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Which of the following conditions is/are suitable for the stability of the complex? (a) Chelation (b) Larger basic nature of the ligand (c) Larger charge on the central metal ion. (d) Smaller charge on the central metal ion

Short Answer

Expert verified
Conditions (a), (b), and (c) are suitable for complex stability.

Step by step solution

01

Understanding Chelation

Chelation occurs when a ligand forms a stable complex with a central metal ion by creating a closed ring structure. This typically results in a more stable complex because the ring structure prevents easy dissociation, making it an important condition for stability.
02

Evaluating Basic Nature of Ligands

A ligand with a larger basic nature can donate electrons more effectively to the central metal ion, stabilizing the complex. More basic ligands form stronger coordinate bonds with the metal, enhancing stability.
03

Analyzing the Charge on the Central Metal Ion - Larger Charge

A larger charge on the central metal ion increases the electrostatic attraction between the metal and the ligands. This can strengthen the binding in the complex, leading to greater stability. Therefore, a higher charge generally contributes positively to the stability.
04

Analyzing the Charge on the Central Metal Ion - Smaller Charge

Conversely, a smaller charge on the central metal ion provides less electrostatic attraction, making the complex less stable. It does not support the formation of a stable complex as much as a larger charge does.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chelation
Chelation is a fascinating phenomenon in coordination chemistry. It occurs when a ligand forms one or more bonds with a metal ion. The key feature of chelation is the creation of a ring structure. This ring locks the ligand and metal ion together, making the overall complex less prone to breaking apart.
This ring structure typically results in increased stability. The reason for this is simple: when the ligand wraps around the metal ion to form a ring, it's harder for it to detach from the complex. It's similar to how a necklace is less likely to fall off if it's clasped securely. Chelates are especially effective when the ligand can form several bonds simultaneously, enhancing the rigidity and durability of the complex.
  • Increased stability through ring formation.
  • Reduced likelihood of dissociation.
  • Enhanced rigidity with multiple bonding sites.
Ligand Basicity
Ligand basicity refers to a ligand's ability to donate electron pairs to a central metal ion. The stronger the basicity of a ligand, the better it can donate electrons. This electron donation is crucial because it forms the coordinate bond that holds the metal-ligand complex together.
More basic ligands, capable of donating electrons efficiently, contribute to stronger coordinate bonds. As a result, the overall stability of the metal complex is improved. Essentially, when a ligand is more basic, it can cling tighter and form a more robust bond with the metal ion, enhancing the complex's integrity.
Here are a few key points about ligand basicity:
  • More basic ligands donate electrons more effectively.
  • Stronger coordinate bonds enhance complex stability.
  • Efficient electron donation is crucial for a stable complex.
Charge on Central Metal Ion
The charge on the central metal ion plays a pivotal role in complex stability. A higher charge on the metal ion increases electrostatic attraction between the metal and the ligands. This increased attraction strengthens the binding within the complex, making it more stable.
When the central metal ion has a larger positive charge, it exerts a stronger pull on the electrons from the ligands. This results in tighter binding and a more stable assembly. Conversely, if the metal ion has a smaller charge, the electrostatic pull weakens. This leads to less effective bonding, which could result in a less stable complex.
Key points to understand about metal ion charge:
  • Larger charges increase electrostatic attraction.
  • Stronger binding with larger charges leads to greater stability.
  • Smaller charges result in weaker bonds, reducing stability.

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Most popular questions from this chapter

Ammonia forms the complex ion \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) with copper ions in the alkaline solutions, but not in acidic solutions. What is the reason for it? (a) in acidic solutions, hydration protects copper ions (b) the acidic solutions, protons coordinate with ammonia molecules forming \(\mathrm{NH}_{4}^{+}\)ions and \(\mathrm{NH}_{3}\) molecules are not available (c) in alkaline solutions, insoluble \(\mathrm{Cu}(\mathrm{OH})_{2}\) is precipitated which is soluble in excess of any alkali (d) copper hydroxide is an amphoteric substance

The correct order of ionic radii of \(\mathrm{Y}^{3+}, \mathrm{La}^{3+}, \mathrm{Eu}^{3+}\) and \(\mathrm{Lu}^{3+}\) is (a) \(\mathrm{Lu}^{3+}<\mathrm{Eu}^{3+}<\mathrm{La}^{3+}<\mathrm{Y}^{3+}\) (b) \(\mathrm{La}^{3+}<\mathrm{Eu}^{3+}<\mathrm{Lu}^{3+}<\mathrm{Y}^{3+}\) (c) \(\mathrm{Y}^{3+}<\mathrm{La}^{3+}<\mathrm{Eu}^{3+}<\mathrm{Lu}^{3+}\) (d) \(\mathrm{Y}^{3+}<\mathrm{Lu}^{3+}<\mathrm{Eu}^{3+}<\mathrm{La}^{3+}\)

What is the general outer configuration of the coinage metals? (a) \(\mathrm{ns}^{2} \mathrm{np}^{6}\) (b) \((\mathrm{n}-1) \mathrm{d}^{9} \mathrm{~ns}^{2}\) (c) \((\mathrm{n}-1) \mathrm{d}^{10} \mathrm{~ns}^{1}\) (d) \((\mathrm{n}-1) \mathrm{d}^{10} \mathrm{~ns}^{2}\)

Which of the following atoms has the highest first Ionization energy? (a) \(\mathrm{Na}\) (b) \(\mathrm{K}\) (c) \(\mathrm{Sc}\) (d) \(\mathrm{Rb}\)

Cerium \((\mathrm{Z}=58)\) is an important member of the lanthanoids. Which of the following statements about cerium is incorrect? (a) the common oxidation states of cerium are \(+3\) and \(+4\) (b) the \(+3\) oxidation state of cerium is more stable than the \(+4\) oxidation state (c) the \(+4\) oxidation state of cerium is not known in solutions (d) cerium (IV) acts as an oxidizing agent

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