Chapter 24: Problem 54
The reaction intermediate in \(\mathrm{E}_{1 C b}\) is (a) Carbonium ion (b) carbon free radical (c) Carbanion (d) Carbene
Short Answer
Expert verified
The reaction intermediate in E1cb is (c) Carbanion.
Step by step solution
01
Understanding E1cb Mechanism
An \( ext{E}_{1cb}\) mechanism is a type of elimination reaction where the intermediate formed is particularly important in determining the nature of the bond-breaking and bond-making process. Let's understand what intermediates commonly form in such a mechanism.
02
Defining the Intermediates
In an \( ext{E}_{1cb}\) reaction, the leaving group departs before the \(eta\)-hydrogen. This mechanism involves a two-step process where a carbanion is formed as an intermediate which is stabilized through resonance or inductive effects.
03
Role of Carbanion
The carbanion, typically more stable than other potential intermediates like carbocations or free radicals in this context, acts as a key intermediate. It is negatively charged due to the excess lone pair of electrons, resulting from proton abstraction.
04
Confirming the Intermediate
Given the role of a carbanion in facilitating bond formation during the \( ext{E}_{1cb}\) reaction as an intermediate before forming the final double bond, it is essential in this type of reaction.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Reaction Intermediate
Reaction intermediates are transient species in a chemical reaction which are formed during the conversion of reactants into products. These intermediates are crucial because they directly influence the mechanism and rate of a reaction.
The unique trait of a reaction intermediate is its ephemeral nature; it exists only long enough to become a stepping stone to the next phase of the reaction.
In the context of the E1cb mechanism, the reaction intermediate is vital. This mechanism is characterized by a two-step process:
- First, a base abstracts a proton, creating a carbanion.
- Then, the leaving group departs.
The Dynamics of a Carbanion
A carbanion is a negatively charged species that arises when a carbon atom holds a pair of unshared electrons. In an E1cb reaction, it assumes the role of the crucial intermediate.
The formation of a carbanion is initiated by the removal of a proton (a hydrogen ion), which leaves behind a pair of electrons. These additional electrons on the carbon atom result in the negative charge.
Carbanions are often stabilized by two effects:
- Resonance: The delocalization of the negative charge over multiple atoms, which can disperse the charge and stabilize the carbanion.
- Inductive Effect: Electronegative atoms or groups near the carbanion can further stabilize it by pulling some of the electron density away, reducing the net charge.
A Closer Look at Elimination Reaction
Elimination reactions are a vital class of reactions in organic chemistry where one molecule splits into two molecules. A common characteristic is the removal of elements from a saturated molecule to form an unsaturated one, typically resulting in the formation of a carbon-carbon double bond.
In particular, the E1cb elimination reaction stands out due to its unique two-step mechanism. Here’s how it works:
- The first step involves deprotonation, where a proton is removed by a base, generating a carbanion.
- The second step involves the expulsion of a leaving group to form the final double bond structure.