Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the process of extraction of gold Roasted gold ore \(+\mathrm{CN}^{-}+\mathrm{H}_{2} \mathrm{O} \stackrel{\mathrm{O}_{2}}{\longrightarrow}[\mathrm{X}]+\mathrm{OH}^{-}\) \([\mathrm{X}]+\mathrm{Zn} \longrightarrow[\mathrm{Y}]+\mathrm{Au}\) Identify the complexes of \([\mathrm{X}]\) and \([\mathrm{Y}]\) (a) \(\mathrm{Y}=\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-}\) (b) \(\mathrm{X}=\left[\mathrm{Au}(\mathrm{CN})_{4}\right]^{3-}\) (c) \(\mathrm{X}=\left[\mathrm{Au}(\mathrm{CN})_{2}\right]\) (d) \(\mathrm{Y}=\left[\mathrm{Zn}(\mathrm{CN})_{6}\right]^{4-}\)

Short Answer

Expert verified
\([X] = [\text{Au(CN)}_2]^-\) and \([Y] = [\text{Zn(CN)}_4]^{2-}\) from options (c) and (a).

Step by step solution

01

Understand the Reaction

In the gold extraction process, roasted gold ore reacts with cyanide ions and water in the presence of oxygen to form a complex denoted as \([X]\) and hydroxide ions. The complex \([X]\) then reacts with zinc to form another complex \([Y]\) and releases gold.
02

Identify products and reactants in the first reaction

The reaction \( \text{Roasted gold ore} + \text{CN}^- + \text{H}_2\text{O} \stackrel{\text{O}_2}{\longrightarrow} [X] + \text{OH}^- \) is typical for cyanidation, forming a complex with gold. Given the common product in such reactions is \([\text{Au(CN)}_2]^-\), the possible complexes are either \([\text{Au(CN)}_2]^-\) or \([\text{Au(CN)}_4]^{3-}\).
03

Match complex [X] with options

Option (c) provides \(X = [\text{Au(CN)}_2]^-\), which aligns with the standard process of gold cyanidation, thus identifying \([X] = [\text{Au(CN)}_2]^-\).
04

Examine the Second Reaction

The complex \([X]\) reacts with zinc to form \([Y]\) and gold. In practice, \( [Y] \) is typically a zinc cyanide complex like \([\text{Zn(CN)}_4]^{2-}\) or \([\text{Zn(CN)}_6]^{4-}\). By elimination and matching options, the common complex \([\text{Zn(CN)}_4]^{2-}\) aligns with (a), identifying \([Y] = [\text{Zn(CN)}_4]^{2-}\).
05

Confirm the Answer with Options

Based on our deductions: \([X] = [\text{Au(CN)}_2]^-\) matches with option (c), and \([Y] = [\text{Zn(CN)}_4]^{2-}\) corresponds to option (a). Thus, options (a) and (c) correctly identify the complexes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cyanidation process
The cyanidation process is a crucial technique employed in the extraction of gold from ore. This process involves the transformation of gold into a water-soluble coordination complex through a reaction with cyanide ions. The primary goal is to convert gold particles contained within the ore into a form that can be easily extracted and purified.

During the cyanidation process, gold reacts with cyanide ions (CN⁻) in an aqueous environment. The presence of oxygen is essential, as it facilitates the oxidation of gold metal to ionized form, creating the gold-cyanide complex. This allows the metal to dissolve in the solution and separate from unwanted impurities within the ore.
Gold-cyanide complex
The gold-cyanide complex is a key component in the gold extraction process, especially during cyanidation. It refers to the gold ion bonded with cyanide ions in the solution. The primary complex formed in this method is \( ext{Au(CN)}_2^-\), a stable compound that is integral in making the gold soluble.

Formation of this complex occurs when gold, in the presence of cyanide ions, reacts to form a coordination compound. This process is facilitated by the oxygen in the solution, which assists in oxidizing metallic gold to an ionic form. The resulting \([ ext{Au(CN)}_2]^-\) is easily separated from the mixture, enabling the extraction and recovery of gold from the solution through further processing.
Zinc cyanide complex
In the gold extraction process, after forming the gold-cyanide complex, zinc plays an essential role in recovering gold. The zinc cyanide complex is formed during the final stages of the cyanidation process. When zinc metal is added to the cyanide solution containing the gold complex, a chemical reaction takes place.

Zinc displaces the gold from the \([ ext{Au(CN)}_2]^-\) complex due to its higher reactivity, converting it into metallic gold. The leftover compound becomes a zinc cyanide compound, typically \([ ext{Zn(CN)}_4]^{2-}\). This allows gold to precipitate out of the solution and be collected for further refinement.
Oxidation-reduction reactions
Oxidation-reduction reactions, often known as redox reactions, are fundamental to the cyanidation process used for gold extraction. These reactions involve the transfer of electrons between substances, resulting in a change in oxidation state. In the cyanidation process, redox reactions are crucial at various stages.

Initially, oxygen aids the oxidation of gold metal by cyanide ions, transforming it into a soluble gold-cyanide complex \([ ext{Au(CN)}_2]^-\). Subsequently, another redox reaction happens when zinc is introduced to the solution. Zinc, being more reactive, donates electrons to reduce the gold complexes back to metallic gold, while zinc itself is oxidized, forming the zinc cyanide complex. These interactions are key in efficiently separating gold from the ore and recovering it from solution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Among the properties (A) reducing (B) oxidizing (C) complexing, the set of properties shown by \(\mathrm{CN}\) - ion towards metal species is [2004] (a) A, B (b) \(\mathrm{B}, \mathrm{C}\) (c) \(\mathrm{C}, \mathrm{A}\) (d) \(\mathrm{A}, \mathrm{B}, \mathrm{C}\)

Which of the following statement is correct with reference to the ferrous and ferric ions? 1\. \(\mathrm{Fe}^{3+}\) gives brown colour with potassium ferricyanide 2\. \(\mathrm{Fe}^{2+}\) gives blue precipitate with potassium ferricyanide 3\. \(\mathrm{Fe}^{3+}\) gives red colour with potassium thiocyanate 4\. \(\mathrm{Fe}^{2+}\) gives brown colour with ammonium thiocyanate. (a) 1,4 (b) 1,2 (c) 2,3 (d) all of these

With \(\mathrm{NH}_{4} \mathrm{OH}\), the silver nitrate is decomposed to give a brown precipitate of (a) \(\mathrm{Ag}_{2} \mathrm{O}\) (b) \(\mathrm{AgO}\) (c) \(\mathrm{Ag}(\mathrm{OH})_{2}\) (d) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\)

A colourless water soluble salt \(X\) on heating gives brown gas and leaves a metallic residue. Solution of \(X\) gives brick red precipitate with solution of \(\mathrm{K}_{2} \mathrm{CrO}_{4}\). An ammonical solution of \(X\) gives a silver mirror with formic acid. Salt \(X\) is used in making indelible election ink. Identify the salt \(X\) here? (a) \(\mathrm{AgCl}\) (b) \(\mathrm{HgNO}_{3}\) (c) \(\mathrm{AgNO}_{3}\) (d) \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\)

\(\mathrm{K} 1\) and \(\mathrm{CuSO}_{4}\) solution when mixed gives (a) \(\mathrm{K}_{2} \mathrm{SO}_{4}+\mathrm{Cu}_{2} \mathrm{I}_{2}+\mathrm{I}_{2}\) (b) \(\mathrm{Cu}_{2} \mathrm{I}_{2}+\mathrm{K}_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{CuI}_{2}+\mathrm{K}_{2} \mathrm{SO}_{4}\) (d) \(\mathrm{K}_{2} \mathrm{SO}_{4}+\mathrm{CuI}_{2}+\mathrm{I}_{2}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free