Question

Question: Remember Mr. Rockness in Question 11? He now retrains college professors. It is a much more challenging task but still involves five steps. He has worked hard to balance the line; however, there are a lot of variabilities. Each stage in the process now handles between one and six faculty members per hour depending on how bad the case is. If there is some inventory available for every position (do not worry about the start-up), what is the expected output per hour? (Assume that each stage is independent and that it is equally likely that one, two, three, four, five, or six faculty members get processed each hour at each stage.)

Short answer

Answer

Themaximum level of the outcome that an organization can support to manufacture or offer any sort of service. The assembly line cannot produce 2,000 students per week.

Step-by-step solution

  Calculate the maximum output for each step

Formula, we used to calculate maximum output

Output = Available time/cycle time

Maximum output for description unpacks and place on the belt

Here, the time required per student is - 1.0

Faculty members work a 40-hour week

So, the output is

(40 hours/week *60 minutes/hour)/1.0 minutes/student = 2,400

Maximum output for description strip off bad habits

Here, the time required per student is - 1.5

Faculty members work a 40-hour week

So, the output is

(40 hours/week x 60 minutes/hour)/1.5 minutes/student = 1,600

Maximum output for description scrub and clean mind

Here, the time required per student is – 0.8

Faculty members work a 40-hour week

So, the output is

(40 hours/week x 60 minutes/hour)/0.8 minutes/student = 3,000

Maximum output for description insert modern methods

Here, the time required per student is – 1.0

Faculty members work a 40-hour week

So, the output is

(40 hours/week x 60 minutes/hour)/1.0 minutes/student = 2,400

Maximum output for description insert modern methods

Here, the time required per student is – 1.2

Faculty members work a 40-hour week

So, the output is

(40 hours/week x 60 minutes/hour)/1.2 minutes/student = 2,000.

Longest process on the assembly line

The longest process on this “assembly line” will govern the output. Therefore, the maximum output from this line will be:

Output = available time/cycle time

= (40 hours per week) x (60 minutes per hour)/1.5 minutes per student =1,600 students per week.

Therefore, this line cannot produce 2,000 students per week.