Chapter 3: Problem 56
According to the kinetic theory of gases (a) the pressure exerted by a gas is proportional to mean square velocity of the molecules (b) the pressure exerted by the gas is proportional to the root mean square velocity of the molecules (c) the root mean square velocity is inversely proportional to the temperature (d) the mean translational K.E. of the molecule is directly proportional to the absolute temperature.
Short Answer
Step by step solution
Understanding Kinetic Theory Basics
Analyzing Pressure and Mean Square Velocity
Examining Pressure and Root Mean Square Velocity
Relationship between Root Mean Square Velocity and Temperature
Mean Translational K.E. and Temperature Relationship
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pressure and Mean Square Velocity
- The concept of pressure being related to molecular motion is based on the mean square velocity of these molecules.
- Mathematically, pressure, denoted by \( P \), is proportional to the mean square velocity \( \langle v^2 \rangle \).
To understand this better, keep in mind that the mean square velocity is different from the regular mean velocity. It makes use of squaring the velocities before averaging them, which gives more weight to higher speeds. This is why it's critical in analyzing gas pressure and provides a foundation for further understanding the kinetic theory of gases.
Root Mean Square Velocity and Temperature
- The mathematical expression for root mean square velocity is \( v_{rms} = \sqrt{\frac{3kT}{m}} \).
- Here, \( k \) is the Boltzmann constant, \( T \) represents the absolute temperature, and \( m \) is the mass of a single molecule.
The root mean square velocity helps explain phenomena like how quickly a gas spreads in a room. As the temperature increases, the molecules spread out faster due to their increased velocities. Recognizing this link is essential, especially in predicting and analyzing gas behavior under different temperature conditions.
Mean Translational Kinetic Energy
- The formula that expresses mean translational kinetic energy is \( \langle KE \rangle = \frac{3}{2}kT \).
- This equation highlights that the mean translational kinetic energy is directly proportional to the absolute temperature \( T \).
The significance of this relationship is that it directly links the thermal energy possessed by a gas to its kinetic energy. An increase in temperature results in an increase in the kinetic energy of molecules, reflecting increased molecular motion. Similarly, a decrease in temperature indicates less molecular motion, hence, a reduction in kinetic energy.
Understanding mean translational kinetic energy helps grasp how gases store energy and how this affects their behavior under various thermal conditions. It provides a foundational insight into why gases expand when heated and contract when cooled. Such knowledge is invaluable in fields ranging from meteorology to engineering, as it reveals the intricacies of gas behavior.