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Which one of the following statements incorrect? Benzaldehyde can be produced by the (a) reduction of benzoyl chloride (b) oxidation of toluene (c) hydrolysis of benzal chloride (d) reduction of benzyl chloride

Short Answer

Expert verified
The incorrect statements are (a) and (d).

Step by step solution

01

Understanding the Problem

To determine which statement about the production of benzaldehyde is incorrect, we need to analyze each option and understand the chemical reactions involved in producing benzaldehyde.
02

Analyzing Option (a)

Option (a) suggests that benzaldehyde can be produced by the reduction of benzoyl chloride. This is incorrect because reducing benzoyl chloride typically gives benzyl alcohol, not benzaldehyde.
03

Analyzing Option (b)

Option (b) states that benzaldehyde can be produced by the oxidation of toluene. This is correct; the partial oxidation of toluene can yield benzaldehyde.
04

Analyzing Option (c)

Option (c) proposes that benzaldehyde can be produced by the hydrolysis of benzal chloride. This is correct; hydrolysis of benzal chloride yields benzaldehyde.
05

Analyzing Option (d)

Option (d) claims that benzaldehyde can be produced by the reduction of benzyl chloride. This is incorrect; reducing benzyl chloride typically produces toluene, not benzaldehyde.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction Reactions
Reduction reactions play a key role in the transformation of chemical compounds by adding electrons to a substance. This can often change a molecule's structure significantly. In this context, when we talk about reducing a compound like benzoyl chloride, we are referring to the addition of electrons and hydrogen to the molecule. However, instead of producing benzaldehyde, the reduction of benzoyl chloride typically results in the formation of benzyl alcohol. This happens because the reduction process converts the carbonyl group present in benzoyl chloride into a hydroxyl group, producing the alcohol.
Typically, in a reduction reaction, you will notice:
  • Gain of hydrogen atoms
  • Loss of oxygen atoms
  • Gain of electrons
When analyzing this specific reaction, it is crucial to remember that not all reductions can precisely form the desired product. Understanding the nature of reducing agents and the influences they have on different compounds is vital in predicting the outcomes of chemical reactions.
Oxidation Reactions
Oxidation reactions are the opposite of reduction. They involve the loss of electrons and often are associated with the gain of oxygen or loss of hydrogen. Toluene can be oxidized to produce benzaldehyde when a catalyst that aids in partial oxidation is used. The process involves removing a hydrogen atom and adding an oxygen atom to the carbon in the toluene molecule.
In oxidation reactions, you generally see:
  • Loss of hydrogen atoms
  • Gain of oxygen atoms
  • Loss of electrons
Partial oxidation is an important concept in industrial chemistry, especially when targeting specific products like benzaldehyde, which can be further oxidized if not controlled carefully. Hence, understanding and applying controlled oxidation procedures is essential to produce desired chemical compounds effectively.
Chemical Reaction Analysis
Chemical reaction analysis is about assessing and understanding the transformations during a chemical reaction. In analyzing the options for producing benzaldehyde, it's important to evaluate each proposed method based on the nature of the reactions involved.
With benzaldehyde production, several pathways can yield the compound, but not all are correct. For instance:
  • The hydrolysis of benzal chloride is a straightforward method as it breaks down benzal chloride with water to yield benzaldehyde.
  • Understanding the specific changes, like which bonds are broken and formed, can help in analyzing whether the reaction pathway will produce the expected product.
  • Knowledge of the properties of reactants like benzoyl chloride, toluene, and benzal chloride is crucial to predict the outcome of reactions involving them.
Conducting a thorough chemical reaction analysis helps chemists troubleshoot incorrect pathways and strategize more efficient methods for synthesizing specific compounds, ensuring that the desired product is obtained with minimal byproducts.

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Most popular questions from this chapter

A compound of molecular weight 180 is acetylated to give a compound of molecular weight \(390 .\) The number of amino groups in the compound is (a) 6 (b) 5 (c) 4 (d) 3

Cinnamic acid is formed when \(\mathrm{C}_{6} \mathrm{H}_{5}\) CHO condensation with \(\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}\) in presence of (a) sodium metal (b) sodium acetate (c) anhydrous \(\mathrm{ZnCl}_{2}\) (d) conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\)

Which one of the following acids is thermally most unstable? (a) \(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{COOH}\) (b) \(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\) (c) \(\mathrm{CH}_{3} \mathrm{COCOOH}\) (d) \(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\)

Treatment of propionaldehyde with dil. \(\mathrm{NaOH}\) solution gives (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CHO}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}_{2} \mathrm{CH}_{2} \mathrm{CHO}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHOHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CHO}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)

A substance \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) yields on oxidation a compound, \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}\) which gives an oxime and a positive iodoform test. The original substance on treatment with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) gives \(\mathrm{C}_{4} \mathrm{H}_{\mathrm{g}}\). The structure of the compound is (a) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}\) (b) \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{2} \mathrm{CH}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2} \mathrm{CH}_{3}\)

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