Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

When excess of \(\mathrm{KCN}\) is added to aqueous solution of copper sulphate a co-ordination compound \(\mathrm{K}_{\mathrm{x}}\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]\) is formed. The value of \(\mathrm{x}\) is

Short Answer

Expert verified
The value of \(x\) is 3.

Step by step solution

01

Understand the Reaction

When excess \(\text{KCN}\) is added to \(\text{CuSO}_4\), complex ion \(\left[\text{Cu(CN)}_4\right]^{3-}\) is formed, paired with \(\text{K}^+\) ions. This means copper changes its state from \(\text{Cu}^{2+}\) in \(\text{CuSO}_4\) to \(\text{Cu}^+\) in the coordination compound. The cyanide ion \(\text{CN}^-\) acts as a ligand.
02

Determine the Charge of the Coordination Compound

Determine the charge of the complex ion \(\left[\text{Cu(CN)}_4\right]^{3-}\). Each \(\text{CN}^-\) ion contributes a \(-1\) charge, and since there are four \(\text{CN}^-\) ions, they contribute a total \(-4\) charge. Copper is in the \(+1\) oxidation state, so the total charge on \(\left[\text{Cu(CN)}_4\right]\) is \(-3\) (\(+1 + (-4) = -3\)).
03

Balance the Charges with Potassium Ions

Since the complex ion has a \(-3\) charge, three potassium ions \(\text{K}^+\) are needed to balance this negative charge. This means that the coordination compound formula should be \(\text{K}_3\left[\text{Cu(CN)}_4\right]\).
04

Identify the Value of \(x\)

In the formula \(\text{K}_x\left[\text{Cu(CN)}_4\right]\), \(x\) represents the number of \(\text{K}^+\) ions needed for charge balance. Since we calculated that 3 \(\text{K}^+\) ions are required, \(x = 3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Compounds
Coordination compounds are fascinating chemical entities formed by the combination of central metal atoms or ions with surrounding molecules or ions known as ligands. These ligands form coordinate covalent bonds with the metal center. In our example, copper from copper sulfate acts as the central metal, bonding with cyanide ligands to form a new coordination compound. Coordination compounds are essential in chemistry because they expand the range of possible chemical behaviors and interactions. They are found in various applications, such as catalysis, medicine, and materials science.
Oxidation States
Oxidation states, also known as oxidation numbers, help us understand the electron distribution in atoms during chemical reactions. In our coordination compound example, the copper in copper sulfate (\(\text{CuSO}_4\)) originally has an oxidation state of \(+2\). However, when it forms a complex with cyanide ions (\(\text{CN}^-\)), the oxidation state changes to \(+1\). This change results from the transfer of electrons between copper and the ligands. Understanding oxidation states is crucial for predicting the chemical behavior and reactions of compounds.
Ligands
Ligands are ions or molecules that bind to central metal atoms within coordination compounds. They play a crucial role in determining the structure and properties of the compound. In the example we are considering, cyanide ions \(\text{CN}^-\) serve as ligands, coordinating with a copper ion. Ligands are important because they affect the geometry and electronic properties of the metal center in the compound. There are many types of ligands, including monodentate (binding through a single atom) and polydentate (binding through multiple atoms) types. Their ability to donate electron pairs to the a metal is what characterizes them as ligands.
Charge Balance
Achieving charge balance is a key concept when studying coordination compounds. This ensures that compounds remain neutral overall. In our exercise, the complex ion \(\left[\text{Cu(CN)}_4\right]^{3-}\) carries a \(-3\) charge. To balance this negative charge, three potassium ions \(\text{K}^+\), having a positive charge each, are required. Thus, the formula for the complete coordination compound becomes \(\text{K}_3\left[\text{Cu(CN)}_4\right]\). Charge balance is fundamental to correctly writing chemical formulas for coordination compounds, as it helps to maintain neutrality and stability in the compound.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A solution containing \(2.675 \mathrm{~g}\) of \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) (molar mass \(=267.5 \mathrm{~g} \mathrm{~mol}^{-1}\) ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of \(\mathrm{AgNO}_{3}\) to give \(4.78 \mathrm{~g}\) of \(\mathrm{AgCl}\) (molar mass \(\left.=143.5 \mathrm{~g} \mathrm{~mol}^{-1}\right) .\) The formula of the complex is (Atomic mass of \(\mathrm{Ag}=108 \mathrm{u}\) ) [2010] (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) (b) \(\left[\mathrm{CoCl}_{2}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}\) (c) \(\left[\mathrm{CoCl}_{3}\left(\mathrm{NH}_{3}\right)_{3}\right]\) (d) \(\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{Cl}_{2}\)

Which of the following statement is incorrect? (a) in \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\), the ligand has satisfied both primary and secondary valencies of ferric ion (b) in \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) the ligand has satisfied only the secondary valency of ferric ion (c) in \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) the ligand has satisfied both primary and secondary valencies of ferrous ion (d) in \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\), the ligand has satisfied only the secondary valency of copper

Which of the following pairs represents linkage isomers? (a) \(\left[\mathrm{Pd}\left(\mathrm{P} \mathrm{Ph}_{3}\right)_{2}(\mathrm{NCS})_{2}\right]\) and \(\left[\mathrm{Pd}\left(\mathrm{P} \mathrm{Ph}_{3}\right)_{2}(\mathrm{SCN})_{2}\right]\) (b) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{3}\right] \mathrm{SO}_{4}\) and \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SO}_{4}\right] \mathrm{NO}_{3}\) (c) \(\left[\mathrm{Pt} \mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Br}_{2}\) and (d) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{Pt} \mathrm{Cl}_{4}\right]\) and \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{CuCl}_{4}\right]\)

When concentrated HCl is added to a solution of \(\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2^{+}}\)ion, an intense blue colour develops due to the formation of which one of the following? (a) \(\left[\mathrm{CoCl}_{4}\right]^{2}\) (b) \(\left[\mathrm{CoCl}_{6}\right]^{-}\) (c) \(\left[\mathrm{CoCl}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right]^{+}\) (d) \(\left[\mathrm{CoCl}_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]\)

In the complex \(\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]^{3-}\) the hybridization state, oxidation state and number of unpaired electrons are (a) \(\mathrm{dsp}^{2},+1,1\) (b) sp \(^{3},+1\), zero (c) \(\mathrm{sp}^{3},+2,1\) (d) \(\mathrm{dsp}^{2}\), \(+2\), zero

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free