Chapter 10: Problem 69
The rate constant of first-order reaction is \(3 \times 10^{-6}\) per second. The initial concentration is \(0.10 \mathrm{M}\). The initial rate is (a) \(3 \times 10^{-7} \mathrm{Ms}^{-1}\) (b) \(3 \times 10^{-4} \mathrm{Ms}^{-1}\) (c) \(3 \times 10^{-5} \mathrm{Ms}^{-1}\) (d) \(3 \times 10^{-6} \mathrm{Ms}^{-1}\)
Short Answer
Step by step solution
Understand the Reaction Order and Formula
Identify Given Values
Substitute Values into the Rate Equation
Perform the Calculation
Match Your Answer with Given Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order reaction
- Rate = k × [A]
- k is the rate constant.
- [A] is the concentration of the reactant.
Rate constant
- s-1
Initial concentration
Reaction rate calculation
- Start with the equation: Rate = k × [A]
- Identify your values. In this case:
- k is the rate constant: 3 × 10-6 s-1
- [A] (initial concentration) is 0.10 M
- Substitute these values into the equation and calculate: Rate = (3 × 10-6 s-1) × (0.10 M)
- Do the math, and you get: Rate = 3 × 10-7 M s-1