Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which of the following compounds on reaction with \(\mathrm{NaOH}\) and \(\mathrm{Na}_{2} \mathrm{O}_{2}\) gives yellow colour? (a) \(\mathrm{Zn}(\mathrm{OH})_{2}\) (b) \(\mathrm{Cr}(\mathrm{OH})_{3}\) (c) \(\mathrm{Al}(\mathrm{OH})_{3}\) (d) none of these

Short Answer

Expert verified
(b) \( \mathrm{Cr(OH)}_3 \) gives a yellow color.

Step by step solution

01

Analyze the Reaction

We need to determine which compound reacts with \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \) to give a yellow color. This reaction combination is known to test for the presence of chromium compounds as chromium can yield a chromate with a yellow hue.
02

Consider Each Compound

First, \( \mathrm{Zn(OH)}_2 \) and \( \mathrm{Al(OH)}_3 \) do not form yellow products with \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \). They form different, colorless ions.However, \( \mathrm{Cr(OH)}_3 \) in the presence of \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \) gets oxidized to \( \mathrm{Na}_2\mathrm{CrO}_4 \), a chromate, which is yellow.
03

Determine the Correct Answer

Since chromate ions (\( \mathrm{CrO}_4^{2-} \)) are yellow and are produced from \( \mathrm{Cr(OH)}_3 \) in this chemical reaction, \( \mathrm{Cr(OH)}_3 \) is the compound that gives the yellow color when reacted with \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chromium Compounds
Chromium compounds are fascinating and versatile in the field of chemistry. They have a range of oxidation states that allow them to participate in varied reactions. Among them, chromium(III) hydroxide, written as \( \mathrm{Cr(OH)}_3 \), is known for its ability to undergo transformations, leading to interesting visual changes.
When we discuss chromium compounds, their distinctive colors in various oxidation states often stand out. For students preparing for Chemistry JEE Main, it's vital to understand chromium's colored compounds, especially chromates and dichromates. These vibrant colors are not only visually striking but serve as important clues in chemical identification.
Here's the key point: chromium's oxidation state changes from +3 in chromium(III) hydroxide to +6 in chromates, which is crucial for its role in certain chemical tests. This shift to a higher oxidation state explains why certain reactions, such as with \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \), result in vivid colors.
Oxidation Reactions
Oxidation reactions are a core element of chemical transformations, especially involving metals like chromium. In the case of chromium(III) hydroxide (\( \mathrm{Cr(OH)}_3 \)), when it reacts in the presence of \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \), it gets oxidized.
But what exactly does it mean to be oxidized? In simple terms, during an oxidation reaction, a substance loses electrons. Here, chromium in \( \mathrm{Cr(OH)}_3 \) transitions to a higher oxidation state, forming chromate ions \( \mathrm{CrO}_4^{2-} \). This reaction results in a color change to bright yellow, signifying a shift to the chromium(VI) state.
  • Key Takeaway: Oxidation increases the oxidation state of a substance, which can often be identified by a change in color, as seen in this reaction where chromium changes from a +3 to a +6 state, forming chromates.
Understanding these processes is not just about recognizing color changes, but also grasping the electron transfer and transformations taking place.
Chromate Test
The chromate test is a simple yet effective chemical procedure used to detect the presence of chromium in a compound by producing a measurable color change. In educational settings, this is a practical application of oxidation principles.
During this test, you mix the compound with \( \mathrm{NaOH} \) and \( \mathrm{Na}_{2} \mathrm{O}_{2} \). If chromium is present, the reaction will produce \( \mathrm{Na}_2\mathrm{CrO}_4 \), a compound recognized for its striking yellow color.
  • Why the test works: Chromium in \( \mathrm{Cr(OH)}_3 \) gets oxidized, forming chromate ions.
  • Visible indicator: The formation of a yellow hue confirms the presence of chromium.
The beauty of the chromate test lies in its straightforwardness. It's a visual and simple method used not only in labs but also in standardized tests like the Chemistry JEE Main to assess knowledge of chemical properties and reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Borax \(\left[\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7} .10 \mathrm{H}_{2} \mathrm{O}\right]\) when heated on platinum loop it gives a dark transparent glass like bead. The hot bead is dipped in the salt till it reacts with transition metal oxide. It produces characteristic bead of meta borate. $$ \begin{array}{ll} \text { Colour of the bead } & \text { Ion } \\ \text { Blue green or light blue } & \mathrm{Cu}^{2+} \\ \text { Yellow } & \mathrm{Fe}^{2+} \text { or } \mathrm{Fe}^{3+} \\ \text { Green } & \mathrm{Cr}^{3+} \\ \text { Violet } & \mathrm{Mn}^{2+} \\ \text { Dark blue } & \mathrm{Co}^{2+} \\ \text { Brown } & \mathrm{Ni}^{2+} \end{array} $$ The hybridisation of \(\mathrm{B}\) in borax is (a) sp (b) \(\mathrm{sp}^{2}\) (c) \(\mathrm{sp}^{3}\) (d) Both (B) and (C)

Which of the following sulphides are yellow? (a) \(\mathrm{As}_{2} \mathrm{~S}_{3}\) (b) \(\mathrm{ZnS}\) (c) \(\mathrm{CdS}\) (d) \(\mathrm{SnS}_{2}\)

Which is incorrect here? (1) Heat of neutralization for strong acid and strong base is always less than \(13.7 \mathrm{~kJ}\). (2) Aniline yellow can also be used to prepare other dyes. (3) Phenolphthalein can be used as an indicator in the titration of strong acid and weak base (4) Methyl orange works in the range of \(3.1-4.4\). (a) 2 and 4 (b) 2 and 3 (c) 1 and 3 (d) 3 and 4

Which of the following reagents can be used to separate a mixture of aniline and phenol here? (1) \(\mathrm{NaHCO}_{3}\) (2) Bromine \(/ \mathrm{H}_{2} \mathrm{O}\) (3) \(\mathrm{NaOH}\) (4) \(\mathrm{HCl}\) (a) 1 and 3 (b) 2 and 4 (c) 3 and 4 (d) 1,3 and 4

Perssian blue is formed when (a) ammonium sulphate reacts with \(\mathrm{FeCl}_{3}\) (b) ferrous sulphate reacts with \(\mathrm{FeCl}_{3}\) (c) ferrous ammonium sulphate reacts with \(\mathrm{FeCl}_{3}\) (d) ferric sulphate reacts with \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free