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In context with the transition elements, which of the following statement is incorrect? (a) In the highest oxidation states, the transition metal show basic character and cationic complex. (b) In the highest oxidation states of the first five transition element (Sc to \(\mathrm{Mn}\) ), all the \(4 \mathrm{~s}\) and \(3 \mathrm{~d}\) electrons are used for bonding. (c) Once the d \(^{5}\) configuration is exceeded, the tendency to involve all the \(3 \mathrm{~d}\) electrons in bonding decreases. (d) In addition to the normal oxidation states, the zero oxidation state is also shown by these elements in complex.

Short Answer

Expert verified
Statement (a) is incorrect.

Step by step solution

01

Understand the Options

Let's look at each of the statements to understand their meanings related to transition elements.
02

Analyze Statement (a)

Statement (a) claims that in the highest oxidation states, transition metals show basic character and form cationic complexes. Transition metals in high oxidation states often form compounds that are more acidic than basic, and they can form both cationic and anionic complexes.
03

Review Statement (b)

Statement (b) refers to the fact that for the first five transition elements, from Sc to Mn, in their highest oxidation states, all their 4s and 3d electrons are used for bonding. This is indeed true.
04

Consider Statement (c)

Statement (c) suggests that once a d^5 configuration is exceeded, the ability to use all 3d electrons in bonding decreases. This is accurate due to the exchange energy stabilization being maximized at d^5.
05

Examine Statement (d)

Statement (d) asserts that transition metals can exhibit a zero oxidation state in complexes. This is a valid statement as many transition metals can form complexes in a zero oxidation state.
06

Determine the Incorrect Statement

Based on the analysis, statement (a) is incorrect as it inaccurately describes the basic character in high oxidation states for transition metals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Transition elements can exhibit various oxidation states. This characteristic is due to their ability to lose different numbers of electrons from both the 4s and 3d subshells. Generally, oxidation states range from +1 to +7 for these elements.
The term "oxidation state" refers to the charge left on the atom after electrons are removed or added to it. For transition metals:
  • The 4s electrons are removed first, followed by the 3d electrons.
  • High oxidation states are typically found in compounds such as oxides and fluorides.
  • In high oxidation states, transition metals often display acidic characteristics, not basic, contrary to what some might think. This is because these metals form covalent bonds in which they share electrons.
Understanding oxidation states is key to predicting the chemical behavior of transition metals.
D-Electron Configuration
The electron configuration of transition elements is significant since it determines their chemical properties. Transition metals are defined by their partially filled d orbitals.
  • The electron configuration of these elements largely impacts their stability and reactivity.
  • For instance, a d electron configuration such as d5 is particularly stable due to half-filled orbital stability and exchange energy.
  • This configuration's stability is the reason why the reactivity decreases when transitioning to d6 and beyond, as forming very stable configurations becomes less feasible.
Thus, knowing their d-electron configuration helps in understanding their bonding and oxidation states.
Complex Formation
Transition metals are well-known for their ability to form a range of complex compounds. This is a notable feature of their chemistry. A complex is a structure consisting of a central metal atom bonded to surrounding molecules or anions known as ligands:
  • Transition metals can form complexes due to their small, highly charged ions and the availability of d orbitals.
  • These complexes can be cationic, anionic, or neutral, depending on the metal and the ligands.
  • Interestingly, metals in their zero oxidation state can still form stable complexes, showcasing the diversity of their chemistry.
The formation of complexes extends the utility of transition metals in catalysts, biological systems, and industrial applications.

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Most popular questions from this chapter

What is the current order of spin only magnetic moment (in B.M.) of \(\mathrm{Mn}^{2+}, \mathrm{Cr}^{2+}\) and \(\mathrm{V}^{2+}\) ? (a) \(\mathrm{Mn}^{2+}>\mathrm{V}^{2+}>\mathrm{Cr}^{2+}\) (b) \(\mathrm{V}^{2+}>\mathrm{Cr}^{2+}>\mathrm{Mn}^{2+}\) (c) \(\mathrm{Mn}^{2+}>\mathrm{Cr}^{2+}>\mathrm{V}^{2+}\) (d) \(\mathrm{Cr}^{2+}>\mathrm{V}^{2+}>\mathrm{Mn}^{2+}\)

Which of the following d-block elements do not posses characteristics properties of transition elements? (a) Cadmium (b) Manganese (c) Zinc (d) Copper

Which of the following statement is correct when a mixture of \(\mathrm{NaCl}\) and \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) is gently warmed with concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4} ?\) 1\. deep red coloured vapours are evolved 2\. the vapours when passed into \(\mathrm{NaOH}\) solution give a yellow solution of \(\mathrm{Na}_{2} \mathrm{CrO}_{4}\) 3\. chlorine gas is evolved 4\. chromyl chloride is formed (a) \(1,2,4\) (b) \(1,2,3\) (c) \(2,3,4\) (d) all are correct

The pair of the compounds in which both the metals are in the highest possible oxidation state is (a) \(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}, \mathrm{MnO}_{2}\) (b) \(\mathrm{CrO}_{2} \mathrm{Cl}_{2}, \mathrm{MnO}_{4}^{-}\) (c) \(\mathrm{TiO}_{3}, \mathrm{MnO}_{2}\) (d) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-},\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}\)

Which of the following factors may be regarded as the main cause of lanthanide contraction? (a) poor shielding of one of 4 f electrons by another in the subshell (b) effective shielding of one of \(4 \mathrm{f}\) electrons by another in the subshell (c) poor shielding of 5 d-electrons by 4 f electrons (d) greater shielding of 5 d-electrons by 4 f electrons

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