(+4 \mathrm{H}(\mathrm{g}) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})\) (d) \(2 \mathrm{C}\) (graphite) \(+4 \mathrm{H}(\mathrm{g}) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})\)

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