Chapter 26: Problem 131
Aryl halides are less reactive towards nucleophilic substitution reactions as compared to alkyl halides due to 1\. the formation of less stable carbonium ion 2\. resonance stabilization 3\. longer carbon-halogen bond 4\. the inductive effect 5\. sp \(^{2}\) hybridized carbon attached to halogen (a) \(1,2,3\) (b) \(2,4,5\) (c) 2,5 (d) 4,5
Short Answer
Step by step solution
Understanding Aryl Halides Reactivity
Evaluate Resonance Stabilization (Option 2)
Evaluate the Role of sp² Hybridization (Option 5)
Cross Out Incorrect Options
Selecting the Correct Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Resonance Stabilization
Resonance stabilization in aryl halides can be visualized in terms of resonance structures, where the lone pair on the halogen atom can be delocalized across the pi system of the benzene ring. This creates partial double-bond character to the carbon-halogen bond, thereby strengthening the bond and reducing the possibility of the halogen atom leaving.
- This added stability through electron delocalization means that the carbon-halogen bond is tougher to break.
- Resonance not only stabilizes an aryl halide but also poses a challenge for a nucleophile to effectively kick out the halogen atom.
sp² Hybridization
The \ \( sp^{2} \ \) hybridization leads to a bond with more s-character, which results in not only a more robust bond but also enhances overlap between the carbon and halogen atoms. This tight bonding means greater energy is required to break such a bond, significantly reducing the chance of a nucleophilic substitution.
- The shorter and stronger C-X bond due to \ \( sp^{2} \ \) hybridization makes bond cleavage more challenging during reactions.
- Consequently, this structural feature contributes to the lower reactivity of aryl halides toward nucleophilic attacks.
Aryl Halides Reactivity
Aryl halides, due to their structural configuration, resist typical nucleophilic substitution. The aromatic ring provides resistance, stabilizing the compound and reducing the likelihood of substitution.
- The aromatic core resists disruption because it features a highly delocalized \ \( \pi \)-electron system.
- The combination of resonance stabilization and \ \( sp^{2} \ \)-hybridized carbons enhances bond strength and durability.