Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Carbonation of methylmagnesium bromide gives an organic compound. This compound is also obtained by (a) Hydrolysis of methyl formate with dilute mineral acid (b) Oxidation of methyl alcohol (c) Hydrolysis of methyl formate with dilute mineral acid (d) Hydrolysis of acetonitrile by a mineral acid

Short Answer

Expert verified
The answer is (d), Hydrolysis of acetonitrile by a mineral acid.

Step by step solution

01

Understand the Reaction

When methylmagnesium bromide, a Grignard reagent, reacts with carbon dioxide, it forms a carboxylate salt which, upon acidification, gives acetic acid (00-CH₃).
02

Analyze Option (a)

Hydrolysis of methyl formate (HCOOCH₃) using a dilute mineral acid yields formic acid (HCOOH) and methanol (CH₃OH). This reaction does not produce acetic acid.
03

Analyze Option (b)

Oxidation of methyl alcohol (CH₃OH) first leads to the formation of formaldehyde (HCHO), and upon further oxidation, it does formic acid, not acetic acid.
04

Analyze Option (c)

This option appears to be miswritten since it is identical to (a). Neither are related to the production of acetic acid specifically.
05

Analyze Option (d)

Hydrolysis of acetonitrile (CH₃CN) by a mineral acid produces acetic acid (00-CH₃), as the nitrile group converts to a carboxylic acid group in the process.
06

Conclusion

Only the hydrolysis of acetonitrile by a mineral acid corresponds to the formation of the same final product as carbonation of methylmagnesium bromide, acetic acid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Methylmagnesium Bromide
Methylmagnesium bromide, a popular Grignard reagent, is a compound where a magnesium atom is bonded to a methyl group and a bromine atom. It’s usually represented as CH₃MgBr. The compound is crucial in organic chemistry for forming Grignard reactions, which create carbon-carbon bonds. Grignard reagents react with a variety of electrophilic compounds, allowing for the synthesis of a wide array of organic molecules. In this specific context, when methylmagnesium bromide reacts with carbon dioxide, it undergoes a carboxylation reaction. One of the carbon dioxide’s oxygen double bonds breaks, and the Grignard reagent adds to it. This results in a carboxylic acid salt. When this salt is acidified, it turns into a carboxylic acid, here resulting in acetic acid. The cleverness in using Grignard reagents lies in their versatility for synthesizing complex molecules through simple reactions. Whether making alcohols, acids, or other functional groups, Grignard reactions remain a staple in the chemist's toolkit.
Carboxylic Acid Formation
Carboxylic acids are critical in organic chemistry due to their ability to participate in various chemical reactions. They are characterized by the presence of a carboxyl group (-COOH). In this context, the formation of acetic acid showcases a straightforward process of carboxylic acid production through the carbonation of methylmagnesium bromide. When introducing carbon dioxide to the Grignard reagent methylmagnesium bromide, a carboxylation reaction occurs. This transforms the carbon dioxide into a carboxylate ion, which subsequently forms the carboxylic acid upon acidification. This process highlights a common method in organic synthesis to create carboxylic acids. Besides being formed from reactions involving Grignard reagents, carboxylic acids can also emerge from other processes like hydrolysis. The reaction mechanisms involved ensure that carboxylic acids remain versatile intermediates in producing numerous complex molecules.
Hydrolysis of Nitriles
Hydrolysis is a chemical process in which water breaks chemical bonds, and in organic chemistry, nitriles can be transformed into carboxylic acids via hydrolysis. Hydrolosis of nitriles involves breaking the nitrogen-carbon triple bond with a water molecule. In the exercise, acetonitrile (CH₃CN), a simple nitrile, undergoes hydrolysis in the presence of a mineral acid. When hydrolyzed, the nitrile group in acetonitrile converts into a carboxylic acid group, producing acetic acid. This transformation aligns with the final product formed in the carbonation of methylmagnesium bromide. The capability of converting nitriles to carboxylic acids is not only practical but also environmentally beneficial as it allows for the creation of essential organic acids without extensive resources. This method provides a robust route for synthesizing necessary compounds in both laboratory settings and industrial production.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The reaction of benzaldehdye with alkali gives (a) benzene + benzyl alcohol (b) phenol + benzene (c) benzene + benzyl alcohol (d) benzyl alcohol + sodium benzoate

\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO} \frac{\mathrm{NaCN}}{(\mathrm{HCl})}-\mathrm{A} \stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow} \mathrm{B}\) in the above sequence of reactions \(\mathrm{A}\) and \(\mathrm{B}\) are (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH}\) (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH})_{2}\) (c) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{COOH}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}\)

Which one of the following pairs is not correctly matched? (a) \(>\mathrm{C}=\mathrm{O} \longrightarrow \mathrm{CH}_{2}\) Clemmensen reduction (b) \(-\mathrm{COCl} \longrightarrow \mathrm{CHO}\) Rosenmund reduction (c) \(>\mathrm{C}=\mathrm{O} \longrightarrow>\mathrm{CHOH}\) Wolff - Kishner reduction (d) \(-\mathrm{C} \equiv \mathrm{N} \longrightarrow-\mathrm{CHO}\) Stephen reduction

When propanamide reacts with \(\mathrm{Br}_{2}\) and \(\mathrm{NaOH}\) then which of the following compounds is formed? (a) propyl alcohol (b) ethyl alcohol (c) ethylamine (d) propylamine

Consider the following acids: (1) \(\mathrm{O}-\mathrm{HOC}_{6} \mathrm{H}_{4} \mathrm{COOH}\) (2) \(\mathrm{O}-\mathrm{CH}_{3} \mathrm{OC}_{6} \mathrm{H}_{4} \mathrm{COOH}\) (3) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}^{\circ}\) Arrange these acids in the decreasing order of their acidities. (a) \(1>3>2\) (b) \(3>2>1\) (c) \(1>2>3\) (d) \(2>3>1\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free