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Which one is the correct statement? (a) 2-butene is Saytzeff's product (b) 1-butene is the Hofmann product (c) both (a) and (b) are correct (d) none is correct

Short Answer

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(c) both (a) and (b) are correct.

Step by step solution

01

Understanding the Terms

First, let's understand the terms involved in the statements. Saytzeff's Rule (or Zaitsev's rule) states that in an elimination reaction, the more substituted alkene is usually the major product. The Hofmann product, on the other hand, refers to the less substituted alkene formed in eliminations that occur with quaternary ammonium salts.
02

Analyzing 2-Butene

2-butene is a more substituted alkene compared to 1-butene, as its double bond is located between the second and third carbon atoms, allowing more alkyl groups to be attached around the double bond. According to Saytzeff's Rule, 2-butene would be the major product in a typical E2 elimination reaction, so statement (a) is correct in general contexts.
03

Analyzing 1-Butene

1-butene is less substituted than 2-butene, as its double bond is at the terminal carbon (between the first and second carbon atoms). In eliminations with bulky bases or specific conditions, according to Hofmann’s rule, the less substituted alkene like 1-butene becomes the major product, making statement (b) correct under these specific conditions.
04

Evaluating Combined Statement

Both statements (a) and (b) can be correct given their individual justifications. Statement (c), suggesting both (a) and (b) are correct under the respective contexts, is thus the correct choice.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Saytzeff's Rule
In the world of organic chemistry, Saytzeff's Rule is an essential guideline used to predict the outcome of elimination reactions, particularly E2 reactions. According to this rule, the preferred product of an elimination reaction is the more substituted alkene. A more substituted alkene means there are more alkyl groups (like methyl or ethyl groups) attached to the carbon atoms involved in the double bond. Generally, alkenes with more alkyl groups around the double bond are more stable due to hyperconjugation and inductive effects. This stability explains why they are formed as major products more commonly.

When predicting products using Saytzeff's Rule:
  • Look for the potential alkenes that can form from the elimination reaction.
  • Identify the degree of substitution of each possible alkene.
  • Recognize that the more substituted alkene is typically favored.
Saytzeff's Rule is typically applied to reactions involving small, non-bulky bases where steric hindrance plays a minimal role in the reaction mechanism.
Hofmann Product
The Hofmann Product is an interesting concept, often considered an exception to Saytzeff's Rule. It arises predominantly in eliminations involving bulky bases or quaternary ammonium substrates through the E2 or E1cb reaction mechanisms. Unlike the more stable, substituted alkenes advocated by Saytzeff's Rule, the Hofmann Product is the less substituted alkene. This means that the double bond is positioned towards the end of the carbon chain, thus involving fewer alkyl groups.

Factors favoring Hofmann Product formation include:
  • The use of sterically hindered, bulky bases.
  • Elimination from quaternary ammonium salts.
  • Reactions under conditions where steric effects outweigh stability effects.
In these scenarios, the less substituted alkene forms more easily because the bulky base cannot effectively remove a proton from the crowded, more substituted position. Therefore, Hofmann Products are an important consideration when analyzing reactions involving sterically demanding conditions.
Substituted Alkene
Substituted alkenes are a fundamental topic in organic chemistry, especially when discussing elimination reactions. An alkene is a hydrocarbon with at least one carbon-carbon double bond, and substitution in this context refers to how many alkyl groups (carbon-containing groups) are attached to the carbons involved in the double bond.

The degree of substitution affects:
  • The stability of the alkene; more substituted alkenes are generally more stable.
  • The potential reactivity and the type of reactions the alkene can undergo.
  • The outcome of an elimination reaction, as predicted by Saytzeff's and Hofmann's rules.
In a more substituted alkene, there can be greater electron donation from the alkyl groups to the double bond, enhancing the stability and sometimes the overall reactivity of the molecule. As a result, understanding substituted alkenes helps predict the major and minor products in chemical reactions and facilitates a deeper comprehension of reaction mechanisms.

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Most popular questions from this chapter

Identify the final product (C) in the following sequence of reactions. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{I} \stackrel{\text { Alc. } \mathrm{KOH}, \Delta}{\longrightarrow}(\mathrm{A}) \stackrel{\mathrm{Br}_{2}}{\longrightarrow}(\mathrm{B}) \stackrel{\mathrm{KCN}}{\longrightarrow}(\mathrm{C})\) (a) \(\mathrm{NCCH}_{2} \mathrm{CH}_{2} \mathrm{CN}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CN}\) (d) \(\mathrm{BrCH}_{2} \mathrm{CH}_{2} \mathrm{CN}\)

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