Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An organic compound (A) reacts with sodium metal and forms (B). On heating with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\), (A) gives diethyl ether. (A) and (B) are respectively (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{ONa}\) (b) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\) and \(\mathrm{CH}_{3} \mathrm{ONa}\) (c) \(\mathrm{CH}_{3} \mathrm{OH}\) and \(\mathrm{CH}_{3} \mathrm{ONa}\) (d) \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}\) and \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{ONa}\)

Short Answer

Expert verified
(a) \( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \) and \( \mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa} \).

Step by step solution

01

Identify the Reaction with Sodium

The problem states that compound A reacts with sodium metal to form compound B. This indicates that compound A is an alcohol. When an alcohol reacts with sodium, it forms an alkoxide and hydrogen gas. For example, ethanol (\( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \)) reacts with sodium to form sodium ethoxide (\( \mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa} \)).
02

Determine Reaction with Concentrated Sulfuric Acid

The problem states that compound A, when heated with concentrated \( \mathrm{H}_2 \mathrm{SO}_4 \), gives diethyl ether. The formation of diethyl ether involves the dehydration of ethanol (\( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \)) in the presence of acid to form ether. This suggests that compound A must be ethanol, which readily forms diethyl ether when treated with acid.
03

Match the Compounds to Options

Given that compound A is ethanol (\( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \)) that reacts with sodium to form sodium ethoxide (\( \mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa} \)), the corresponding pair in the options is option (a): \( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \) and \( \mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa} \). Therefore, the correct answer is option (a).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ethanol
Ethanol, commonly known as ethyl alcohol, is a colorless, flammable liquid. It's a key ingredient in alcoholic beverages but also serves crucial roles in various industrial and chemical processes. Chemically, it is represented by the formula \( \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \). Understanding ethanol involves recognizing its dual nature as both a drinkable alcohol and an essential chemical reagent.

In reactions, ethanol often participates as a reactant, providing a hydroxyl group \( (\mathrm{-OH}) \). This characteristic makes it a prime candidate for participating in substitution reactions like forming alkoxides. Ethanol's ability to donate a proton (\( \mathrm{H}^+ \)) from its hydroxyl group underlies many of its chemical transformations.

Key attributes of ethanol include:
  • Polar structure, allowing it to mix with water.
  • Combustibility, making it useful as a fuel.
  • Capacity to form ethers like diethyl ether when subjected to specific conditions like heating with acids.
The versatility of ethanol makes it foundational in both organic chemistry labs and various industries.
Sodium Alkoxide
Sodium alkoxide is a compound formed when an alcohol reacts with metallic sodium. In this context, the alkoxide of interest is sodium ethoxide, produced when ethanol reacts with sodium metal.

The reaction can be summarized as follows:

\[ \mathrm{2} \; \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} + \mathrm{2Na} \rightarrow \mathrm{2} \; \mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa} + \mathrm{H}_2 \uparrow \]

Here, ethoxide ions replace the hydroxyl hydrogen, yielding hydrogen gas as a byproduct. Sodium alkoxides like sodium ethoxide are crucial intermediates in organic synthesis.

Key properties of sodium alkoxides include:
  • Strong basicity, as they readily donate\/accept protons.
  • Usage as bases or nucleophiles in chemical reactions.
  • Soluble in organic solvents, facilitating their role in non-aqueous conditions.
Sodium alkoxides are not only essential in laboratory syntheses but also play roles in industrial applications that involve converting alcohols into other chemical forms.
Dehydration Reaction
Dehydration reactions are important for forming complex molecules by removing water. In the context of ethanol, when it is heated with a strong acid like sulfuric acid, dehydration results in the formation of ethers.

The general dehydration equation is:
\[ \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} \xrightarrow{\text{\( H_2SO_4 \), \text{heat}}} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OCH}_2 \mathrm{CH}_3} + \mathrm{H}_2\mathrm{O} \]

Here, two ethanol molecules lose water, bonding together to form diethyl ether. Dehydration reactions are widely used in organic chemistry for synthesizing new compounds.

Important features of dehydration reactions include:
  • Requires acid catalysts and heat to proceed.
  • Often result in symmetric or mixed ethers depending on reactants.
  • Accompanied by the loss of one molar equivalent of water.
Understanding dehydration reactions helps in designing pathways for synthesizing a broad range of simple and complex chemicals.
Diethyl Ether Formation
Diethyl ether formation is a classic example of how alcohols can transform into ethers through dehydration. This particular process involves ethanol molecules under specific conditions.

The synthesis of diethyl ether typically requires heating ethanol with concentrated sulfuric acid. This induces a dehydration reaction, in which two ethanol molecules combine, foregoing a water molecule:
  • The hydroxyl group of one ethanol loses an \( \mathrm{H}^+ \), while another ethanol provides an \( \mathrm{H}^- \) to form water.
  • The resulting carbocation intermediate facilitates the linkage of two ethyl groups, creating diethyl ether.
Diethyl ether's formation emphasizes how simple structure manipulations can produce a functional and useful chemical compound in both the lab and industry.

Its characteristics include:
  • Low boiling point, providing utility as a solvent.
  • Colorless and highly volatile nature.
  • Role as an anesthetic in earlier medical practices.
In summary, diethyl ether formation from ethanol highlights the interplay between fundamental chemical reactions and practical applications in chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Among the following, the most stable compound is (a) cis-1, 2-cyclohexanediol (b) trans- 1,2 -cyclohexanediol (c) cis-1, 3-cyclohexenediol (d) trans- 1,3 -cyclohexanediol

Which of the following compounds on reaction with \(\mathrm{CH}_{3} \mathrm{MgBr}\) will give a tertiary alcohol? CC(C)(C)C 11 (a) (b) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{CH}_{3}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COOH}\)

Match the following: List I 1\. absolute alcohol 2\. denatured alcohol 3\. \(80 \%\) proof alcoholic liquor 4\. rubbing alcohol List II (i) alcohol made undrinkable by the addition of toxic materials or poisons. (ii) alcoholic liquor containing \(40 \%\) ethanol by volume (iii) anhydrous alcohol (iv) isopropyl alcohol The correct matching is:

Which of the following reactions will yield 2-propanol? (1) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{O} \stackrel{\mathrm{H}^{\prime}}{\longrightarrow}\) (2) \(\mathrm{CH}_{3} \mathrm{CHO} \stackrel{\text { (i) } \mathrm{CH}_{3} \mathrm{MgI}, \text { (ii) } \mathrm{H}_{2} \mathrm{O}}{\longrightarrow}\) (3) \(\mathrm{CH}_{2} \mathrm{O} \quad\) (i) \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Mgl}\), (ii) \(\mathrm{H}_{2} \mathrm{O}\) (4) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3} \stackrel{\text { Neutral } \mathrm{KMnO}_{4}}{\longrightarrow}\) (a) 1 and 3 (b) 2 and 4 (c) 1 and 2 (d) 3 and 4

Ortho \(-\) Nitrophenol is less soluble in water than pand \(\mathrm{m}-\) Nitrophenols because (a) Melting point of o- Nitrophenol is lower than those of \(\mathrm{m}\) - and \(\mathrm{p}\) - isomers (b) o- Nitrophenol is more volatile in steam than those of \(\mathrm{m}\) - and \(\mathrm{p}\) - isomers (c) o- Nitrophenol shows Intramolecular H-bonding (d) o- Nitrophenol shows Intermolecular H-bonding

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free