Chapter 21: Problem 37
The reaction \({ }_{5} \mathrm{~B}^{8} \longrightarrow \mathrm{Be}^{8}+{ }_{1} \mathrm{e}^{0}\) takes place due to (a) \(\alpha\) decay (b) \(\beta\) decay (c) positron decay (d) electron capture
Short Answer
Expert verified
The reaction is positron decay (option c).
Step by step solution
01
Analyze the Reaction Equation
The given nuclear reaction is \( {}_5 \text{B}^8 \rightarrow {}_4 \text{Be}^8 + {}_{+1} \text{e}^0 \). This shows that Boron-8 is transforming into Beryllium-8 with the emission of an electron with a positive charge.
02
Identify the Decay Process
The emission of an electron with a positive charge in the reaction is indicative of positron emission, commonly known as positron decay. In this process, a proton in the nucleus is converted into a neutron, releasing a positron.
03
Compare Options
Compare the characteristics of different decay types: \( \alpha \)-decay involves emission of helium nuclei, \( \beta \)-decay involves emission of electrons, positron decay involves emission of positrons, and electron capture involves the nucleus absorbing an electron. The given reaction matches positron decay.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Positron Emission
Positron emission is a fascinating process in nuclear chemistry. It involves the transformation of a proton in the nucleus into a neutron, with the simultaneous emission of a positron. A positron is like an electron, but with a positive charge instead of a negative one. This contrasts with what happens in beta decay, where an electron is emitted. The phenomenon of positron emission is often termed as beta plus (β+) decay due to its similarity with beta decay, but with opposite charge characteristics. This process is crucial in medical imaging, particularly in techniques like Positron Emission Tomography (PET), which takes advantage of the properties of positrons to create images of the body.
Nuclear Decay Processes
Nuclear decay processes involve the transformation of an unstable nucleus into a more stable one. During these processes, the nucleus can emit particles or radiation. These decays include alpha decay, beta decay, gamma decay, and positron emission. Each type of decay process changes the nucleus in different ways:
- Alpha decay: Emission of helium nuclei (two protons and two neutrons), decreasing the atomic number by 2 and the mass number by 4.
- Beta decay: Emission of electrons which transforms a neutron into a proton, increasing the atomic number by 1.
- Positron emission: A proton transforms into a neutron with the emission of a positron, decreasing the atomic number by 1.
- Electron capture: The nucleus absorbs an electron, converting a proton into a neutron, also decreasing the atomic number by 1.
Nuclear Reactions
Nuclear reactions involve changes in an atom's nucleus and can result in the alteration of one element into another. They are initiated when nuclear components like protons and neutrons are added, emitted, or re-arrange within the nucleus. Different from chemical reactions, nuclear reactions can happen by different modes, such as fission, fusion, and various types of decay, including positron emission.
Nuclear reactions are best known for their critical role in producing energy, both for destructive purposes in nuclear weapons and constructive purposes in nuclear power generation. The energy released in a nuclear reaction is vast compared to chemical reactions, due to changes in the nucleus which are governed by the principle of mass-energy equivalence, famously described by Einstein's equation, \( E=mc^2 \).
Nuclear reactions are best known for their critical role in producing energy, both for destructive purposes in nuclear weapons and constructive purposes in nuclear power generation. The energy released in a nuclear reaction is vast compared to chemical reactions, due to changes in the nucleus which are governed by the principle of mass-energy equivalence, famously described by Einstein's equation, \( E=mc^2 \).
Boron-8 Decay
Boron-8 decay is an interesting example of positron emission. In the given reaction, the isotope Boron-8 ( \( {}_5 ext{B}^8 \)) undergoes decay to form Beryllium-8 ( \( {}_4 ext{Be}^8 \)) and a positron ( \( {}_{+1} ext{e}^0 \)). This process illustrates positron emission, where one of the protons in the boron nucleus is transformed into a neutron, emitting a positron as a result.
The transformation from Boron-8 to Beryllium-8 does not change the mass number since the process involves converting a proton to a neutron, and thus the overall mass number of 8 is retained. However, the atomic number decreases from 5 to 4, as there are now fewer protons in the nucleus. This change appropriately reflects the new identity of the nucleus as Beryllium. Such transformations are significant in nuclear science because they demonstrate one of the many ways elements can transmute in nature.
The transformation from Boron-8 to Beryllium-8 does not change the mass number since the process involves converting a proton to a neutron, and thus the overall mass number of 8 is retained. However, the atomic number decreases from 5 to 4, as there are now fewer protons in the nucleus. This change appropriately reflects the new identity of the nucleus as Beryllium. Such transformations are significant in nuclear science because they demonstrate one of the many ways elements can transmute in nature.