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Over a period of about 9 months, 1,353 women reported the timing of each of their menstrual cycles. For the first cycle reported by each woman, the mean cycle time was 28.86 days, and the standard deviation of the 1,353 times was 4.24 days. \(^{52}\) (a) Construct a \(99 \%\) confidence interval for the population mean cycle time. (b) Because environmental rhythms can influence biological rhythms, one might hypothesize that the population mean menstrual cycle time is 29.5 days, the length of the lunar month. Is the confidence interval of part (a) consistent with this hypothesis?

Short Answer

Expert verified
The 99% confidence interval for the population mean cycle time is approximately \(28.86 \pm (2.576 * \frac{4.24}{\sqrt{1353}}))\). Since this interval does not include the hypothesized mean of 29.5 days, it is not consistent with the hypothesis.

Step by step solution

01

Identify the Given Values

From the problem, we have the sample size (n) of 1,353 women, the sample mean (\(\bar{x}\)) of 28.86 days, and the sample standard deviation (s) of 4.24 days. Since we are dealing with a large sample size, we can use the z-distribution to construct the confidence interval.
02

Find the Z-score for the 99% Confidence Interval

To construct a 99% confidence interval, we need to find the z-score that corresponds to the middle 99% of the z-distribution. This value can be found in a z-table or by using statistical software. The z-score that captures the central 99% is approximately 2.576.
03

Calculate the Standard Error of the Mean

The standard error of the mean (SEM) is calculated using the formula SEM = s / \(\sqrt{n}\), where s is the sample standard deviation and n is the sample size.
04

Compute the Margin of Error

The margin of error (E) is found by multiplying the z-score for the desired confidence level by the standard error of the mean (SEM): E = z * SEM.
05

Construct the Confidence Interval

The 99% confidence interval for the population mean is given by the formula \(\bar{x} \pm E\). Use the sample mean (\(\bar{x}\)) and the margin of error (E) calculated in the previous steps to determine the lower and upper bounds of the interval.
06

Evaluate the Hypothesis

Compare the confidence interval obtained in Step 5 with the hypothesized population mean of 29.5 days to determine if the hypothesis falls within the confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean Estimation
When we talk about population mean estimation, we refer to the process of using sample data to predict the average of an entire population. This is particularly useful when it's impractical or impossible to measure every individual in a population. In our exercise, the population mean estimation is utilized to infer the average menstrual cycle duration for all women based on the sample of 1,353 women. To estimate the mean with a degree of confidence, we use a confidence interval, which gives us a range that is likely to contain the true population mean with a certain level of certainty, such as 99% in the given example.

Confidence intervals include the estimated population mean, and the width of the interval is affected by the variability in the data (standard deviation) and the size of the sample. A narrower interval suggests a more precise estimate. However, it's crucial to remember that no matter how narrow the interval might be, there is still a possibility, though small, that the true mean lies outside of it.
Standard Deviation
The measure of variability in a dataset is known as the standard deviation. It indicates how much, on average, each data point differs from the mean. In the context of our example, the standard deviation tells us about the variability in the menstrual cycle lengths among the 1,353 women studied. A high standard deviation would suggest that there is a wide variety of cycle lengths, whereas a lower standard deviation would imply that the cycle lengths are more consistent around the mean.

Understanding the standard deviation is essential for constructing confidence intervals and for hypothesis testing because it directly impacts the margin of error. The larger the standard deviation, the wider the confidence interval will be, reflecting less precision in our mean estimate.
Sample Size
The sample size is the number of observations in a sample. It plays a critical role in statistical analyses because larger sample sizes generally lead to more precise estimates of population parameters. In the exercise, a sample size of 1,353 is relatively large, allowing us to use certain statistical methods, like the z-distribution, with greater confidence.

The sample size impacts the calculation of the standard error of the mean, which is involved when constructing confidence intervals and conducting hypothesis testing. Larger samples tend to have smaller standard errors, which, in turn, produce narrower confidence intervals. This means our estimates of the population mean are more accurate. It's a basic principle that as the sample size increases, the confidence in our estimates also increases.
Z-Score Calculation
A z-score calculation is a statistical technique used to describe the position of a raw score in terms of its distance from the mean, measured in standard deviations. When constructing confidence intervals, the z-score helps to determine how far out from the mean a certain percentage of the data lies. In the 99% confidence interval from our exercise, the z-score of approximately 2.576 tells us that if we go out 2.576 standard deviations from the mean on both sides, we will capture the middle 99% of the distribution.

In simpler terms, the z-score is a 'multiplier' that adjusts for the level of confidence we want to have in our estimates. A higher confidence level, like 99%, requires a higher z-score, which also results in a wider confidence interval. It's the key value that defines the range around our sample mean where we expect the population mean to fall.
Standard Error of the Mean
The standard error of the mean (SEM) is a statistical term that measures the precision with which a sample mean estimates the population mean. Simply put, it tells us how accurate our sample is as a representation of the broader population. In the exercise, the SEM is obtained by dividing the standard deviation by the square root of the sample size.

SEM is an essential concept when creating confidence intervals as it is used to calculate the margin of error. When the SEM is small, it signifies that there is less variability between the sample mean and the true population mean, which typically occurs with larger samples. This smaller error translates into a tighter confidence interval, suggesting that the sample mean is a good estimation of the population mean with a smaller range for potential error.
Hypothesis Testing
Hypothesis testing is a method used in statistics to evaluate the plausibility of a hypothesis by using sample data. The procedure often involves proposing a null hypothesis, which is a statement of no effect or no difference, and then determining whether the observed data falls within a range that is considered normal if the null hypothesis were true.

In the context of our example, the hypothesis that the average menstrual cycle is equal to the lunar cycle (29.5 days) is tested against the confidence interval. If the hypothesized mean is within this interval, we do not have evidence to reject the null hypothesis, suggesting that our sampled data is consistent with the hypothesis. If it is outside the interval, we may consider it statistically unlikely that the true population mean is equal to the hypothesized value, and thus we might reject the null hypothesis. Hypothesis testing provides a systematic way to quantify the support for a hypothesis based on sample data.

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Most popular questions from this chapter

Data from two samples gave the following results: $$\begin{array}{|lcc|}\hline & \text { Sample 1 } & \text { Sample 2 } \\\\\hline n & 22 & 21 \\\\\bar{y} & 1.7 & 2.4 \\\\\text { SE } & 0.5 & 0.7 \\\\\hline \end{array}$$ Compute the standard error of \(\left(\bar{Y}_{1}-\bar{Y}_{2}\right)\).

Prothrombin time is a measure of the clotting ability of blood. For 10 rats treated with an antibiotic and 10 control rats, the prothrombin times (in seconds) were reported as follows \(^{43}\) : $$ \begin{array}{|lcc|} \hline & \text { Antibiotic } & \text { Control } \\ \hline n & 10 & 10 \\ \bar{y} & 25 & 23 \\ s & 10 & 8 \\ \hline \end{array} $$ (a) Construct a \(90 \%\) confidence interval for the difference in population means. (Assume that the two populations from which the data came are normally distributed.) [Note: Formula (6.7.1) yields 17.2 degrees of freedom for these data.] (b) Why is it important that we assume that the two populations are normally distributed in part (a)? (c) Interpret the confidence interval from part (a) in the context of this setting.

As part of a study of the development of the thymus gland, researchers weighed the glands of five chick embryos after 14 days of incubation. The thymus weights (mg) were as follows \(^{12}\) $$ \begin{array}{lllll} 29.6 & 21.5 & 28.0 & 34.6 & 44.9 \end{array} $$ For these data, the mean is 31.7 and the standard deviation is 8.7 (a) Calculate the standard error of the mean. (b) Construct a \(90 \%\) confidence interval for the population mean.

An experiment is being planned to compare the effects of several diets on the weight gain of beef cattle, measured over a 140 -day test period. \(^{20}\) In order to have enough precision to compare the diets, it is desired that the standard error of the mean for each diet should not exceed \(5 \mathrm{~kg}\). (a) If the population standard deviation of weight gain is guessed to be about \(20 \mathrm{~kg}\) on any of the diets, how many cattle should be put on each diet in order to achieve a sufficiently small standard error? (b) If the guess of the standard deviation is doubled, to \(40 \mathrm{~kg}\), does the required number of cattle double? Explain.

Data from two samples gave the following results: $$ \begin{array}{|lcc|}\hline & \text { Sample 1 } & \text { Sample 2 } \\\\\hline \bar{y} & 96.2 & 87.3 \\\\\mathrm{SE} & 3.7 & 4.6 \\\\\hline\end{array}$$ $$ \text { Compute the standard error of }\left(\bar{Y}_{1}-\bar{Y}_{2}\right) $$.

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