Chapter 14: Problem 101
The correct order of acidic strength is (a) \(\mathrm{Cl}_{2} \mathrm{O}_{7}>\mathrm{SO}_{2}>\mathrm{P}_{4} \mathrm{O}_{10}\) (b) \(\mathrm{CO}_{2}>\mathrm{N}_{2} \mathrm{O}_{5}>\mathrm{SO}_{3}\) (c) \(\mathrm{Na}_{2} \mathrm{O}>\mathrm{MgO}>\mathrm{Al}_{2} \mathrm{O}_{3}\) (d) \(\mathrm{K}_{2} \mathrm{O}>\mathrm{CaO}>\mathrm{Mg} \mathrm{O}\)
Short Answer
Step by step solution
Understand Acidic Oxides
Analyze Option (a)
Analyze Option (b)
Analyze Option (c)
Analyze Option (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Acidic Oxides
- \(\mathrm{SO}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{H}_{2}\mathrm{SO}_{3}\) (sulfurous acid)
- \(\mathrm{Cl}_{2}\mathrm{O}_{7} + \mathrm{H}_{2}\mathrm{O} \rightarrow 2\mathrm{HClO}_{4}\) (perchloric acid)
Electronegativity
- Chlorine (Cl) is more electronegative than sulfur (S), which is evident in the acidic strength of their oxides (\(\mathrm{Cl}_{2}\mathrm{O}_{7}\) stronger than \(\mathrm{SO}_{2}\)).
- Electronegativity influences the polarity of bonds. More electronegative elements like chlorine form stronger acidic oxides due to their ability to attract electrons from oxygen.
Oxidation State
- In \(\mathrm{Cl}_{2}\mathrm{O}_{7}\), chlorine has an oxidation state of +7, which is higher than that in \(\mathrm{SO}_{2}\) where sulfur has an oxidation state of +4.
- This higher oxidation state helps elements attract oxygen atoms more effectively, leading to more acidic properties.
Non-metal Oxides
- Carbon dioxide (\(\mathrm{CO}_{2}\))
- Sulfur trioxide (\(\mathrm{SO}_{3}\))
- Nitrogen pentoxide (\(\mathrm{N}_{2}\mathrm{O}_{5}\))
- \(\mathrm{CO}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{H}_{2}\mathrm{CO}_{3}\) (carbonic acid)
- \(\mathrm{N}_{2}\mathrm{O}_{5} + \mathrm{H}_{2}\mathrm{O} \rightarrow 2\mathrm{HNO}_{3}\) (nitric acid)