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The possible number of co-ordination isomers of \(\mathrm{Pt}(\mathrm{Py})_{4} \mathrm{CuCl}_{4}\) are

Short Answer

Expert verified
There are two coordination isomers for the compound.

Step by step solution

01

Understanding Coordination Isomers

Coordination isomers are isomers where the composition of the complexes can interchange between the metal ions. For example, the ligands can exchange places between the cationic and anionic parts of the compound.
02

Initial Structure Analysis

We begin with the structure of \( \text{Pt(Py)}_4^{2+} \text{ and } \text{CuCl}_4^{2-} \). In this structure, \( \text{Platinum (Pt)} \) is coordinated with four pyridine (Py) ligands, and \( \text{Copper (Cu)} \) is coordinated with four chlorides (Cl).
03

Determining Possible Exchanges

Consider exchanges between \( \text{Pt} \) and \( \text{Cu} \). The possible exchanges involve either moving all ligands from \( \text{Pt} \) to \( \text{Cu} \), or first swapping part of the ligands and then all of them.
04

Calculation of Isomers

For coordination exchanges, the system can have the initial structure \( \text{Pt(Py)}_4\text{CuCl}_4 \), and the swapped form \( \text{Cu(Py)}_4\text{PtCl}_4 \). In total, there are 2 distinct coordination isomers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Chemistry
Coordination chemistry helps us understand how transition metals interact with ligands to form stable complexes. These complexes are crucial in various reactions and processes in the chemical world. When a metal ion bonds with surrounding molecules or ions, it forms these intricate structures.
In a coordination complex, the central metal atom or ion is surrounded by multiple molecules known as ligands.
  • Ligands can be anions, neutral molecules, or even cations.
  • The number of ligands attached to the central metal is referred to as the coordination number.
Coordination chemistry not only explains how these complexes form but also their properties, reactivity, and roles in chemical reactions.
By examining the arrangement of these ligands around the metal center, chemists can predict the reactivity and potential applications of these complexes. This branch of chemistry serves as a foundation for understanding various phenomena, including isomerism in coordination compounds.
Isomerism in Inorganic Chemistry
Isomerism is a fascinating area of study, especially in inorganic chemistry. It involves compounds with the same formula but different arrangements of atoms, leading to different properties and behaviors in a chemical context.
There are several types of isomerism, but in coordination compounds, we often encounter:
  • Coordination Isomerism: Where the composition of a complex can change between two metal ions. The ligands exchange places, as seen in the exercise, between the cationic and anionic components.
  • Geometric Isomerism: Isomers differ from each other by the spatial arrangement of their ligands.
Coordination isomers like those of \(\mathrm{Pt}(\mathrm{Py})_{4}\mathrm{CuCl}_{4}\) show how different metal-ligand arrangements lead to variations in their chemical behavior. Thus, understanding these isomers is essential for predicting the outcomes of chemical reactions and the interactions between molecules.
Transition Metal Complexes
Transition metal complexes are extended structures formed when transition metals bond with ligands. These complexes are integral to many biological processes and catalytic reactions due to their versatile and often unique properties.
Transition metals, such as platinum and copper in the exercise, possess several key characteristics:
  • They have partially filled d orbitals, allowing them to form multiple bonds with ligands.
  • The metals can exhibit various oxidation states, adding to the complexity and richness of possible interactions.
  • These metal-ligand bonds can result in colorful compounds, a feature exploited in industries for dyes and pigments.
In complexes, the metal center can significantly affect the electronic properties, influencing the reactivity and stability of the entire compound. Transition metal complexes play a pivotal role in technology and medicine, offering solutions to problems from energy production to drug design. Understanding how these complexes form and function unveils the broader picture of chemical interactions in nature and industrial applications.

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Most popular questions from this chapter

The correct order of magnetic moments (spin only values in B.M.) among the following is (Atomic number of \(\mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27\) ) (a) \(\left[\mathrm{MnCl}_{4}\right]^{2-}>\left[\mathrm{CoCl}_{4}\right]^{2-}>\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}\) (b) \(\left[\mathrm{MnCl}_{4}\right]^{2-}>\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}>\left[\mathrm{CoCl}_{4}\right]^{2-}\) (c) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}>\left[\mathrm{MnCl}_{4}\right]^{2->}\left[\mathrm{CoCl}_{4}\right]^{2-}\) (d) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}>\left[\mathrm{CoCl}_{4}\right]^{2-}>\left[\mathrm{MnCl}_{4}\right]^{2-}\)

Consider the following spatial arrangements of the octahedral complex ion \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{+} .\) Which of the following statements is incorrect regarding these structures? (a) 2 and 3 are cis and trans isomers respectively (b) 1 and 3 are enantiomers (c) 3 and 4 have identical structures (d) 2 and 4 are trans and cis isomers respectively

Each of the compounds \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}, \mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}\) \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{3}\) and \(\mathrm{K}_{2} \mathrm{PtCl}_{6}\) has been dissolved in wate: to make its \(0.001 \mathrm{M}\) solution. The order of thei increasing conductivity in solution is (a) \(\mathrm{K}_{2} \mathrm{PtCl}_{6}<\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}<\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}<\) \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{3}\) (b) \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}<\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{3}<\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}<\) \(\mathrm{K}_{2} \mathrm{PtCl}_{6}\) (c) \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{3}<\mathrm{K}_{2} \mathrm{PtCl}_{6}<\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}<\) \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}\) (d) \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{4}<\mathrm{K}_{2} \mathrm{PtCl}_{6}<\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{3}<\) \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}\)

In the silver plating of copper, \(\mathrm{K}\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]\) is used instead of \(\mathrm{AgNO}_{3}\). The reason is (a) less availability of \(\mathrm{Ag}^{+}\)ions, as Cu cannot displace Ag from \(\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]^{-}\)ion (b) more voltage is required (c) a thin layer of \(\mathrm{Ag}\) is formed on \(\mathrm{Cu}\) (d) \(\mathrm{Ag}^{+}\)ions are completely removed from solution

Which one of the following has largest number of isomers? (a) \(\left[\mathrm{Ru}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{+}\) (b) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]^{2+}\) (c) \(\left[\mathrm{Ir}\left(\mathrm{PR}_{3}\right)_{2} \mathrm{H}(\mathrm{CO})\right]^{2+}\) (d) \(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+}\) \([\mathrm{R}=\) alkyl group, en \(=\) ethylenediamine \(]\)

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