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The correct order of solubility of fluorides of alkaline earth metals is (a) \(\mathrm{BeF}_{2}>\mathrm{MgF}_{2}>\mathrm{CaF}_{2}>\mathrm{SrF}_{2}>\mathrm{BaF}_{2}\) (b) \(\mathrm{MgF}_{2}>\mathrm{BaF}_{2}>\mathrm{SrF}_{2}>\mathrm{CaF}_{2}>\mathrm{BeF}_{2}\) (c) \(\mathrm{BaF}_{2}>\mathrm{SrF}_{2}>\mathrm{CaF}_{2}>\mathrm{MgF}_{2}>\mathrm{BeF}_{2}\) (d) \(\mathrm{BeF}_{2}^{2}>\mathrm{Mg}^{2} \mathrm{~F}_{2}>\mathrm{SrF}_{2}^{2}>\mathrm{BaF}_{2}^{2}>\mathrm{CaF}_{2}^{2}\)

Short Answer

Expert verified
The correct order is (c): BaF₂ > SrF₂ > CaF₂ > MgF₂ > BeF₂.

Step by step solution

01

Understanding Solubility in Alkaline Earth Metals

The solubility of alkaline earth metal fluorides in water generally decreases as we move down the group from beryllium to barium. This is due to the decreasing lattice energy being offset by the relatively small decrease in hydration energy. Hence, the solubility order is influenced more by lattice energy than hydration energy as we move down the group.
02

Comparing Given Options

We compare each provided option to the general trend known for alkaline earth metal fluorides: (a) Shows solubility decreasing down the group. (b) Incorrect as it shows BeF₂ as least soluble, which is inaccurate. (c) Correctly indicates decreasing solubility from BaF₂ to BeF₂. (d) There are irregular terms like BeF₂² and SrF₂², which do not match the standard representation of these compounds.
03

Identify the Correct Option

By matching the general trend of solubility (decreasing from BaF₂ to BeF₂), the correct answer choice that follows this trend closely is (c), where it decreases in order of BaF₂ > SrF₂ > CaF₂ > MgF₂ > BeF₂.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lattice Energy
Lattice energy is a crucial concept in understanding why some metal fluorides dissolve more easily than others. It is the energy required to separate a mole of a solid ionic compound into gaseous ions. This energy relies heavily on the strength of the electrostatic force between the oppositely charged ions. These forces are stronger when the ions are closer together or when they carry higher charges. In the case of alkaline earth metal fluorides, which are mostly composed of +2 cations and -1 fluoride anions, lattice energy plays a pivotal role. As we move down Group 2 in the periodic table, from beryllium to barium, the size of the cations increases. This increase in size results in less electrostatic attraction between the cations and anions due to a greater distance between them, thus decreasing the lattice energy. Understanding this:
  • Higher lattice energy means the compound is harder to break apart, thus less soluble.
  • Lattice energy decreases as we move down the group from BeF₂ to BaF₂, making the compounds more soluble.
Hydration Energy
Hydration energy is another significant force determining solubility. Unlike lattice energy, hydration energy is the energy released when ions from a solid are dissolved and surrounded by water molecules. This energy helps to pull apart the solid ionic compound. What's important to remember?
  • Smaller ions with higher charges have a higher charge density, attracting water molecules more strongly.
  • As we move down the group, the size of the alkaline earth metal cations increases, resulting in a decrease in hydration energy.
  • This means that lower hydration energy makes fluoride compounds less soluble in water.
In the bigger picture, as you proceed down the group, both lattice and hydration energies decrease. However, with alkaline earth metal fluorides, the decrease in lattice energy is more significant. Thus, generally, lattice energy has a more substantial effect on solubility trends.
Group Trend in Periodic Table
The periodic table can tell us a lot about how elements and their compounds will behave, and this is particularly true for solubility trends of alkaline earth metal fluorides. Key observations in group trends:
  • Group 2 metals become larger as you move from top to bottom, from beryllium to barium.
  • The increase in ionic size generally decreases the charge density and thus affects both lattice and hydration energies.
  • Because the lattice energy more significantly decreases than hydration energy, solubility usually decreases down the group.
Thus, with these trends, the solubility order for alkaline earth fluorides is generally decreasing from BaF₂ to BeF₂. This reflects both the changes in lattice and hydration energies as well as the general periodical group trends.

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Most popular questions from this chapter

Following statements regarding the periodic trends of chemical reactivity of the alkali metals and the halogens are given. Which one of these statements gives the correct picture? [2006] (a) the reactivity decreases in the alkali metals but increases in the halogens with increase in atomic number down the group (b) in both the alkali metals and the halogens the chemical reactivity decreases with increase in atomic number down the group (c) chemical reactivity increases with increase in atomic number down the group in both the alkali metals and halogens (d) in alkali metals the reactivity increases but in the halogens it decreases with increase in atomic number down the group

Which one of the following arrangements do not truely represent the property indicated against it? (a) \(\mathrm{Br}_{2}<\mathrm{Cl}_{2}<\mathrm{F}_{2}-\) Electronegativity (b) \(\mathrm{Br}_{2}<\mathrm{Cl}_{2}<\mathrm{F}_{2}-\) Bond energy (c) \(\mathrm{Br}_{2}<\mathrm{Cl}_{2}^{2}<\mathrm{F}_{2}-\) Electron affinity (d) \(\mathrm{Br}_{2}<\mathrm{Cl}_{2}<\mathrm{F}_{2}^{2}-\) oxidizing power

The stability of the following alkali metal chlorides follows the order (a) \(\mathrm{CsCl}>\mathrm{KCl}>\mathrm{NaCl}>\mathrm{LiCl}\) (b) \(\mathrm{NaCl}>\mathrm{KCl}>\mathrm{LiCl}>\mathrm{CsCl}\) (c) \(\mathrm{KCl}>\mathrm{CsCl}>\mathrm{NaCl}>\mathrm{LiCl}\) (d) \(\mathrm{LiCl}>\mathrm{KCl}>\mathrm{NaCl}>\mathrm{CsCl}\)

The catenation tendency of \(\mathrm{C}, \mathrm{Si}\) and Ge is in the order \(\mathrm{Ge}<\mathrm{Si}<\mathrm{C}\). The bond energies (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) of \(\mathrm{C}-\mathrm{C}\), Si-Si and Ge-Ge bonds, respectively are (a) \(348,180,167\) (b) \(180,167,348\) (c) \(348,167,180\) (d) \(167,180,348\)

Noble gases do not react with other elements because (a) completely paired up electrons lead to stable electronic configuration (b) the size of their atoms is very small (c) they are found in abundance (d) they are monoatomic

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