Chapter 14: Problem 168
The decreasing values of bond angles from \(\mathrm{NH}_{3}\) \(\left(106^{\circ}\right)\) to \(\mathrm{SbH}_{3}\left(101^{\circ}\right)\) down group 15 of the periodic table is due to (a) increasing bp-bp repulsion (b) increasing p orbital character in sp \(^{3}\) (c) decreasing lp-bp repulsion (d) decreasing electronegativity
Short Answer
Step by step solution
Understanding Bond Angles in Group 15 Hydrides
Assessing Electronegativity Down Group 15
Examining Lone Pair-Bond Pair Repulsion
Analyzing Orbital Hybridization
Evaluating Options
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Key Concepts
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