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Acetic anhydride is used for the detection and estimation of (a) \(-\) COOH group (b) \(-\mathrm{OH}\) group (c) \(-\mathrm{CONH}_{2}\) group (d) \(-\) CHO group

Short Answer

Expert verified
Acetic anhydride is used for the detection and estimation of the –OH group (option b).

Step by step solution

01

Understanding Acetic Anhydride

Acetic anhydride is a reagent commonly used in organic chemistry to introduce acetyl groups into molecules by reacting with functional groups.
02

Reactivity of Functional Groups with Acetic Anhydride

Consider which functional groups acetic anhydride will actively react with. It primarily reacts with hydroxyl (–OH) groups to form esters because hydroxyl groups can nucleophilically attack the acyl carbon of acetic anhydride.
03

Evaluating the Options

We have four options: (a) –COOH group, (b) –OH group, (c) –CONH2 group, and (d) –CHO group. Of these, acetic anhydride is most well-known for reacting with –OH groups to form an ester and acetic acid.
04

Confirming the Best Option

Among the options, the –OH group (option b) is the one that acetic anhydride will most effectively detect and estimate due to its esterification reaction, which is a common practice in organic synthesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acetic Anhydride
Acetic anhydride is an important chemical reagent in organic chemistry, known for its ability to introduce acetyl groups into organic molecules. It has the chemical formula \[ \text{(CH}_3\text{CO)}_2\text{O} \]. This compound is particularly useful in reactions where it acts as an acetylating agent, meaning it adds an acetyl group \( \text{(CH}_3\text{CO)-} \) to various substrates.

The reactivity of acetic anhydride stems from its structure. It is an anhydride, which is a compound formed from two acetic acid molecules by the removal of a water molecule. This makes it highly reactive, specifically with functional groups that can donate electrons.

In the context of organic reactions, its ability to react with nucleophiles, such as alcohols, amines, and water, makes it versatile. With alcohols, for instance, it forms esters, while with water, it produces acetic acid. Understanding these interactions is crucial for its effective use in synthesis.
Functional Groups
Functional groups are specific groups of atoms within molecules that determine the characteristic chemical reactions of those molecules. The interaction between a reagent like acetic anhydride and functional groups is a central theme in organic synthesis and transformation.

Some common functional groups include:
  • Hydroxyl Group (\(-\mathrm{OH}\)): Commonly found in alcohols and phenols. They can act as nucleophiles and are known to react with acetic anhydride to form esters.
  • Carboxyl Group (\(-\mathrm{COOH}\)): Found in carboxylic acids, and though reactive, it doesn’t typically convert into esters with acetic anhydride without special conditions.
  • Amino Group (\(-\mathrm{NH}_2\)): Present in amines and amides. They can also react with acetic anhydride, leading to acetamides.
  • Aldehyde Group (\(-\mathrm{CHO}\)): Aldehydes generally do not react directly with acetic anhydride under basic conditions due to their structure.
Understanding how functional groups behave in chemical reactions allows chemists to predict the products of reactions and to synthesize new materials.
Esterification
Esterification is a chemical reaction that occurs when an acid reacts with an alcohol, resulting in an ester and water. This process can also occur using an acid anhydride, like acetic anhydride, instead of directly using the acid.

In the case of acetic anhydride's reaction with alcohols, the overall esterification reaction can be represented as:\[\text{R–OH} + \text{(CH}_3\text{CO)}_2\text{O} \rightarrow \text{R–OCOCH}_3 + \text{CH}_3\text{COOH}\]where \( \text{R–OH} \) is the alcohol and \( \text{R–OCOCH}_3 \) is the resulting ester.

The mechanism involves the nucleophilic attack of the alcohol’s hydroxyl group (\(-\mathrm{OH}\)) on the carbonyl carbon of the acetic anhydride, forming an intermediate compound that eventually produces an ester. Esterification is key in forming flavors, fragrances, and polymers with diverse industrial applications.

Being able to conduct an esterification reaction with acetic anhydride provides a tool for chemists to modify and enhance molecules with acetylation, finding wide-ranging utility in synthetic laboratories.

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Most popular questions from this chapter

A mixture of two salts is not water soluble but dissolves completely in dil. HCl to form a colourless solution. The mixture could be (a) \(\mathrm{BaCO}_{3}\) and \(\mathrm{ZnS}\) (b) \(\mathrm{AgNO}_{3}\) and \(\mathrm{KBr}\) (c) \(\mathrm{Mn}\left(\mathrm{NO}_{3}\right)_{2}\) and \(\mathrm{MgSO}_{4}\) (d) \(\mathrm{FeCl}_{3}\) and \(\mathrm{CaCO}_{3}\)

Borax \(\left[\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7} .10 \mathrm{H}_{2} \mathrm{O}\right]\) when heated on platinum loop it gives a dark transparent glass like bead. The hot bead is dipped in the salt till it reacts with transition metal oxide. It produces characteristic bead of meta borate. $$ \begin{array}{ll} \text { Colour of the bead } & \text { Ion } \\ \text { Blue green or light blue } & \mathrm{Cu}^{2+} \\ \text { Yellow } & \mathrm{Fe}^{2+} \text { or } \mathrm{Fe}^{3+} \\ \text { Green } & \mathrm{Cr}^{3+} \\ \text { Violet } & \mathrm{Mn}^{2+} \\ \text { Dark blue } & \mathrm{Co}^{2+} \\ \text { Brown } & \mathrm{Ni}^{2+} \end{array} $$ The colour of bead \(\mathrm{Ni}\left(\mathrm{BO}_{2}\right)_{2}\) is of (a) Brown (b) Blue (c) Green (d) Violet

Which of the following is not a correct statement? (a) The aqueous solution of potash alum is acidic due to cationic hydrolysis. (b) Mohr's salt is a double salt (c) Aniline yellow is also called p-amino azobenzene. (d) Iodoform can be prepared from methanol also by haloform reaction.

How do we differentiate between \(\mathrm{Fe}^{3+}\) and \(\mathrm{Cr}^{3+}\) in group III? (a) by increasing \(\mathrm{NH}_{4}{ }^{+}\)ion concentration (b) by decreasing \(\mathrm{OH}^{-}\)ion concentration (c) by adding excess of \(\mathrm{NH}_{4} \mathrm{OH}\) solution (d) both (a) and (b)

In the titration of a certain solution of a mixture of \(\mathrm{NaHCO}_{3}\) and \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) against \(\mathrm{HCl}, \mathrm{V}_{1} \mathrm{~mL}\) of \(\mathrm{HCl}\) is required with phenolphthalein as indicator and \(\mathrm{V}_{2} \mathrm{~mL}\) with methyl orange as indicator for the same volume of the titrated solution. Hence volume of \(\mathrm{HCl}\) for reaction of \(\mathrm{HCl}\) with \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) alone is (a) \(\mathrm{V}_{2} / 4 \mathrm{~mL}\) (b) \(2 \mathrm{~V}_{1} \mathrm{~mL}\) (c) \(\left(\hat{V}_{2}-\mathrm{V}_{1}\right) \mathrm{mL}\) (d) \(\left(\mathrm{V}_{1} / 3\right) \mathrm{mL}\)

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