Chapter 3: Problem 107
The ratio of root mean square velocity to average velocity of a gas molecule at a particular temperature is (a) \(1: 1.086\) (b) \(2: 1.086\) (c) \(1.086: 1\) (d) \(1.086: 2\)
Short Answer
Expert verified
The ratio is (c) \(1.086: 1\).
Step by step solution
01
Identify Relevant Formulas
To solve this problem, we use the formulas for root mean square velocity \(v_{rms}\) and average velocity \(v_{avg}\) of gas molecules. They are given by:\[ v_{rms} = \sqrt{\frac{3RT}{M}} \]\[ v_{avg} = \sqrt{\frac{8RT}{\pi M}} \]where \(R\) is the ideal gas constant, \(T\) is the absolute temperature, and \(M\) is the molar mass of the gas.
02
Express the Ratio
We need to find the ratio \(\frac{v_{rms}}{v_{avg}}\) which results in:\[\frac{v_{rms}}{v_{avg}} = \frac{\sqrt{\frac{3RT}{M}}}{\sqrt{\frac{8RT}{\pi M}}}\]This simplifies to the ratio of the constants under the square root.
03
Simplify the Ratio
Simplifying this equation gives:\[\frac{v_{rms}}{v_{avg}} = \sqrt{\frac{3}{8/\pi}} = \sqrt{\frac{3\pi}{8}}\]Substituting \(\pi \approx 3.1415\) into the equation, we calculate \(\sqrt{\frac{3 \times 3.1415}{8}}\).
04
Calculate Numerically
Calculate \(\sqrt{\frac{3 \times 3.1415}{8}} = \sqrt{1.178}\) using the approximation \(\sqrt{1.178} \approx 1.086\). This implies:\[ \frac{v_{rms}}{v_{avg}} \approx 1.086 \]
05
Select the Correct Answer
The calculated ratio \(v_{rms} : v_{avg} = 1.086 : 1\) matches option (c). Therefore, the correct answer is option (c) \(1.086 : 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Root Mean Square Velocity
Root mean square velocity, denoted as \( v_{rms} \), is a measure of the speed of gas molecules. It provides an average velocity, considering the squared velocities of the molecules but scaled back by taking the square root.
This metric is particularly useful because it accounts for the entire distribution of molecular speeds in a gas sample. The formula for calculating \( v_{rms} \) is:
This metric is particularly useful because it accounts for the entire distribution of molecular speeds in a gas sample. The formula for calculating \( v_{rms} \) is:
- \( v_{rms} = \sqrt{\frac{3RT}{M}} \)
- \( R \) is the ideal gas constant.
- \( T \) is the absolute temperature.
- \( M \) is the molar mass of the gas.
Average Velocity
Average velocity, represented as \( v_{avg} \), is another way to describe the speed of gas molecules.
It is based on the principle of calculating the mean speed of all molecules without any squaring involved, thus it’s a direct mean. The formula to calculate \( v_{avg} \) is given by:
It is based on the principle of calculating the mean speed of all molecules without any squaring involved, thus it’s a direct mean. The formula to calculate \( v_{avg} \) is given by:
- \( v_{avg} = \sqrt{\frac{8RT}{\pi M}} \)
- \( R \) is the ideal gas constant.
- \( T \) is the absolute temperature.
- \( M \) is the molar mass of the gas.
- \( \pi \) is a mathematical constant approximately equal to 3.1415.
Ratio of Velocities
The comparison between root mean square velocity \( v_{rms} \) and average velocity \( v_{avg} \) of gas molecules is often expressed as a ratio. Finding this ratio helps to understand the relationship between different measures of molecular speed, and in the given problem, the aim is to calculate this ratio.
To determine this, you use the expressions:
To determine this, you use the expressions:
- \( \frac{v_{rms}}{v_{avg}} = \frac{\sqrt{\frac{3RT}{M}}}{\sqrt{\frac{8RT}{\pi M}}} \)
- \( \frac{v_{rms}}{v_{avg}} = \sqrt{\frac{3\pi}{8}} \)
Ideal Gas Law
The ideal gas law plays a crucial role in understanding gas behavior, particularly when linking macroscopic properties like pressure, volume, and temperature with molecular properties such as velocities. The equation represents the relationship as follows:
- \( PV = nRT \)
- \( P \) stands for pressure.
- \( V \) represents volume.
- \( n \) is the number of moles of gas.
- \( R \) is the ideal gas constant.
- \( T \) is the absolute temperature.