Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The best reagent to convert pent-3-en-2-ol into pent3-en \(-2\)-one is (a) acidic permanganate (b) acidic dichromate (c) chromic anhydride in glacial acetic acid (d) pyridinium chloro-chromate

Short Answer

Expert verified
The best reagent is pyridinium chloro-chromate (PCC).

Step by step solution

01

Understand the Reaction

The reaction described is the conversion of an alcohol (pent-3-en-2-ol) into a ketone (pent-3-en-2-one). This is an oxidation reaction where an alcohol is oxidized to a ketone.
02

Evaluate Each Option

Evaluate each option based on its ability to oxidize secondary alcohols to ketones. (a) Acidic permanganate is strong but typically over-oxidizes alcohols to carboxylic acids. (b) Acidic dichromate can oxidize alcohols to ketones but might be too strong. (c) Chromic anhydride in glacial acetic acid is a known reagent for selective oxidation. (d) Pyridinium chloro-chromate (PCC) is known for oxidizing alcohols to aldehydes and ketones without over-oxidizing.
03

Select Best Reagent

The best choice must selectively oxidize the secondary alcohol to a ketone without further oxidation. PCC (option d) is renowned for its ability to convert alcohols to aldehydes or ketones without over-oxidizing to carboxylic acids, making it the ideal choice for this reaction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation of Alcohols
In organic chemistry, the oxidation of alcohols is a crucial process. It involves converting an alcohol into a more oxidized form, such as a ketone or aldehyde. This transformation is significant because it can change the properties and reactivity of a molecule. The oxidation process usually involves the removal of hydrogen atoms from the alcohol group.
For secondary alcohols like pent-3-en-2-ol, oxidation typically yields ketones. Understanding the nature of this transformation is key to predicting the outcome of reactions in organic synthesis.
Let’s summarize the general steps:
  • Start with an alcohol functional group.
  • Apply an oxidizing agent.
  • End with a ketone or aldehyde with increased oxidation state.
The choice of oxidizing agent is crucial for achieving the desired product selectively and efficiently.
Reagents in Organic Chemistry
Reagents are essential tools in organic chemistry, acting as the workhorses that drive chemical reactions forward. They are substances or compounds added to cause a chemical reaction, and the choice of reagent has a significant impact on the reaction outcome.
Different reagents have specific properties that make them suitable for certain reactions. For example:
  • Strong oxidizers like acidic permanganate can over-oxidize alcohols to carboxylic acids.
  • Acidic dichromate is potent but can be too harsh, leading to over-oxidation.
  • Chromic anhydride in glacial acetic acid allows selective oxidation without over-oxidizing.
  • Pyridinium chloro-chromate (PCC) is preferred for its ability to convert alcohols to aldehydes or ketones smoothly, without further oxidation to acids.
Choosing the right reagent ensures the transformation is achieved with precision, minimizing side reactions and maximizing yield.
Alcohol to Ketone Conversion
The process of converting alcohols to ketones is a common transformation in organic chemistry, essential for synthesizing compounds with desired properties. Secondary alcohols like pent-3-en-2-ol are ideal candidates for oxidation to ketones.
To effectively carry out this conversion, a suitable reagent like Pyridinium chloro-chromate (PCC) is used. PCC is known for:
  • Its ability to oxidize secondary alcohols to ketones without requiring additional catalysts.
  • Operating under mild conditions, thus preventing over-oxidation to carboxylic acids.
Here’s how it works: the PCC reagent acknowledges the presence of the hydroxyl group in the alcohol and facilitates the oxidation, removing hydrogen atoms to generate a ketone.
This conversion is significant because ketones serve as important building blocks in various chemical syntheses, offering stability and reactivity useful for further chemical manipulation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A fruity smell is produced by the reaction of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) with (a) \(\mathrm{PCl}_{5}\) (b) \(\mathrm{CH}_{3} \mathrm{COOH}\) (c) \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) (d) none of these

\(\mathrm{CH}_{3} \mathrm{COCl}\) reacts with (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (b) Salicylic acid (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\) (d) all of these

\(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO} \frac{\mathrm{NaCN}}{(\mathrm{HCl})}-\mathrm{A} \stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow} \mathrm{B}\) in the above sequence of reactions \(\mathrm{A}\) and \(\mathrm{B}\) are (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH}\) (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH})_{2}\) (c) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{COOH}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}\)

A compound of molecular weight 180 is acetylated to give a compound of molecular weight \(390 .\) The number of amino groups in the compound is (a) 6 (b) 5 (c) 4 (d) 3

What will happen if \(\mathrm{LiAlH}_{4}\) is added to an ester? (a) one unit of alcohol and one unit of acid is obtained (b) two units of alcohol are obtained (c) two units of acids are obtained (d) none of these

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free