Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A radioactive element A decays by the sequence and with half-lives, given below A \((\) half-life \(=30 \min ) \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{B}+\mathrm{a}\) \(\mathrm{B}\) (half-life \(=2\) days \() \stackrel{\mathrm{k}_{2}}{\longrightarrow} \mathrm{C}+2 \mathrm{~b}\) Which of the following statements is correct (a) \(\mathrm{B}\) and \(\mathrm{C}\) are isotopes (b) The mass number of \(\mathrm{B}\) is greater than \(\mathrm{A}\) (c) Atomic number of \(\mathrm{A}\) and \(\mathrm{C}\) are same (d) Disintegration constant \(\mathrm{k}_{2}>\mathrm{k}_{1}\)

Short Answer

Expert verified
The correct answer is (c) Atomic number of A and C are same.

Step by step solution

01

Determine the Decay Path

The decay path shows that element A decays into element B and releases an alpha particle (\( \alpha \) is a helium nucleus with 2 protons and 2 neutrons). Element B further decays into element C by releasing 2 beta particles (\( \beta \) are electrons or positrons which do not affect mass number but change atomic number).
02

Analyze the Decay of A to B

When A decays to B by emitting an alpha particle, the mass number of A decreases by 4 and its atomic number decreases by 2. Therefore, element B has a lower mass number and atomic number compared to element A.
03

Analyze the Decay of B to C

Element B decays into C by emitting two beta particles. Each beta emission increases the atomic number by 1 (since a neutron is converted to a proton). Therefore, the atomic number of C is 2 more than that of B, matching the original atomic number of A.
04

Evaluate Isotopes

Isotopes are atoms with the same atomic number but different mass numbers. Since B and C have different atomic numbers, they are not isotopes.
05

Compare Disintegration Constants

The disintegration constant \( k \) is inversely related to half-life: \( k = \frac{\ln(2)}{T_{1/2}} \). A has a half-life of 30 min, while B has a half-life of 2 days. Therefore, \( k_1 > k_2 \) because a smaller half-life indicates a larger decay constant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life
The concept of half-life is a fundamental part of radioactive decay. It represents the time it takes for half of a quantity of a radioactive substance to decay. This idea stems from the exponential nature of decay, where substances diminish by half over regular intervals of time.
For instance, if you start with 100 grams of a radioactive element that has a half-life of 1 hour, you'll have 50 grams after one hour. Another hour will pass, and you'll have 25 grams remaining.
In our exercise, element A has a half-life of 30 minutes, meaning A reduces to half its quantity in a 30-minute timeframe. Element B, on the other hand, takes 2 days to reach the halfway point in its decay process.
The shorter the half-life, the faster a radioactive element decays, which also affects its disintegration constant directly. Understanding half-life helps researchers track the transformation of elements into other forms.
Alpha Decay
Alpha decay is one type of radioactive decay, where an atomic nucleus releases an alpha particle. This particle, being the equivalent of a helium nucleus, has 2 protons and 2 neutrons. Such a release results in a reduction of the original nucleus's mass number by 4 and its atomic number by 2.
In the given problem, element A undergoes alpha decay into element B. When A emits an alpha particle, its composition changes significantly. Specifically, it loses 4 units in mass due to losing 2 protons and 2 neutrons. Consequently, its identity changes, because it now contains 2 fewer protons, resulting in a shift in its place on the periodic table.
This process makes alpha decay a significant manner through which unstable nuclei move toward stability in their atomic journeys.
Beta Decay
Beta decay is another common form of radioactive decay that involves the transformation of a neutron into a proton, or vice versa, with the ejection of a beta particle. In the form of electrons (or positrons), beta particles are released during this process, and this emission impacts the atomic number positively or negatively. However, the overall mass number remains unchanged.
When element B decays into element C, it emits two beta particles. Each emission converts a neutron to a proton, effectively increasing the atomic number by 1 with no effect on the mass number. So, the element shifts up by two places in the periodic table.
Beta decay plays a significant role in the chain of decay, enriching elements progressively by altering their atomic numbers without altering their weights. This process demonstrates the complexities of atomic stability and transmutation.
Disintegration Constant
The disintegration constant, often denoted as \( k \), is a measure of the decay rate of a radioactive substance. It numerically represents the probability per unit time that a nucleus will decay. The relationship between the disintegration constant and half-life is given by the equation:\[ k = \frac{\ln(2)}{T_{1/2}} \]Here, \( T_{1/2} \) is the half-life, and \( \ln(2) \) (approximately 0.693) is the natural logarithm of 2.
From this relationship, it's clear that as the half-life decreases, the disintegration constant increases, meaning the substance decays faster. In the exercise, the half-lives of elements A and B are compared, with A having a shorter half-life than B, indicating that its decay process is more rapid. Thus, \( k_1 \) (of A) is greater than \( k_2 \) (of B).
Understanding this constant helps in quantifying the stability and rate of decay of radioactive materials, enabling scientists and engineers to predict future behaviors in various applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free