Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The rate constant of first-order reaction is \(10^{-2} \mathrm{~min}^{-1}\). The half-life period of reaction is (a) \(693 \mathrm{~min}\) (b) \(69.3 \mathrm{~min}\) (c) \(6.93 \mathrm{~min}\) (d) \(0.693 \mathrm{~min}\)

Short Answer

Expert verified
The half-life is 69.3 min, which is option (b).

Step by step solution

01

Understanding Half-Life Equation for First-Order Reactions

The formula to find the half-life \( t_{1/2} \) of a first-order reaction is \( t_{1/2} = \frac{0.693}{k} \), where \( k \) is the rate constant.
02

Substitute the Given Rate Constant

Given that the rate constant \( k = 10^{-2} \mathrm{~min}^{-1} \). Substitute \( k \) into the half-life equation: \( t_{1/2} = \frac{0.693}{10^{-2}} \).
03

Calculate the Half-Life Period

Perform the division: \( t_{1/2} = \frac{0.693}{0.01} = 69.3 \mathrm{~min} \).
04

Identify the Correct Answer from Options

Among the provided options, the half-life period we calculated, \( 69.3 \mathrm{~min} \), matches option (b).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
In first-order reactions, the rate constant, denoted as \( k \), is a crucial factor determining the speed at which a reaction proceeds. This constant is unique to each reaction and remains unchanged, provided the temperature remains constant. To put it simply, the rate constant is part of the mathematical relationship that describes how quickly reactants turn into products in a given reaction.

For a reaction with the rate constant \( k = 10^{-2} \mathrm{~min}^{-1} \), this value tells us that the reaction is relatively slow, as the numerical value is small. Typically, an increase in the numerical value of the rate constant indicates a faster reaction.
  • The units of the rate constant vary based on the order of reaction. For first-order reactions, the units are \( \mathrm{time}^{-1} \), such as \( \mathrm{min}^{-1} \).
  • First-order reactions depend only on the concentration of one reactant, which simplifies calculations.
  • The rate constant is integral when determining important reaction metrics, such as the half-life, as seen in our example.
Half-Life
The half-life of a reaction, denoted as \( t_{1/2} \), is the time it takes for half of the reactant to be consumed. For first-order reactions, there's a handy equation to calculate this:

\[ t_{1/2} = \frac{0.693}{k} \]
This relationship highlights that the half-life is inversely proportional to the rate constant \( k \). This means that a smaller rate constant results in a longer half-life, and similarly, a larger rate constant shortens the half-life.
  • The factor 0.693 arises from the natural logarithm of 2, which is a constant used in exponential decay processes.
  • One remarkable feature of first-order reactions is that the half-life remains constant throughout the reaction. This characteristics greatly simplifies planning and predicting when a reaction will reach a certain stage.
  • For our exercise, plugging in the rate constant into the half-life formula gives us \( t_{1/2} = 69.3 \mathrm{~min} \), a clear indication of the reaction's behavior over time.
Kinetics
Kinetics is the study of the speed or rate of a chemical reaction and the factors affecting it. In the context of first-order reactions, kinetics helps us examine reactions where the rate is directly proportional to the concentration of one reactant.

Understanding kinetics allows chemists to predict how changes in conditions, such as temperature or reactant concentration, can influence the speed of a reaction. This is particularly useful in industrial and laboratory settings, where maximizing efficiency and yield is crucial.
  • First-order kinetics implies that doubling the reactant concentration doubles the reaction rate, offering a straightforward relationship.
  • Kinetics can provide insights into the reaction mechanism, thereby helping researchers develop better catalysts or reaction conditions.
  • Kinetics is also vital in pharmacology, as it helps predict how drugs metabolize within the body by following first-order reaction patterns.
By diving into the kinetics of a reaction, we gain a deeper understanding of the dynamic processes driving chemical transformations, thus enabling controlled manipulation of reaction conditions to achieve desired outcomes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the initial concentration of reactant in certain reaction is doubled, the half life period of the reaction is also doubled. The order of reaction is (a) zero (b) first (c) second (d) \(1.5\)

Which of the following statements is correct? (1) order of a reaction can be known from experimental results and not from the stoichiometry of a reaction. (2) molecularity a reaction refers to (i) each of the elementary steps in (an overall mechanism of) a complex reaction or (ii) a single step reaction. (3) overall molecularity of a reaction may be determined in a manner similar to overall order of reaction. (4) overall order of a reaction \(\mathrm{A}^{\mathrm{m}}+\mathrm{B}^{\mathrm{n}} \longrightarrow \mathrm{AB}_{\mathrm{x}}\) is \(\mathrm{m}+\mathrm{n}\) Select the correct answer using the following codes: (a) 2 and 3 (b) 1,3 and 4 (c) 2,3 and 4 (d) 1,2 and 3

For the reaction \(\mathrm{a} \mathrm{A} \longrightarrow \mathrm{xP}\) when \([\mathrm{A}]=2.2 \mathrm{mM}\) the rate was found to be \(2.4 \mathrm{~m} \mathrm{M} \mathrm{s}^{-1}\) On reducing concentration of \(\mathrm{A}\) to half, the rate changes to \(0.6 \mathrm{~m} \mathrm{M} \mathrm{s}^{-1}\). The order of reaction with respect to \(\mathrm{A}\) is (a) \(1.5\) (b) \(2.0\) (c) \(2.5\) (d) \(3.0\)

For a chemical reaction which can never be a fractional number. (a) order (b) half-life (c) molecularity (d) rate constant

Identify the correct statements: (a) The order of an elementary reaction is equal to its molecularity (b) The order of a reaction can be zero (c) For second order reaction, order of reaction \(=2 \times\) molecularity. (d) The order of inversion of cane sugar is 2 .

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free