Question

Calculating income and cost per service for a service company

Buddy Grooming provides grooming services for pets. In April, the company earned \(16,300 in revenues and incurred the following operating costs to groom 660 dogs:

Wages Expense \) 4,061

Grooming Supplies Expense 1,675

Building Rent Expense 900

Utilities Expense 305

Depreciation Expense—Equipment 55

Requirements 2. What is the cost of service to groom one dog?

Short answer

The cost of service to groom one dog will be $10.6.

Step-by-step solution

Step-by-Step SolutionStep 1: Definition of Wages Expense

The wages expense is defined as the expense incurred by the business on paying the employees of the company.

Computation of Cost of service to groom one dog

$$\begin{gathered} \mathbf{Cost}\mathbf{}\mathbf{of}\mathbf{}\mathbf{Service}\mathbf{}\mathbf{to}\mathbf{}\mathbf{groom}\mathbf{}\mathbf{one}\mathbf{}\mathbf{dog}\mathbf{=}\frac{\mathrm{Total}\mathrm{Expense}}{\mathrm{Number}\mathrm{of}\mathrm{services}\mathrm{provided}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\$6,996}{660} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{\$}\mathbf{10}\mathbf{.}\mathbf{6} \end{gathered}$$