Chapter 24: Problem 72
The most stable free radical among the following is (1) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2}\) (2) \(\mathrm{CH}_{3}-\dot{\mathrm{CH}}-\mathrm{CH}_{3}\) (3) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHCH}_{3}\) (4) \(\mathrm{CH}_{3} \mathrm{CH}_{2}\) (a) \(3>1>4>2\) (b) \(1>3>2>4\) (c) \(3>1>2>4\) (d) \(3>2>1>4\)
Short Answer
Step by step solution
Understand the Concept of Stability in Free Radicals
Analyze the Radical Structures
Compare Stability
Select the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Resonance Stabilization
When a molecule has resonance, it can distribute the unpaired electron across multiple atoms.
This delocalization reduces the energy of the radical, making it more stable.
- Phenyl rings: Considered excellent at providing resonance because they have cyclic structures which allow electron clouds to overlap.
- Benzyl and allylic radicals: They are often stabilized by resonance with such structures.
Hyperconjugation
Hyperconjugation involves the interaction of the radical's unpaired electron with adjacent sigma bonds.
- Available Hydrogens: More adjacent C-H bonds mean more interactions, hence higher stability.
- Alkyl groups: These groups with available C-H bonds provide a greater hyperconjugative effect.
Inductive Effects
These groups pull electron density towards themselves, helping stabilize the radical's charge distribution. However, for many free radicals, this effect is less pronounced compared to resonance and hyperconjugation.
- Electronegative Atoms: Atoms like fluorine or chlorine can stabilize a radical by pulling electrons towards them.
- Distance Matters: The effect weakens with increased distance from the radical center.
Benzyl Radical
It benefits greatly from resonance stabilization, which significantly improves its stability.
- Phenyl Ring Interaction: The unpaired electron can resonate through the electrons in the ring.
- Stability: A benzyl radical is more stable than many other free radicals due to this constant state of electron sharing.
Allylic Radical
Situated next to a double-bonded group, they allow the unpaired electron to be delocalized across adjacent pi bonds.
- Adjacent Pi Bonds: Provide an opportunity for the radical to stabilize through resonance.
- Phenyl Group Strength: When also adjacent to phenyl groups, like in some radicals analyzed, it provides even more resonance structures.