Chapter 13: Problem 153
Which of the following species have bond order \(3 ?\) (a) \(\mathrm{CN}^{-}\) (b) \(\mathrm{O}_{2}^{-}\) (c) \(\mathrm{NO}^{+}\) (d) \(\mathrm{CO}\)
Short Answer
Expert verified
\( \mathrm{CN}^{-} \), \( \mathrm{NO}^{+} \), and \( \mathrm{CO} \).
Step by step solution
01
Understanding Bond Order
Bond order is defined as the difference between the number of bonding electrons and the number of antibonding electrons divided by two. The formula for bond order is given by \( \text{Bond Order} = \frac{\text{Number of Bonding Electrons} - \text{Number of Antibonding Electrons}}{2} \). A bond order of 3 indicates a triple bond.
02
Calculating Bond Order for \( \mathrm{CN}^{-} \)
The molecular orbital configuration of \( \mathrm{CN}^{-} \) is similar to that of \( \mathrm{CO} \), but we can also write the electron configuration as \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p)^4 \sigma(2p)^2 \). The bond order is \( \frac{10 - 4}{2} = 3 \).
03
Calculating Bond Order for \( \mathrm{O}_{2}^{-} \)
For \( \mathrm{O}_{2}^{-} \), the electron configuration would be \( \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x, 2p_y)^4 \pi^*(2p_x, 2p_y)^3 \). The bond order is \( \frac{9 - 4}{2} = 2.5 \).
04
Calculating Bond Order for \( \mathrm{NO}^{+} \)
The electron configuration for \( \mathrm{NO}^{+} \) can be viewed as similar to \( \mathrm{N}_{2} \), \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p_x, 2p_y)^4 \sigma(2p_z)^2 \). The bond order is \( \frac{10 - 4}{2} = 3 \).
05
Calculating Bond Order for \( \mathrm{CO} \)
The electron configuration for \( \mathrm{CO} \) is \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p_x, 2p_y)^4 \sigma(2p_z)^2 \). The bond order is \( \frac{10 - 4}{2} = 3 \).
06
Conclusion
Comparing the bond orders calculated, \( \mathrm{CN}^{-} \), \( \mathrm{NO}^{+} \), and \( \mathrm{CO} \) each have a bond order of 3, indicating they are triple bonded.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Orbital Theory
Molecular Orbital Theory (MOT) is an essential concept in understanding how atoms combine to form molecules. Instead of viewing electrons in individual atoms, MOT suggests that electrons are within molecular orbitals that extend over the entire molecule. These molecular orbitals are formed by the linear combination of atomic orbitals. There are two types of molecular orbitals:
- Bonding Orbitals: These are lower in energy than the atomic orbitals they come from and stabilize the molecule.
- Antibonding Orbitals: These are higher in energy and can destabilize the molecule if occupied by electrons.
Electron Configuration
Electron configuration refers to the distribution of electrons within an atomic or molecular orbital structure. Understanding electron configuration is crucial for determining the chemical properties and reactivity of molecules. For instance, when analyzing molecules such as \( \mathrm{CN}^{-} \), \( \mathrm{NO}^{+} \), and \( \mathrm{CO} \), different electron configurations explain their bond order. Electron configurations for these molecules are often expressed in terms of sigma (\( \sigma \)) and pi (\( \pi \)) orbitals:
- For \( \mathrm{CN}^{-} \), \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p)^4 \sigma(2p)^2 \), yielding a bond order of 3.
- For \( \mathrm{NO}^{+} \), \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p_x, 2p_y)^4 \sigma(2p_z)^2 \), also with a bond order of 3.
- For \( \mathrm{CO} \), \( \sigma(2s)^2 \sigma^*(2s)^2 \pi(2p_x, 2p_y)^4 \sigma(2p_z)^2 \), again with a bond order of 3.
Triple Bonds
Triple bonds are a type of chemical bond involving three shared pairs of electrons between two atoms, resulting in a bond order of 3. They are characterized by their strength and short length compared to single and double bonds. In the context of molecular orbital theory, a triple bond typically involves:
- One sigma \( (\sigma) \) bond - a head-on overlap of orbitals.
- Two pi \( (\pi) \) bonds - side-on overlaps of adjacent electron orbitals.