Chapter 26: Problem 1
C-X bond is strongest in (a) \(\mathrm{CH}_{3} \mathrm{Br}\) (b) \(\mathrm{CH}_{3} \mathrm{Cl}\) (c) \(\mathrm{CH}_{3} \mathrm{I}\) (d) \(\mathrm{CH}_{3} \mathrm{~F}\)
Short Answer
Expert verified
The C-X bond is strongest in \\( \mathrm{CH}_3 \mathrm{F} \\).
Step by step solution
01
Understanding Bond Strength
The bond strength in a molecule primarily depends on the bond length and the difference in electronegativities between the atoms forming the bond. Shorter bond lengths and larger differences in electronegativities typically result in stronger bonds.
02
Analyzing the C-X Bond
In the given options, we have C-X bonds where X is a halogen (Br, Cl, I, F). Bond strength generally decreases with increasing atomic size: as the atomic size of halogens increases, the bond length increases, making it weaker.
03
Examining Halogen Atomic Size
Among the halogens (F, Cl, Br, I), fluorine (F) is the smallest and iodine (I) is the largest. Shorter bonds (such as C-F) are stronger because the atoms are closer together, offering a stronger attraction.
04
Comparing Electronegativity
Fluorine is the most electronegative element, resulting in a highly polar and strong C-F bond due to the significant difference in electronegativity between C and F compared to other halogens.
05
Conclusion of Analysis
Considering both the bond length and the electronegativity difference, the C-F bond is the strongest among the options given. Thus, \( \mathrm{CH}_3 \mathrm{F} \) has the strongest C-X bond.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronegativity
Electronegativity is a measure of how strongly an atom attracts electrons in a bond.
This concept is crucial in determining bond strength.
When two atoms form a bond, the difference in their electronegativities affects the bond's characteristics.
Fluorine is the most electronegative element on the periodic table, surpassing other halogens like chlorine, bromine, and iodine. This means that when fluorine forms a bond with carbon, as in the case of a C-F bond, it pulls the shared electrons closer to itself more effectively than other halogens.
Fluorine is the most electronegative element on the periodic table, surpassing other halogens like chlorine, bromine, and iodine. This means that when fluorine forms a bond with carbon, as in the case of a C-F bond, it pulls the shared electrons closer to itself more effectively than other halogens.
- A larger electronegativity difference between two atoms leads to a more polar bond.
- A highly polar bond is generally stronger and more stable.
- The C-F bond is exceptionally strong due to the significant electronegativity difference between carbon and fluorine.
Atomic Size
Atomic size, or atomic radius, is the distance from the nucleus of an atom to its outermost electron cloud.
This factor significantly influences bond strength.
In general, as you move down a group in the periodic table, the atomic size increases due to the addition of electron shells.
For halogens, the order of increasing atomic size is: fluorine < chlorine < bromine < iodine.
For halogens, the order of increasing atomic size is: fluorine < chlorine < bromine < iodine.
- Fluorine, being the smallest halogen, allows for the closest approach to carbon, creating a short and strong bond.
- Bigger atoms like iodine result in longer bond lengths, which are generally weaker due to the decreased attraction between the bonded atoms.
C-X Bond Analysis
Examining the C-X bond, where X represents a halogen such as fluorine, chlorine, bromine, or iodine, involves analyzing both bond length and electronegativity.
Both factors are pivotal in determining bond strength.
In the case of C-F bonds, the combination of short bond length and substantial electronegativity difference makes them the strongest among C-X bonds. The C-F bond is the most robust due to fluorine's small atomic size and high electronegativity.
In the case of C-F bonds, the combination of short bond length and substantial electronegativity difference makes them the strongest among C-X bonds. The C-F bond is the most robust due to fluorine's small atomic size and high electronegativity.
- Shorter bond lengths result in stronger bonds, as seen with C-F compared to other C-X bonds.
- The significant electronegativity difference enhances the bond polarity and strength.
- Analyzing both the atomic size and electronegativity offers a more comprehensive understanding of bond behavior.