Chapter 15: Problem 42
The value of \(\ldots \ldots \ldots\) is less for \(\mathrm{D}_{2} \mathrm{O}\) compared to that of \(\mathrm{H}_{2} \mathrm{O}_{2}\) (a) boiling point (b) latent heat of vaporization (J \(\mathrm{g}^{-1}\) ) (c) density \(\left(\mathrm{g} / \mathrm{mL}^{-1}\right)\) at \(20^{\circ} \mathrm{C}\) (d) dielectric constant at \(20^{\circ} \mathrm{C}\)
Short Answer
Step by step solution
Understanding the Property
Boiling Point Comparison
Latent Heat of Vaporization Analysis
Density Comparison
Dielectric Constant Investigation
Conclusion on Property with Lesser Value
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Boiling Point
- Hydrogen peroxide (H_2O_2) boasts a higher boiling point than regular water (H_2O) and heavy water (D_2O), thanks to its stronger hydrogen bonds.
- These bonds require more energy (i.e., higher temperature) to break, which is why H_2O_2 has a higher boiling point.
- As a result, heavy water boils at a lower temperature compared to hydrogen peroxide.
Latent Heat of Vaporization
For D_2O, or heavy water, the larger, heavier molecules require even more energy to make this change. Imagine trying to blow up a heavier balloon. It takes a little more air, right? That’s because:
- Heavy water molecules, due to their mass, demand more energy input.
- Thus, D_2O has a larger latent heat of vaporization than H_2O_2.
Density
Heavy water, noted as D_2O, is literally heavier per given volume because:
- It contains deuterium, a heavier isotope of hydrogen.
- This makes D_2O denser than regular water (H_2O) and hydrogen peroxide.
This means that if you were to measure out equal volumes of D_2O and H_2O_2 at the same temperature, D_2O would weigh more.
Dielectric Constant
Hydrogen peroxide (H_2O_2) features a higher dielectric constant compared to heavy water (D_2O). Here’s why:
- The presence of an extra oxygen atom in H_2O_2 increases its molecular polarity.
- This molecular structure allows H_2O_2 to store more electrical energy.
So, if you're looking for a compound with a stronger ability to handle electric fields, H_2O_2 would be the go-to choice.