Chapter 14: Problem 116
Regarding \(\mathrm{F}^{-}\)and \(\mathrm{Cl}^{-}\)which of the following statements is correct? 1\. Cl can give up an electron more easily than \(\mathrm{F}^{-}\) 2\. \(\mathrm{Cl}^{-}\)is a better reducing agent than \(\mathrm{F}^{-}\) 3\. \(\mathrm{Cl}^{-}\)is smaller in size than \(\mathrm{F}^{-}\) 4\. \(\mathrm{F}^{-}\)can be oxidized more readily than \(\mathrm{Cl}^{-}\) (a) 1,2 and 4 (b) 1 only (c) 1 and 2 (d) 3 and 4
Short Answer
Step by step solution
Analyze Oxidation Trends
Evaluate Reducing Agent Ability
Consider Atomic Size
Final Assessment of Statements
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation Trends
To determine which ion is more likely to undergo oxidation, we need to look at their electronegativity and size. Fluoride ions (\( \text{F}^- \)) are smaller and have a higher electronegativity compared to chloride ions (\( \text{Cl}^- \)). This means \( \text{F}^- \) holds its additional electron more tightly and is less likely to give it up. Hence, \( \text{Cl}^- \) is more prone to oxidation as it can lose its electron more easily than \( \text{F}^- \).
- \( \text{Oxidation:} \) Loss of electrons.
- \( \text{High electronegativity:} \) Provides stronger electron hold
- \( \text{\( \text{Cl}^- \) is more oxidizable than \( \text{F}^- \):} \) \( \text{Cl}^- \) is larger, holds its electron less tightly.
Reducing Agents
In comparing \( \text{F}^- \) and \( \text{Cl}^- \), the ability to act as reducing agents is determined by how readily they can give away electrons. Due to its larger size and weaker electron holding capacity, \( \text{Cl}^- \) acts as a better reducing agent than \( \text{F}^- \). The extra space in \( \text{Cl}^- \)'s electron cloud allows easier electron donation.
- \( \text{Reducing Agent:} \) Donates electrons.
- \( \text{\( \text{Cl}^- \) as a reducing agent:} \) Larger, with a weaker electron hold.
- \( \text{Electron donation capability:} \) Higher in \( \text{Cl}^- \) than \( \text{F}^- \).
Atomic Size
Within the periodic table, atomic size increases as you move down a group. This puts \( \text{Cl}^- \) at a larger size compared to \( \text{F}^- \) since chlorine is located below fluorine. The extra electron shells in \( \text{Cl}^- \) result in a larger overall ion size.
- \( \text{Atomic size increases down a group:} \) More electron shells added.
- \( \text{\( \text{Cl}^- \) is larger than \( \text{F}^-\):} \) Due to additional electron shell.
- \( \text{Size influences reactivity:} \) Larger ions often have more significant reaction tendencies in redox processes.
Periodic Trends
Elements in the same group of the periodic table show consistent trends in properties. For instance, as you progress down a group:
- \( \text{Atomic size increases:} \) Each element has an additional electron shell.
- \( \text{Electronegativity decreases:} \) Larger atoms have less electromagnetic pull on their electrons.
- \( \text{Ionization energy decreases:} \) Easier to remove electrons from larger atoms.
- \( \text{\( \text{F}^- \) is smaller and more electronegative than \( \text{Cl}^- \)} \)
- \( \text{\( \text{Cl}^- \) is larger, has lower ionization energy, thus is better at electron donation.} \)