Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

On reacting with oxalic acid at \(503 \mathrm{~K}\), glycerol gives (a) formic acid (b) glyceraldehyde (c) allyl alcohol (d) none of these

Short Answer

Expert verified
The correct product is (c) allyl alcohol.

Step by step solution

01

Understanding the reaction

Glycerol, a trihydric alcohol (also known as glycerine), when reacted with oxalic acid at high temperature (around \(503 \text{ K}\)), undergoes a dehydration reaction. The key is to examine if this reaction is known and to identify the products that typically result.
02

Identify possible products

During the heating of glycerol with oxalic acid, a dehydration process can yield several possible products: one of which is allyl alcohol. It is important to note that the conditions specified, namely the high temperature of \(503 \text{ K}\), favor this typical dehydration product.
03

Evaluating the options

Review the options provided: (a) formic acid, (b) glyceraldehyde, (c) allyl alcohol, (d) none of these. Considering the identified reaction, the product formed by this specific dehydration process is allyl alcohol. This matches option (c).
04

Conclusion

Determining the accurate option means confirming allyl alcohol as the correct answer when glycerol is reacted with oxalic acid at \(503 \text{ K}\). Thus, the choice is found among the given options.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dehydration Reaction
In chemistry, a dehydration reaction is a type of chemical reaction that typically involves the removal of water from a molecule. It's like squeezing out moisture to form a new, different substance. This process is especially common with alcohols, like glycerol, where the hydroxyl groups (\( -OH \)) can lose a water molecule. By applying heat or a catalyst, a dehydration reaction can lead to the creation of unsaturated compounds. In the example of glycerol reacting with oxalic acid at \( 503 \text{ K} \), this high temperature provides the necessary energy for the dehydration reaction to occur.
  • This reaction results in the loss of water molecules.
  • Leads to the formation of new products, which are often unsaturated compounds.
  • Usually requires heat or another form of energy to proceed.
Overall, dehydration reactions play a crucial role in transforming compounds and are foundational in organic synthesis and industrial applications.
Allyl Alcohol Formation
During the dehydration reaction of glycerol with oxalic acid, one major product formed is allyl alcohol. Allyl alcohol is an organic compound characterized by its functional group \( CH_2=CH-CH_2OH \), making it an unsaturated alcohol. The formation of allyl alcohol illustrates how dehydration can alter a compound's structure by creating a double bond.
  • Occurs typically when glycerol loses water to form a double bond.
  • The resulting allyl alcohol has a distinct smell – sometimes recognized in nature as it can be found in garlic.
  • This compound serves as a valuable intermediate in various chemical synthesis processes, including the production of pharmaceuticals and fragrances.
Understanding allyl alcohol formation not only explains reactions like the one between glycerol and oxalic acid but also showcases the utility of allyl alcohol in industrial and pharmaceutical fields.
Organic Chemistry
Organic chemistry is the study of carbon-containing compounds and their reactions. It's foundational to understanding biological molecules and the myriad of reactions they can undergo. In the realm of organic chemistry, reactions like the one between glycerol and oxalic acid provide a microcosm of study into how molecules interact. Organic chemistry facilitates the synthesis of new materials, enhances understanding of biological processes, and more.
  • Covers the reactions, composition, structure, and synthesis of carbon-based compounds.
  • Helps in understanding the properties of substances ranging from simple gases to complex polymers.
  • Leverages reactions such as dehydration to explore the transformations these molecules can undergo.
Without organic chemistry, the development of pharmaceuticals, polymers, and even everyday materials would be unsophisticated, underscoring its profound impact on technology and life sciences.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An unknown alcohol is treated with the "Lucas reagent" to determine whether the alcohol is primary, secondary or tertiary. Which alcohol reacts fastest and by what mechanism (a) secondary alcohol by \(\mathrm{S}_{\mathrm{N}^{2}}\) (b) tertiary alcohol by \(\mathrm{S}_{\mathrm{N}^{2}}\) (c) Secondary alcohol by \(\mathrm{S}_{\mathrm{N} 1}\) (d) tertiary alcohol by \(\mathrm{S}_{\mathrm{N}^{1}}\)

The molecule which the highest boiling point is (a) \(\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{3}\) (b) \(\mathrm{CH}_{3}-\mathrm{CHOH}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\) (d) \(\mathrm{CH}_{3}-\mathrm{CHOH}-\mathrm{CH}_{3}\)

In the following sequence of reactions, \(\mathrm{CH}_{3}-\mathrm{CH}\left(\mathrm{NH}_{2}\right)-\mathrm{CH}_{3} \stackrel{\mathrm{HNO}_{2}}{\longrightarrow} \mathrm{A}\) oxidation \(\underset{\text { (ii) } \mathrm{H}^{\prime} / \mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{B} \frac{\text { (i) } \mathrm{CH}_{3} \mathrm{Mgl}}{\mathrm{C}}\) the compound \(\mathrm{C}\) formed will be (a) butanol-1 (b) 2 -methylpropanol-1 (c) 2 -methylpropanol-2 (d) butanol-2

Which of the following is/are correct? (a) Phenol gives paraquinol with \(\mathrm{S}_{2} \mathrm{O}_{8}^{-2} / \mathrm{OH}^{-}\)as a major product. (b) Phenol can give electrophilic aromatic substitution reactions in absence of lewis acid. (c) Salicylic acid can give white/yellow solution with \(\mathrm{Br}_{2} / \mathrm{CS}_{2}\) (d) Ipso substitution is possible in phenol derivative if it contains \(-\mathrm{COOH}\) or \(-\mathrm{SO}_{3} \mathrm{H}\) group at ortho or para position with respect to OH group.

In the reaction sequence, \(\mathrm{Z}\) will be Glycerol \(\stackrel{\mathrm{KHSO}_{4} / \Delta}{\longrightarrow} \mathrm{X} \stackrel{\mathrm{Zn}-\mathrm{Hg} / \mathrm{conc} \mathrm{HCl} / \Delta}{\longrightarrow}\) \(\mathrm{Y} \stackrel{\mathrm{NBS} / \mathrm{CCl}_{4}}{\longrightarrow} \mathrm{Z}\) (a) 1, 2-dibromopropane (b) 1-bromopropane (c) 2-bromopropane (d) 3-bromopropene

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free