Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Example 6.6 .3 reports measurements of pain for children who have had their tonsils removed. Another variable measured in that experiment was the number of doses of Tylenol taken by the children in the two groups. Those data are $$\begin{array}{|lcc|}\hline & {\text { Type of surgery }} \\\\{ 2 - 3 } & \text { Conventional } & \text { Coblation } \\\\\hline n & 49 & 52 \\\\\bar{y} & 3.0 & 2.3 \\\\\text { SD } & 2.4 & 2.0 \\\\\hline\end{array}$$ Compute the standard error of \(\left(\bar{Y}_{1}-\bar{Y}_{2}\right)\).

Short Answer

Expert verified
The standard error of \(\bar{Y}_{1} - \bar{Y}_{2}\) is approximately 0.4410.

Step by step solution

01

Understand the problem

We need to calculate the standard error of the difference in means, denoted as \(SE(\bar{Y}_{1} - \bar{Y}_{2})\). For independent samples T-test, the standard error of the difference between two means can be computed using the formula: \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = \sqrt{\frac{SD_1^2}{n_1} + \frac{SD_2^2}{n_2}} \] where \(SD_1\) and \(SD_2\) are the standard deviations for each group, and \(n_1\) and \(n_2\) are the sample sizes.
02

Insert the values into the formula

Substitute the given values into the formula: \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = \sqrt{\frac{2.4^2}{49} + \frac{2.0^2}{52}} \]
03

Compute the standard error

Perform the calculations within the square root: \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = \sqrt{\frac{5.76}{49} + \frac{4.0}{52}} \] \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = \sqrt{0.11755 + 0.07692} \] \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = \sqrt{0.19447} \] \[ SE(\bar{Y}_{1} - \bar{Y}_{2}) = 0.4410 \] (Rounded to four decimal places)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Samples T-Test
An independent samples T-test, also known as a two-sample t-test, is a statistical procedure used to determine if there is a significant difference between the means of two independent groups. In the context of the exercise, it helps to compare the average number of Tylenol doses taken by children undergoing conventional surgery versus those undergoing coblation surgery.

To perform this test, several assumptions must be met, including that the samples are independent of each other, the data is normally distributed within each group, and the variances between groups are equal. When these assumptions are not met, other forms of analysis might be more appropriate. The formula to calculate the standard error of the difference between the means is crucial for determining the t-value in a T-test, which then helps assess whether the observed difference is statistically significant.
Difference in Means
The difference in means is a measure of the disparity between the average outcomes of two different groups. In the provided exercise, we are comparing the mean number of Tylenol doses for children post-tonsillectomy between conventional surgery and coblation. Calculating the difference in means alone doesn't indicate whether the observed difference is due to chance or represents a true difference between the groups.

This is where the T-test comes into play, using the standard error of the difference in means to help determine the likelihood that the two groups differ significantly from each other. Understanding the difference in means is important for researchers and practitioners in making informed decisions based on the data collected from their studies or experiments.
Standard Deviation
Standard deviation (SD) is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean (also called the expected value) of the set, while a high standard deviation indicates that the values are spread out over a wider range. In the textbook exercise, standard deviation plays a pivotal role as it reflects the variability of Tylenol doses taken by the children in each group.

When calculating the standard error of the difference in means, the standard deviations of each group are squared and divided by the respective sample sizes. The sum of these values is then square-rooted to obtain the standard error. This process highlights how the variability of each group affects the precision of the estimate of the difference in means.
Sample Size
Sample size refers to the number of observations or measurements taken from a population for the purposes of statistical analysis. In the context of calculating the standard error for an independent samples T-test, as seen in the exercise, the sample sizes of the two groups directly affect the magnitude of the standard error.

Larger sample sizes generally provide more accurate estimates of population parameters and, consequently, smaller standard errors, leading to more precise estimates of the difference in means. As the sample size increases, the confidence in the observed difference between the group means also increases, assuming all other factors are consistent. It is important for students to understand the impact of sample size not only on standard error but also on the overall validity of statistical tests, like the T-test.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An agronomist measured the heights of \(n\) corn plants. \({ }^{5}\) The mean height was \(220 \mathrm{~cm}\) and the standard deviation was \(15 \mathrm{~cm}\). Calculate the standard error of the mean if (a) \(n=25\) (b) \(n=100\)

Red blood cell counts \(\left(10^{-3} \mathrm{X}\right.\) cells per \(\mathrm{mm}^{3}\) ) of 15 lizards had an average of \(843.4 .\) The SD and the SE were, in random order, 64.9 and \(251.2 .\) Which is the \(S D,\) and which is the SE? How do you know?

Over a period of about 9 months, 1,353 women reported the timing of each of their menstrual cycles. For the first cycle reported by each woman, the mean cycle time was 28.86 days, and the standard deviation of the 1,353 times was 4.24 days. \(^{52}\) (a) Construct a \(99 \%\) confidence interval for the population mean cycle time. (b) Because environmental rhythms can influence biological rhythms, one might hypothesize that the population mean menstrual cycle time is 29.5 days, the length of the lunar month. Is the confidence interval of part (a) consistent with this hypothesis?

Is the nutrition information on commercially produced food accurate? In one study, researchers sampled 13 packages of a certain frozen reduced-calorie chicken entrée with a reported calorie content of 252 calories per package. The mean calorie count of the sampled entrées was 306 with a sample standard deviation of 51 calories. \(^{59}\) (a) Compute a \(90 \%\) confidence interval for the population mean calorie content of the frozen entrée. (b) Compute a \(99 \%\) confidence interval for the population mean calorie content of the frozen entrée. (c) Based on the two intervals computed in parts (a) and (b), what do you think about the reported calorie content for this entrée?

In a study of the effect of aluminum intake on the mental development of infants, a group of 92 infants who had been born prematurely were given a special aluminum-depleted intravenous-feeding solution. \({ }^{18}\) At age 18 months the neurologic development of the infants was measured using the Bayley Mental Development Index. (The Bayley Mental Development Index is similar to an IQ score, with 100 being the average in the general population.) A \(95 \%\) confidence interval for the mean is (93.8,102.1) (a) Interpret this interval. That is, what does the interval tell us about neurologic development in the population of prematurely born infants who receive intravenousfeeding solutions? (b) Does this interval indicate that the mean IQ of the sampled population is below the general population average of \(100 ?\)

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free