Chapter 16: Problem 123
A liquid \(\mathrm{A}\) is treated with \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) solution. A mixture of two salts \(\mathrm{B}\) and \(\mathrm{C}\) are produced in the solution. The mixture on acidification with sulphuric acid and distillation produces the liquid \(\mathrm{A}\) again. Identify A. (a) \(\mathrm{Cl}_{2}\) (b) \(\mathrm{O}_{2}\) (c) \(\mathrm{Br}_{2}\) (d) \(\mathrm{N}_{2}^{2}\)
Short Answer
Step by step solution
Understand the Reaction Scheme
Identify the Nature of Liquid A
Analyze the Regeneration Process
Eliminate Options
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reversible Reactions
In the exercise, the reaction between liquid A and sodium carbonate results in salts B and C. These salts, when treated with sulfuric acid, regenerate liquid A. This beautifully highlights the reversible nature of the chemical process. Reversible reactions often occur under closed conditions, allowing the system to achieve equilibrium where both reactants and products coexist.
- In a reversible reaction: reactants can form products and products can revert to reactants.
- Often involves physical changes like phase changes (solid to liquid and vice versa).
- Temperature and pressure can affect the direction of reversible reactions.
Halogen Chemistry
Halogen chemistry is central to the problem described in the exercise. Liquid A, identified as bromine (Br2), is a halogen. Halogens can easily form salts with metals. For instance, bromine reacts with sodium carbonate to form sodium bromide, showcasing typical halogen behavior.
- Halogens exist as diatomic molecules (e.g., Br2).
- They have varied states at room temperature: fluorine and chlorine are gases, bromine is a liquid, iodine, and astatine are solids.
- These elements can form compounds through simple electron gain, resulting in ions with a negative charge.
Inorganic Salts
In the context of the exercise, the formation of salts B and C from the reaction of liquid A with sodium carbonate illustrates the creation of inorganic salts. Here, bromine (Br2) reacts with sodium to yield sodium bromide, showcasing the classic formation of such salts.
- Inorganic salts are characterized by their strong ionic bonds.
- These compounds often have high melting and boiling points.
- They are soluble in water and can conduct electricity in the molten or dissolved state.
Acid-Base Reactions
In the given exercise, sulfuric acid (H2SO4) is used to treat salts B and C, leading to the reformation of liquid A, bromine. This process underscores the acid's role in liberating bromine from the sodium bromide salt. The interaction between hydrochloric acid and such salts is a classic example of acid-base neutralization reactions.
- Acids donate protons (H^+) to bases, which accept them.
- These reactions result in the formation of water and an ionic salt.
- The pH of the solution shifts depending on the strength and concentration of the acids and bases involved.