Chapter 3: Problem 70
If the rms velocity of a gas at \(100 \mathrm{~K}\) is \(10^{4} \mathrm{~cm} \mathrm{sec}^{-1}\), what is the temperature (in \({ }^{\circ} \mathrm{C}\) ) at which the rms velocity will be \(3 \times 10^{4} \mathrm{~cm} \sec ^{-1} ?\) (a) 900 (b) 627 (c) 327 (d) 1217
Short Answer
Expert verified
The temperature is 627°C.
Step by step solution
01
Understanding the Concept of rms Velocity
Root mean square (rms) velocity of gas molecules is given by the equation \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( k \) is the Boltzmann constant, \( T \) is the absolute temperature, and \( m \) is the mass of a molecule.
02
Using the Ratio Form of the rms Velocity Equation
From the formula \( v_{rms} \propto \sqrt{T} \), we deduce that \( \frac{v_1}{v_2} = \sqrt{\frac{T_1}{T_2}} \). Here \( v_1 = 10^4 \text{ cm/sec} \) and \( v_2 = 3 \times 10^4 \text{ cm/sec} \). Therefore, \( \frac{10^4}{3 \times 10^4} = \sqrt{\frac{100}{T_2}} \).
03
Solving for the New Temperature
First, simplify the equation: \( \frac{1}{3} = \sqrt{\frac{100}{T_2}} \). Squaring both sides gives \( \left(\frac{1}{3}\right)^2 = \frac{100}{T_2} \). This simplifies to \( \frac{1}{9} = \frac{100}{T_2} \). Rearranging gives \( T_2 = 900 \text{ K} \).
04
Converting the Temperature to Celsius
Convert the temperature from Kelvin to Celsius using the formula \( \text{Celsius} = \text{Kelvin} - 273.15 \). Thus, the temperature is \( 900 - 273.15 = 626.85 \approx 627^\circ\text{C} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Root Mean Square Velocity
The root mean square (rms) velocity is a concept that helps us understand the motion of gas particles. It's essentially the square root of the average of the squares of the velocities of the gas particles. This measurement provides a useful average speed for gas particles, which is important in thermodynamics and physical chemistry.
The formula for rms velocity is given by:
The formula for rms velocity is given by:
- \( v_{rms} = \sqrt{\frac{3kT}{m}} \)
- \( k \) is the Boltzmann constant, which relates to the energy at the molecular level.
- \( T \) is the temperature in Kelvin, reflecting the average kinetic energy of the particles.
- \( m \) is the mass of one particle of the gas.
Temperature Conversion
Temperature conversion is essential for comparing temperatures in different units. Often, scientific calculations use the Kelvin scale, mainly because it's an absolute temperature scale. But, in many everyday contexts, Celsius is used. The conversion between these two is straightforward:
For instance, if a gas temperature is 900 K, in Celsius this would be:
- \( \text{Celsius} = \text{Kelvin} - 273.15 \)
For instance, if a gas temperature is 900 K, in Celsius this would be:
- \(900 - 273.15 = 626.85 \approx 627^{\circ}\text{C}\)
Ideal Gas Law
The ideal gas law is a fundamental principle that relates the temperature, pressure, and volume of an ideal gas. Though not directly used in the rms velocity calculation, understanding this law gives insight into gas behavior. The ideal gas law is expressed as:
Understanding the ideal gas law helps connect the rms velocity to a broader context of gas behaviors under different conditions.
- \( PV = nRT \)
- \( P \) is the pressure, \( V \) is the volume.
- \( n \) is the number of moles of the gas.
- \( R \) is the ideal gas constant.
- \( T \) is the temperature in Kelvin.
Understanding the ideal gas law helps connect the rms velocity to a broader context of gas behaviors under different conditions.
Boltzmann Constant
The Boltzmann constant, denoted as \( k \), is a fundamental constant in physics and chemistry. It provides a bridge between microscopic and macroscopic physical quantities. The role of the Boltzmann constant is to relate the average kinetic energy of particles in a gas with the temperature of the gas.
When using the rms velocity formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \), the Boltzmann constant helps to quantify the relationship between temperature and kinetic energy. Higher temperature means higher energy and hence faster particle speeds. This constant is indispensable for understanding how variations in temperature influence the movement and energy of gas molecules.
- Its value is approximately \( 1.38 \times 10^{-23} \text{J/K} \).
When using the rms velocity formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \), the Boltzmann constant helps to quantify the relationship between temperature and kinetic energy. Higher temperature means higher energy and hence faster particle speeds. This constant is indispensable for understanding how variations in temperature influence the movement and energy of gas molecules.