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Suppose we have conducted a \(t\) test, with \(\alpha=0.05\), and the \(P\) -value is \(0.03 .\) For each of the following statements, say whether the statement is true or false and explain why. (a) We reject \(H_{0}\) with \(\alpha=0.05\). (b) We have significant evidence for \(H_{A}\) with \(\alpha=0.05\). (c) We would reject \(H_{0}\) if \(\alpha\) were \(0.10 .\) (d) We do not have significant evidence for \(H_{A}\) with \(\alpha=0.10\). (e) If \(H_{0}\) is true, the probability of getting a test statistic at least as extreme as the value of the \(t_{s}\) that was actually obtained is \(3 \%\). (f) There is a \(3 \%\) probability that \(H_{0}\) is true.

Short Answer

Expert verified
True for statements (a), (b), (c), and (e), and false for statements (d) and (f).

Step by step solution

01

Understanding the concept of P-value and significance level

The P-value is the probability of obtaining test results at least as extreme as the observed results, under the assumption that the null hypothesis (H_{0}) is true. The significance level (alpha) is a threshold chosen by the researcher that determines when the null hypothesis should be rejected. If the P-value is less than alpha, we reject the null hypothesis.
02

Statement (a) evaluation

Since the P-value of 0.03 is less than the significance level of 0.05 (P < alpha), we reject the null hypothesis (H_{0}). Thus, the statement is true.
03

Statement (b) evaluation

Rejecting the null hypothesis (H_{0}) implies there is significant evidence in favor of the alternative hypothesis (H_{A}). Therefore, the statement is true, given that the P-value of 0.03 is less than alpha = 0.05.
04

Statement (c) evaluation

If we increase the significance level to alpha = 0.10, the P-value of 0.03 is still less than the new threshold. We would still reject the null hypothesis, making this statement true as well.
05

Statement (d) evaluation

Since we would reject the null hypothesis (H_{0}) for alpha = 0.10, as concluded in statement (c), this means we do have significant evidence for the alternative hypothesis (H_{A}). Therefore, the statement is false.
06

Statement (e) evaluation

This statement correctly describes the P-value. The P-value (0.03 or 3%) is indeed the probability of obtaining a test statistic as extreme as the observed, if the null hypothesis is true. Therefore, this statement is true.
07

Statement (f) evaluation

This statement is a common misconception about P-values. The P-value does not represent the probability that the null hypothesis is true. Instead, it measures the probability of observing the test statistic given the null hypothesis is true. Therefore, the statement is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Statistical significance plays a crucial role in hypothesis testing, indicating whether an observed effect is likely due to chance or not. It's a determination made by comparing the P-value to the significance level (alpha). When the P-value is lower than the preset alpha level, the results are said to be statistically significant.

This significance tells us that the findings are unlikely to have occurred if the null hypothesis were true. In our exercise's context, with a P-value of 0.03, which is less than alpha 0.05, the result is statistically significant, supporting the claim that the null hypothesis should be rejected in favor of the alternative hypothesis.
Null Hypothesis (H0)
The null hypothesis, denoted as H0, is a statement of 'no effect' or 'no difference.' It's the default assumption that there is no significant relationship or change due to the treatment or conditions tested in the study. In hypothesis testing, our goal is to determine whether the data provides enough evidence to reject H0 in favor of the alternative hypothesis, HA.

In the provided exercise, when we say that H0 is rejected, it means the evidence from our data suggests there is an effect or difference, and the observed results are statistically significant. The P-value assists in making this determination because it quantifies the probability of observing the results if H0 were true.
Alternative Hypothesis (HA)
The alternative hypothesis, represented as HA, is what a researcher seeks to support. It is a statement that proposes a statistical relationship, effect, or difference that contradicts the null hypothesis. When we reject H0 due to a low P-value, we lend support to HA, suggesting that the effect we are testing for is present.

In the context of the exercise, with a P-value of 0.03, we accept HA at the 0.05 alpha level, meaning that there is significant evidence of an effect or difference. However, it's important to note that while rejecting H0 supports HA, it does not 'prove' HA to be true; it simply implies the data are more consistent with HA than with H0.
Significance Level (alpha)
The significance level, denoted as alpha, is a critical threshold in hypothesis testing. It is a value set by the researcher before conducting the test, which determines the cutoff for rejecting the null hypothesis. Common alpha levels include 0.05, 0.01, and 0.10, representing a 5%, 1%, and 10% risk of rejecting a true null hypothesis, respectively.

In our exercise, an alpha of 0.05 means we have a 5% willing risk of a 'false positive' conclusion. However, if we adjust the alpha to 0.10, our willingness to accept error increases, making it easier to reject H0, as evidenced in statements (c) and (d). The chosen level of alpha influences the conservativeness of the test; lower alphas reduce the risk of falsely rejecting H0 but also make it harder to detect real differences.

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Most popular questions from this chapter

For an early study of the relationship between diet and heart disease, the investigator obtained data on heart disease mortality in various countries and on national average dietary compositions in the same countries. The accompanying graph shows, for six countries, the \(1948-1949\) death rate from degenerative heart disease (among men ages 55-59 years) plotted against the amount of fat in the diet. \({ }^{32}\) In what ways might this graph be misleading? Which extraneous variables might be relevant here? Discuss.

For each of the following situations, suppose \(H_{0}: \mu_{1}=\mu_{2}\) is being tested against \(H_{A}: \mu_{1}>\mu_{2} .\) State whether or not there is significant evidence for \(H_{A}\). (a) \(t_{s}=3.75\) with 19 degrees of freedom, \(\alpha=0.01\). (b) \(t_{s}=2.6\) with 5 degrees of freedom, \(\alpha=0.10\). (c) \(t_{s}=2.1\) with 7 degrees of freedom, \(\alpha=0.05\). (d) \(t_{\mathrm{c}}=1.8\) with 7 degrees of freedom, \(\alpha=0.05 .\)

Suppose a new drug is being considered for approval by the Food and Drug Administration. The null hypothesis is that the drug is not effective. If the FDA approves the drug, what type of error, Type I or Type II, could not possibly have been made?

An entomologist conducted an experiment to see if wounding a tomato plant would induce changes that improve its defense against insect attack. She grew larvae of the tobacco hornworm (Manduca sexta) on wounded plants or control plants. The accompanying table shows the weights (mg) of the larvae after 7 days of growth. \(^{41}\) (Assume that the data are normally distributed.) How strongly do the data support the researcher's expectation? Use a \(t\) test at the \(5 \%\) significance level. Let \(H_{A}\) be that wounding the plant tends to diminish larval growth. [Note: Formula (6.7.1) yields 31.8 df.] $$ \begin{array}{|lcc|} \hline & \text { Wounded } & \text { Control } \\ \hline n & 16 & 18 \\ \bar{y} & 28.66 & 37.96 \\ s & 9.02 & 11.14 \\ \hline \end{array} $$

A researcher performed a \(t\) test of the null hypothesis that two means are equal. He stated that he chose an alternative hypothesis of \(H_{A}: \mu_{1}>\mu_{2}\) because he observed \(\bar{y}_{1}>\bar{y}_{2}\). (a) Explain what is wrong with this procedure and why it is wrong. (b) Suppose he reported \(t=1.97\) on 25 degrees of freedom and a \(P\) -value of \(0.03 .\) What is the proper \(P\) -value? Why?

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