Chapter 20: Problem 102
The oxidation number of \(\mathrm{Fe}\) in \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4^{-}}, \mathrm{Cr}\) in \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\right]\) and \(\mathrm{Ni}\) in \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) are respectively (a) \(0,+3,+2\) (b) \(+3,+3,0\) (c) \(+3,0,+3\) (d) \(+2,+3,0\)
Short Answer
Step by step solution
Identify the charge of the complex
Determine the charge of ligands for each complex
Calculate oxidation state of Fe in \\([\mathrm{Fe}(\mathrm{CN})_{6}]^{4^{-}}\\)
Calculate oxidation state of Cr in \\([\mathrm{Cr}(\mathrm{NH}_{3})_{3}(\mathrm{NO}_{2})_{3}]\\)
Calculate oxidation state of Ni in \\([\mathrm{Ni}(\mathrm{CO})_{4}]\\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Transition Metal Complexes
The core of a transition metal complex is the central metal ion, which can exist in various oxidation states. This versatility makes these metals excellent at forming complex structures. By understanding the oxidation state of the metal, we gain insight into the type and number of electrons shared between the metal and the surrounding ligands, revealing crucial information about the chemical nature and reactivity of the complex.
In the exercise,
- the iron (Fe) in the complex \([ \mathrm{Fe} ( \mathrm{CN}) _{6} ] ^{4^{-}} \) is examined, along with chromium (Cr) in \([ \mathrm{Cr} ( \mathrm{NH}_3) _{3}( \mathrm{NO}_2) _{3} ] \) and nickel (Ni) in \([ \mathrm{Ni} ( \mathrm{CO}) _{4} ] \).
Ligand Charge
Ligands are classified based on their charge:
- charged ligands like CN− (cyanide) and NO2− (nitrito) carry a negative charge and tend to donate electron density to the metal, affecting its oxidation state.
- neutral ligands such as NH3 (ammonia) and CO (carbonyl) do not change the metal's oxidation state by charge. Instead, they donate electron pairs to the metal, influencing bonding geometry and properties.
- Fe in the complex \([ \mathrm{Fe} ( \mathrm{CN}) _{6} ] ^{4^{-}}\), involves cyanide ligands which are negatively charged.
- Cr in \([ \mathrm{Cr} ( \mathrm{NH}_3) _{3}( \mathrm{NO}_2) _{3} ]\), uses both neutral (ammonia) and negatively charged (nitrito) ligands.
- Ni in \([ \mathrm{Ni} ( \mathrm{CO}) _{4} ]\) features neutral carbonyl ligands, leaving the metal's oxidation state balanced at zero.
Coordination Chemistry
In coordination chemistry, understanding the concept of coordination number is integral. This number represents how many ligand bonds are formed around the central metal ion. It helps in predicting the geometry and electronic properties of the complex:
- The coordination number is often 4, 6, or higher, depending on the number of sites available for ligand attachment on the metal.
- For instance, in the complex \([ \mathrm{Fe} ( \mathrm{CN}) _{6} ] ^{4^{-}} \) the coordination number is 6 as there are six cyanide ligands surrounding the iron ion.