Chapter 27: Problem 173
Carbonyl compounds on reduction with selective reducing agents give alcohols. The structure of alcohol formed depends upon the nature of reducing agents. \(\operatorname{LiAlH}_{4}\), \(\mathrm{NaBH}_{,}\), sodium alcohol, \(\mathrm{Mg}(\mathrm{Hg}) \mathrm{H}, \mathrm{O}\) etc can be used. When \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CHO}\) is reduced with \(\mathrm{NaBH}_{4}\), the product formed is (a) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OH}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CHO}\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}^{2}-\mathrm{CH}_{2}^{2}-\mathrm{CH}_{3}\) (d) \(\mathrm{CH}_{3}^{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{OH}\)
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