Chapter 15: Problem 10
Which of the following cannot be oxidized by \(\mathrm{H}_{2} \mathrm{O}_{2} ?\) (a) \(\mathrm{O}_{3}\) (b) \(\mathrm{PbS}\) (c) \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) (d) \(\mathrm{Kl}+\mathrm{HCl}\)
Short Answer
Expert verified
(a) \( \mathrm{O}_3 \) cannot be oxidized by \( \mathrm{H}_2\mathrm{O}_2 \).
Step by step solution
01
Analyze the Function of H2O2
Hydrogen peroxide, \( \mathrm{H}_2\mathrm{O}_2 \), acts as both an oxidizing and reducing agent, depending on the substances it interacts with. In this context, it is used as an oxidizing agent. We need to determine which compound cannot be oxidized by \( \mathrm{H}_2\mathrm{O}_2 \).
02
Evaluate the Oxidation Potential of Each Compound
To determine the answer, consider the oxidation states of the compounds: - \( \mathrm{O}_3 \) (ozone) is already in a high oxidation state (+2 for oxygen in \( \mathrm{O}_3 \)), making it less likely to be further oxidized.- \( \mathrm{PbS} \) can be oxidized to \( \mathrm{PbSO}_4 \).- \( \mathrm{Na}_2 \mathrm{SO}_3 \) can be oxidized to \( \mathrm{Na}_2 \mathrm{SO}_4 \).- \( \mathrm{Kl} + \mathrm{HCl} \) can react, and \( \mathrm{I}^- \) can be oxidized to \( \mathrm{I}_2 \).
03
Determine Which Cannot Be Oxidized
Compare the given options: - \( \mathrm{O}_3 \) is a strong oxidizer itself and unlikely to undergo oxidation by \( \mathrm{H}_2\mathrm{O}_2 \).- The other compounds, \( \mathrm{PbS}, \) \( \mathrm{Na}_2 \mathrm{SO}_3, \) and \( \mathrm{Kl} \), can each undergo oxidation because they are in forms that can be increased in oxidation state.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidizing and Reducing Agents
An oxidizing agent is a substance that causes another substance to lose electrons, thus being reduced itself in the process. A reducing agent, on the other hand, causes another substance to gain electrons and is oxidized in the process. In the realm of redox chemistry, recognizing these agents is vital for predicting the outcomes of chemical reactions.
- Oxidizing agents accept electrons from other substances. Consequently, they become reduced. Typical oxidizing agents include oxygen, chlorine, and hydrogen peroxide.
- Reducing agents donate electrons to other substances and become oxidized as a result. Examples include metals like zinc or sodium.
Oxidation States
Oxidation states, also known as oxidation numbers, are used to describe the degree of oxidation of an atom in a compound. These numbers vary based on the bonding between atoms and the type of elements involved. Identifying oxidation states is crucial in determining the direction of electron transfer in redox reactions.
- The oxidation state of a pure element is always zero. For instance, in molecules like \( \mathrm{O}_2 \) and \( \mathrm{N}_2 \), both elements have oxidation states of zero.
- In compound ions like \( \mathrm{H}_2\mathrm{O}_2 \), the sum of the oxidation states equals the charge of the molecule. Here, oxygen typically has an oxidation state of -2, but in \( \mathrm{H}_2\mathrm{O}_2 \), each oxygen has an oxidation state of -1.
Hydrogen Peroxide Reactions
Hydrogen peroxide (\( \mathrm{H}_2\mathrm{O}_2 \)) is a versatile chemical compound frequently used in various applications, from disinfection to chemical synthesis. Its ability to act as both an oxidizing and a reducing agent makes it unique in redox chemistry.
- As an oxidizing agent, \( \mathrm{H}_2\mathrm{O}_2 \) can convert sulfides (\( \mathrm{PbS} \)) into sulfates (\( \mathrm{PbSO}_4 \)), and sulfites (\( \mathrm{Na}_2 \mathrm{SO}_3 \)) into sulfates (\( \mathrm{Na}_2 \mathrm{SO}_4 \)).
- It can also react with iodides, causing the conversion of \( \mathrm{I}^- \) to \( \mathrm{I}_2 \). This demonstrates its strong oxidizing power in such reactions.